Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 281-290 of 600 questions.
If (f(x)=x+2) and (g(x)=x-2), what is ((f+g)(x)\cdot(f-g)(x))?
A. (8x)
((f+g)(x)=2x) और ((f-g)(x)=4), इसलिए गुणनफल (8x) है। संयुक्त अभिव्यक्ति को चरणों में हल करें। / ((f+g)(x)=2x) and ((f-g)(x)=4), so the product is (8x). Solve combined expressions step by step.
Login to save your score, XP, coins and progress.
If (f(x)=\frac{1}{x-2-4}) and (g(x)=x+2), what is the domain of ((fg)(x))?
A. \(\mathbb{R}-{-2,2}\)
(x-2-4=(x-2)(x+2)), इसलिए \(x\ne 2,-2\)। गुणा के बाद कटाव दिखे तो भी मूल डोमेन न भूलें। / (x-2-4=(x-2)(x+2)), so \(x\ne 2,-2\). Even if cancellation appears after multiplication, do not forget the original domain.
Login to save your score, XP, coins and progress.
If (f(x)=x-2+1) and (g(x)=2x), which expression equals ((f+g)(x))?
A. \(x^2+2x+1\)
((f+g)(x)=x-2+1+2x=x-2+2x+1)। पदों का क्रम बदलने से मान नहीं बदलता। / ((f+g)(x)=x-2+1+2x=x-2+2x+1). Changing the order of terms does not change the value.
Login to save your score, XP, coins and progress.
If (f(x)=x-2-4x+4) and (g(x)=x-2), what is (\left\(\frac{f}{g}\right\)(5)) for \(x\ne 2\)?
A. (3)
(\frac{(x-2)2}{x-2}=x-2), इसलिए (x=5) पर मान (3) है। पहले सरल करें, फिर मान रखें। / (\frac{(x-2)2}{x-2}=x-2), so at (x=5) the value is (3). Simplify first, then substitute.
Login to save your score, XP, coins and progress.
If (f(x)=3x-2) and (g(x)=x+4), what is ((fg)(1))?
A. (5)
(f(1)=1) और (g(1)=5), इसलिए ((fg)(1)=5)। गुणनफल फलन में मानों को गुणा करें। / (f(1)=1) and (g(1)=5), so ((fg)(1)=5). In a product function, multiply the values.
Login to save your score, XP, coins and progress.
If (f(x)=\frac{x+2}{x-3}) and (g(x)=x-3), what is the simplified form and domain of ((fg)(x))?
A. (x+2), \(x\ne 3\)
गुणन से (x+2) मिलता है, लेकिन (f(x)) के कारण \(x\ne 3\) रहेगा। मूल फलन की शर्तें हमेशा जांचें। / Multiplication gives (x+2), but \(x\ne 3\) remains because of (f(x)). Always check the original function conditions.
Login to save your score, XP, coins and progress.
If (f(x)=x-3) and (g(x)=x), how can ((f-g)(x)) be written?
A. (x(x-1)(x+1))
((f-g)(x)=x-3-x=x\(x^2-1\)=x(x-1)(x+1))। अंतर वर्ग पहचान का उपयोग करें। / ((f-g)(x)=x-3-x=x\(x^2-1\)=x(x-1)(x+1)). Use the difference of squares identity.
Login to save your score, XP, coins and progress.
If (f(x)=2x+5) and (g(x)=5-2x), what is ((f+g)(x))?
A. (10)
(2x) और (-2x) कट जाते हैं, इसलिए योग (10) है। विपरीत पदों को पहचानना समय बचाता है। / (2x) and (-2x) cancel, so the sum is (10). Identifying opposite terms saves time.
Login to save your score, XP, coins and progress.
If (f(x)=x-2+6x+9) and (g(x)=x+3), what is (\left\(\frac{f}{g}\right\)(0)), where \(x\ne -3\)?
A. (3)
(\frac{(x+3)2}{x+3}=x+3), इसलिए (x=0) पर मान (3) है। प्रतिबंध \(x\ne -3\) साथ रखें। / (\frac{(x+3)2}{x+3}=x+3), so at (x=0) the value is (3). Keep the restriction \(x\ne -3\).
Login to save your score, XP, coins and progress.
If (f(x)=\frac{1}{\sqrt{x-1}}) and (g(x)=x-2), what is the domain of ((f+g)(x))?
A. (\(1,\infty\))
हर में \(\sqrt{x-1}\) है, इसलिए (x-1>0) चाहिए। अतः डोमेन (\(1,\infty\)) है। / The denominator has \(\sqrt{x-1}\), so (x-1>0) is needed. Hence the domain is (\(1,\infty\)).
Login to save your score, XP, coins and progress.
Use Google login or mobile OTP. Admin can block users and control login providers.