Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 121-130 of 600 questions.
What is the value of (a) for (2x+ay=5) and (6x+9y=15) to have infinitely many solutions?
B. (3)
अनंत हल के लिए (2/6=a/9=5/15) होना चाहिए। इसलिए (a=3) है। / For infinitely many solutions (2/6=a/9=5/15) must hold. Therefore (a=3).
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What will (k) be for (kx+4y=8) and (3x+2y=9) to have no solution?
C. (6)
कोई हल नहीं के लिए (k/3=4/2) और (8/9) अलग होना चाहिए। इससे (k=6) मिलता है। / For no solution (k/3=4/2) and (8/9) must be different. This gives (k=6).
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What is the value of (b) for (5x+by=20) and (10x+6y=40) to have infinitely many solutions?
B. (3)
अनंत हल के लिए (5/10=b/6=20/40) होना चाहिए। इसलिए (b=3) है। / For infinitely many solutions (5/10=b/6=20/40) must hold. Therefore (b=3).
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What is the value of (p) for (px+5y=10) and (4x+10y=23) to have no solution?
B. (2)
कोई हल नहीं के लिए (p/4=5/10) और (10/23) अलग होना चाहिए। इसलिए (p=2) सही है। / For no solution (p/4=5/10) and (10/23) must be different. Therefore (p=2) is correct.
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What will (m) be for infinitely many solutions of (7x+my=28) and (x+2y=4)?
C. (14)
पहला समीकरण दूसरे का (7) गुना होना चाहिए। इसलिए (m=14) होगा। / The first equation must be (7) times the second. Therefore (m=14).
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What will (a) be for (ax+3y=12) and (8x+6y=25) to have no solution?
C. (4)
कोई हल नहीं के लिए (a/8=3/6) और (12/25) अलग होना चाहिए। इससे (a=4) मिलता है। / For no solution (a/8=3/6) and (12/25) must be different. This gives (a=4).
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Which condition is correct for (qx+6y=18) and (5x+3y=12) to have a unique solution?
B. \(q \ne 10\)
अद्वितीय हल के लिए \(q/5 \ne 6/3\) होना चाहिए। इसलिए \(q \ne 10\) सही शर्त है। / For a unique solution \(q/5 \ne 6/3\) must hold. Therefore \(q \ne 10\) is the correct condition.
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What will (k) be for (2x+3y=9) and (4x+ky=18) to have infinitely many solutions?
C. (6)
अनंत हल के लिए (2/4=3/k=9/18) होना चाहिए। इससे (k=6) मिलता है। / For infinitely many solutions (2/4=3/k=9/18) must hold. This gives (k=6).
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What should (t) not be for (3x+2y=11) and (6x+4y=t) to have no solution?
C. (22)
कोई हल नहीं के लिए \(3/6=2/4 \ne 11/t\) होना चाहिए। यदि (t=22) हो तो अनंत हल हो जाएंगे। / For no solution \(3/6=2/4 \ne 11/t\) must hold. If (t=22) the pair will have infinitely many solutions.
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What will be the graph of (x+2y=6) and (3x+6y=18)?
B. एक ही रेखाSame line
दूसरा समीकरण पहले का (3) गुना है। इसलिए ग्राफ में दोनों रेखाएं एक ही दिखाई देंगी। / The second equation is (3) times the first. Therefore both lines will appear as the same line in the graph.
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