यदि \(2x-3\leq 5\) और (x+1>0) हैं तो संयुक्त हल कौन सा है?

If \(2x-3\leq 5\) and (x+1>0), what is the combined solution?

Explanation opens after your attempt
Correct Answer

A. \(-1<x\leq 4\)

Step 1

Concept

The first inequality gives \(x\leq 4\), and the second gives (x>-1). The combined solution is \(-1<x\leq 4\).

Step 2

Why this answer is correct

The correct answer is A. \(-1<x\leq 4\). The first inequality gives \(x\leq 4\), and the second gives (x>-1). The combined solution is \(-1<x\leq 4\).

Step 3

Exam Tip

पहली असमता से \(x\leq 4\) और दूसरी से (x>-1) मिलता है। संयुक्त हल \(-1<x\leq 4\) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(2x-3\leq 5\) और (x+1>0) हैं तो संयुक्त हल कौन सा है? / If \(2x-3\leq 5\) and (x+1>0), what is the combined solution?

Correct Answer: A. \(-1<x\leq 4\). Explanation: पहली असमता से \(x\leq 4\) और दूसरी से (x>-1) मिलता है। संयुक्त हल \(-1<x\leq 4\) है। / The first inequality gives \(x\leq 4\), and the second gives (x>-1). The combined solution is \(-1<x\leq 4\).

Which concept should I revise for this Mathematics MCQ?

The first inequality gives \(x\leq 4\), and the second gives (x>-1). The combined solution is \(-1<x\leq 4\).

What exam hint can help solve this Mathematics question?

पहली असमता से \(x\leq 4\) और दूसरी से (x>-1) मिलता है। संयुक्त हल \(-1<x\leq 4\) है।