यदि (x) एक वास्तविक संख्या है और \(-1<\frac{2x-3}{5}\leq 3\) है तो (x) का हल कौन सा है?
If (x) is a real number and \(-1<\frac{2x-3}{5}\leq 3\), what is the solution for (x)?
Explanation opens after your attempt
A. \(-1<x\leq 9\)
Concept
Multiplying by (5) gives \(-5<2x-3\leq 15\). This gives \(-1<x\leq 9\).
Why this answer is correct
The correct answer is A. \(-1<x\leq 9\). Multiplying by (5) gives \(-5<2x-3\leq 15\). This gives \(-1<x\leq 9\).
Exam Tip
(5) से गुणा करने पर \(-5<2x-3\leq 15\) मिलता है। इससे \(-1<x\leq 9\) प्राप्त होता है।
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