यदि (f(x)=\frac{1}{\sqrt{x-1}}) और (g(x)=x-2) हों, तो ((f+g)(x)) का डोमेन क्या है?
If (f(x)=\frac{1}{\sqrt{x-1}}) and (g(x)=x-2), what is the domain of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. (\(1,\infty\))
Concept
The denominator has \(\sqrt{x-1}\), so (x-1>0) is needed. Hence the domain is (\(1,\infty\)).
Why this answer is correct
The correct answer is A. (\(1,\infty\)). The denominator has \(\sqrt{x-1}\), so (x-1>0) is needed. Hence the domain is (\(1,\infty\)).
Exam Tip
हर में \(\sqrt{x-1}\) है, इसलिए (x-1>0) चाहिए। अतः डोमेन (\(1,\infty\)) है।
Login to save your score, XP, coins and progress.