Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 341-350 of 591 questions.
If \(x\in\mathbb{R}\) and (6<2x+4), what is the solution?
A. (x>1)
(6<2x+4) से (2<2x) और (x>1) मिलता है। असमता बाईं ओर संख्या से शुरू हो तो भी क्रम ध्यान से रखें। / From (6<2x+4), we get (2<2x), hence (x>1). Even when the inequality starts with a number, keep the order carefully.
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What is the solution of \(\frac{3x-2}{2}<\frac{x+4}{3}\)?
A. (x<2)
(6) से गुणा करने पर (9x-6<2x+8) और (7x<14) मिलता है। धनात्मक हर हटाने पर चिन्ह नहीं बदलता। / Multiplying by (6) gives (9x-6<2x+8), so (7x<14). Removing positive denominators does not change the sign.
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Which value is a solution of \(-3\leq x<1\)?
A. (x=-3)
(-3) शामिल है क्योंकि \(\leq\) है और (1) शामिल नहीं है क्योंकि (<) है। खुले और बंद सिरों को अलग-अलग जांचें। / (-3) is included because of \(\leq\), while (1) is not included because of (<). Check open and closed endpoints separately.
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In which interval is the solution of \(10-5x\geq 0\)?
A. (\(-\infty,2]\)
\(10-5x\geq 0\) से \(-5x\geq -10\) और \(x\leq 2\) मिलता है। सीमा (2) शामिल है क्योंकि चिन्ह \(\geq\) था। / From \(10-5x\geq 0\), \(-5x\geq -10\), so \(x\leq 2\). The boundary (2) is included because the sign was \(\geq\).
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If \(x\in\mathbb{Z}\) and \(1\leq 2x-1<9\), what is the solution set?
A. ({1,2,3,4})
\(1\leq 2x-1<9\) से \(2\leq 2x<10\) और \(1\leq x<5\) मिलता है। पूर्णांक हल (1) से (4) तक हैं। / From \(1\leq 2x-1<9\), we get \(2\leq 2x<10\), hence \(1\leq x<5\). The integer solutions are (1) through (4).
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Which inequality has a number-line graph with a closed circle at (0) and shading to the right?
A. \(x\geq 0\)
बंद वृत्त (0) को शामिल करता है और दाईं ओर छाया (0) से बड़ी संख्याओं को दिखाती है। इसलिए \(x\geq 0\) सही है। / A closed circle includes (0), and right-side shading shows numbers greater than (0). Therefore \(x\geq 0\) is correct.
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If \(2x-3\leq 5\) and (x+1>0), what is the combined solution?
A. \(-1<x\leq 4\)
पहली असमता से \(x\leq 4\) और दूसरी से (x>-1) मिलता है। संयुक्त हल \(-1<x\leq 4\) है। / The first inequality gives \(x\leq 4\), and the second gives (x>-1). The combined solution is \(-1<x\leq 4\).
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Three times a number is not less than (18). Which inequality represents this statement?
A. \(3x\geq 18\)
कम नहीं है का अर्थ (18) से बड़ा या बराबर है। भाषा आधारित प्रश्नों में शब्दों को असमता चिन्ह से सही मिलाएं। / Not less than means greater than or equal to (18). In word problems, match phrases correctly with inequality signs.
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If \(x\in\mathbb{R}\) and (3-2x) is positive, what is the solution for (x)?
A. \(x<\frac{3}{2}\)
धनात्मक का अर्थ (3-2x>0) है। इससे (-2x>-3) और \(x<\frac{3}{2}\) मिलता है। / Positive means (3-2x>0). This gives (-2x>-3), hence \(x<\frac{3}{2}\).
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If (5x+2) is non-negative, which inequality for (x) is correct?
A. \(x\geq -\frac{2}{5}\)
ऋणात्मक नहीं है का अर्थ \(5x+2\geq 0\) है। इससे \(x\geq -\frac{2}{5}\) मिलता है। / Non-negative means \(5x+2\geq 0\). This gives \(x\geq -\frac{2}{5}\).
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