यदि (x) एक वास्तविक संख्या है और \(-1<\frac{2x-3}{5}\leq 3\) है तो (x) का हल कौन सा है?

If (x) is a real number and \(-1<\frac{2x-3}{5}\leq 3\), what is the solution for (x)?

Explanation opens after your attempt
Correct Answer

A. \(-1<x\leq 9\)

Step 1

Concept

Multiplying by (5) gives \(-5<2x-3\leq 15\). This gives \(-1<x\leq 9\).

Step 2

Why this answer is correct

The correct answer is A. \(-1<x\leq 9\). Multiplying by (5) gives \(-5<2x-3\leq 15\). This gives \(-1<x\leq 9\).

Step 3

Exam Tip

(5) से गुणा करने पर \(-5<2x-3\leq 15\) मिलता है। इससे \(-1<x\leq 9\) प्राप्त होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि (x) एक वास्तविक संख्या है और \(-1<\frac{2x-3}{5}\leq 3\) है तो (x) का हल कौन सा है? / If (x) is a real number and \(-1<\frac{2x-3}{5}\leq 3\), what is the solution for (x)?

Correct Answer: A. \(-1<x\leq 9\). Explanation: (5) से गुणा करने पर \(-5<2x-3\leq 15\) मिलता है। इससे \(-1<x\leq 9\) प्राप्त होता है। / Multiplying by (5) gives \(-5<2x-3\leq 15\). This gives \(-1<x\leq 9\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by (5) gives \(-5<2x-3\leq 15\). This gives \(-1<x\leq 9\).

What exam hint can help solve this Mathematics question?

(5) से गुणा करने पर \(-5<2x-3\leq 15\) मिलता है। इससे \(-1<x\leq 9\) प्राप्त होता है।