यदि \(x\in\mathbb{R}\) और (3-2x) धनात्मक है तो (x) का हल कौन सा है?
If \(x\in\mathbb{R}\) and (3-2x) is positive, what is the solution for (x)?
Explanation opens after your attempt
Correct Answer
A. \(x<\frac{3}{2}\)
Concept
Positive means (3-2x>0). This gives (-2x>-3), hence \(x<\frac{3}{2}\).
Why this answer is correct
The correct answer is A. \(x<\frac{3}{2}\). Positive means (3-2x>0). This gives (-2x>-3), hence \(x<\frac{3}{2}\).
Exam Tip
धनात्मक का अर्थ (3-2x>0) है। इससे (-2x>-3) और \(x<\frac{3}{2}\) मिलता है।
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