Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 381-390 of 591 questions.
Which statement correctly means the interval ((2,7))?
B. (2<x<7)
खुले अंतराल ((2,7)) में दोनों सिरे शामिल नहीं होते। इसलिए (2<x<7) सही है। / In the open interval ((2,7)), both endpoints are excluded. Therefore (2<x<7) is correct.
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What is the solution of (3(2-x)>x+10)?
A. (x<-1)
(6-3x>x+10) से (-4x>4) और (x<-1) मिलता है। ऋणात्मक (-4) से भाग देने पर चिन्ह पलटें। / From (6-3x>x+10), we get (-4x>4), hence (x<-1). Reverse the sign when dividing by negative (-4).
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If \(x\in\mathbb{R}\) and \(x+4\geq 0\) and (2x-1<9), what is the combined solution?
A. ([-4,5))
पहली असमता से \(x\geq -4\) और दूसरी से (x<5) मिलता है। प्रतिच्छेद ([-4,5)) है। / The first inequality gives \(x\geq -4\), and the second gives (x<5). Their intersection is ([-4,5)).
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What is the solution of \(\frac{x-4}{-2}\geq 3\)?
B. \(x\leq -2\)
(-2) से गुणा करने पर चिन्ह पलटकर \(x-4\leq -6\) मिलता है। इसलिए \(x\leq -2\) है। / Multiplying by (-2) reverses the sign and gives \(x-4\leq -6\). Therefore \(x\leq -2\).
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If \(x\in\mathbb{Z}\) and \(-3\leq \frac{x}{2}<4\), what is the solution set?
A. ({-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7})
(2) से गुणा करने पर \(-6\leq x<8\) मिलता है। इसलिए पूर्णांक हल (-6) से (7) तक हैं। / Multiplying by (2) gives \(-6\leq x<8\). Therefore the integer solutions are from (-6) to (7).
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Which inequality has no real-number solution?
A. (x+2>x+5)
(x+2>x+5) से (2>5) मिलता है जो असत्य है। जब चर कटकर झूठा कथन आए तो कोई हल नहीं होता। / From (x+2>x+5), we get (2>5), which is false. If variables cancel and a false statement remains, there is no solution.
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Which inequality has all real numbers as its solution?
B. \(5x-4\leq 5x+2\)
\(5x-4\leq 5x+2\) से \(-4\leq 2\) मिलता है जो हमेशा सत्य है। सत्य स्थिर कथन आने पर सभी वास्तविक संख्याएं हल होती हैं। / From \(5x-4\leq 5x+2\), we get \(-4\leq 2\), which is always true. If a true constant statement remains, all real numbers are solutions.
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If (x) is a real number and \(-1<\frac{2x-3}{5}\leq 3\), what is the solution for (x)?
A. \(-1<x\leq 9\)
(5) से गुणा करने पर \(-5<2x-3\leq 15\) मिलता है। इससे \(-1<x\leq 9\) प्राप्त होता है। / Multiplying by (5) gives \(-5<2x-3\leq 15\). This gives \(-1<x\leq 9\).
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Which option is the correct interval form of \(x\leq -4\) or (x>1)?
A. ((-\infty,-4]\cup\(1,\infty\))
या में दोनों अलग भागों का संघ लिया जाता है। (-4) शामिल है और (1) शामिल नहीं है। / For or, take the union of the two separate parts. (-4) is included and (1) is not included.
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B. \(m\geq 40\)
कम नहीं होने चाहिए का अर्थ (40) या उससे अधिक है। इसलिए \(m\geq 40\) सही असमता है। / Must not be less than (40) means (40) or more. Therefore \(m\geq 40\) is the correct inequality.
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