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64 results found for "multiples" in Class 10.

(3) के दो क्रमागत धनात्मक गुणजों का गुणनफल (270) है। वे गुणज कौन से हैं?

The product of two consecutive positive multiples of (3) is (270). Which multiples are they?

Explanation opens after your attempt
Correct Answer

C. (15) और (18)(15) and (18)

Step 1

Concept

Let the multiples be (x) and (x+3). From (x(x+3)=270), we get (x=15).

Step 2

Why this answer is correct

The correct answer is C. (15) और (18) / (15) and (18). Let the multiples be (x) and (x+3). From (x(x+3)=270), we get (x=15).

Step 3

Exam Tip

गुणज (x) और (x+3) मानें। (x(x+3)=270) से (x=15) मिलता है।

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(44) से (297) तक (11) के गुणजों का योग कितना होगा?

What is the sum of the multiples of (11) from (44) to (297)?

Explanation opens after your attempt
Correct Answer

A. (4092)

Step 1

Concept

This is the AP \(44,55,\ldots,297\) with (24) terms. Exam tip: find the number of terms first.

Step 2

Why this answer is correct

The correct answer is A. (4092). This is the AP \(44,55,\ldots,297\) with (24) terms. Exam tip: find the number of terms first.

Step 3

Exam Tip

यह समान्तर श्रेणी \(44,55,\ldots,297\) है जिसमें (24) पद हैं। परीक्षा में पहले पदों की संख्या निकालें।

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(21) से (210) तक (7) के गुणजों का योग कितना होगा?

What is the sum of the multiples of (7) from (21) to (210)?

Explanation opens after your attempt
Correct Answer

D. (3234)

Step 1

Concept

This is the AP \(21,28,\ldots,210\) with (28) terms. Exam tip: find the number of terms first.

Step 2

Why this answer is correct

The correct answer is D. (3234). This is the AP \(21,28,\ldots,210\) with (28) terms. Exam tip: find the number of terms first.

Step 3

Exam Tip

यह समान्तर श्रेणी \(21,28,\ldots,210\) है जिसमें (28) पद हैं। परीक्षा में पहले पदों की संख्या निकालें।

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(50) से कम (4) के सभी धनात्मक गुणजों का योग कितना है?

What is the sum of all positive multiples of (4) less than (50)?

Explanation opens after your attempt
Correct Answer

C. (312)

Step 1

Concept

The AP is \(4,8,\ldots,48\) with (12) terms, and the sum is (312). Identifying the last allowed multiple is important.

Step 2

Why this answer is correct

The correct answer is C. (312). The AP is \(4,8,\ldots,48\) with (12) terms, and the sum is (312). Identifying the last allowed multiple is important.

Step 3

Exam Tip

श्रेढ़ी \(4,8,\ldots,48\) है जिसमें (12) पद हैं और योग (312) है। अंतिम स्वीकार्य गुणज पहचानना जरूरी है।

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(7) से (140) तक (7) के सभी धनात्मक गुणजों का योग ज्ञात कीजिए।

Find the sum of all positive multiples of (7) from (7) to (140).

Explanation opens after your attempt
Correct Answer

D. (1470)

Step 1

Concept

The AP is \(7,14,\ldots,140\) with (20) terms, and its sum is (1470). Finding (n) from the last term is an easy method.

Step 2

Why this answer is correct

The correct answer is D. (1470). The AP is \(7,14,\ldots,140\) with (20) terms, and its sum is (1470). Finding (n) from the last term is an easy method.

Step 3

Exam Tip

यह श्रेढ़ी \(7,14,\ldots,140\) है जिसमें (20) पद हैं और योग (1470) है। अंतिम पद से (n) निकालना आसान तरीका है।

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(300) से कम (25) के सभी तीन अंकों वाले गुणजों का योग कितना है?

What is the sum of all three-digit multiples of (25) less than (300)?

Explanation opens after your attempt
Correct Answer

A. (1500)

Step 1

Concept

The multiples are \(100,125,\ldots,275\), and there are (8) terms, so the sum is (1500). Decide the first and last terms according to the limit.

Step 2

Why this answer is correct

The correct answer is A. (1500). The multiples are \(100,125,\ldots,275\), and there are (8) terms, so the sum is (1500). Decide the first and last terms according to the limit.

Step 3

Exam Tip

गुणज \(100,125,\ldots,275\) हैं और (8) पद हैं, इसलिए योग (1500) है। सीमा के अनुसार पहला और अंतिम पद तय करें।

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(4) से (100) तक (4) के गुणजों का योग कितना है?

What is the sum of the multiples of (4) from (4) to (100)?

Explanation opens after your attempt
Correct Answer

B. (1300)

Step 1

Concept

This is the sum of the first (25) multiples of (4), so \(4\times\frac{25\times26}{2}=1300\). Use the sum of natural numbers for multiples.

Step 2

Why this answer is correct

The correct answer is B. (1300). This is the sum of the first (25) multiples of (4), so \(4\times\frac{25\times26}{2}=1300\). Use the sum of natural numbers for multiples.

Step 3

Exam Tip

यह (4) के पहले (25) गुणजों का योग है, इसलिए \(4\times\frac{25\times26}{2}=1300\)। गुणजों में प्राकृतिक संख्याओं का योग लगाएँ।

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(20) से (200) तक (10) के गुणजों का योग कितना है?

What is the sum of the multiples of (10) from (20) to (200)?

Explanation opens after your attempt
Correct Answer

A. (2090)

Step 1

Concept

The sequence is \(20,30,\ldots,200\) with (19) terms, so the sum is (2090). Include both boundary terms.

Step 2

Why this answer is correct

The correct answer is A. (2090). The sequence is \(20,30,\ldots,200\) with (19) terms, so the sum is (2090). Include both boundary terms.

Step 3

Exam Tip

यह श्रेणी \(20,30,\ldots,200\) है जिसमें (19) पद हैं, इसलिए योग (2090) है। सीमा के दोनों सिरों को शामिल करें।

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(100) से कम (6) के सभी धनात्मक गुणजों का योग ज्ञात कीजिए।

Find the sum of all positive multiples of (6) less than (100).

Explanation opens after your attempt
Correct Answer

A. (816)

Step 1

Concept

The multiples are from (6) to (96), and there are (16) terms, so the sum is (816). In boundary questions, decide the last term first.

Step 2

Why this answer is correct

The correct answer is A. (816). The multiples are from (6) to (96), and there are (16) terms, so the sum is (816). In boundary questions, decide the last term first.

Step 3

Exam Tip

गुणज (6) से (96) तक हैं और (16) पद हैं, इसलिए योग (816) है। सीमा वाले प्रश्न में अंतिम पद पहले तय करें।

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(5000) से कम (41) के धनात्मक गुणजों की समान्तर श्रेणी में अंतिम पद क्या होगा?

What will be the last term in the AP of positive multiples of (41) less than (5000)?

Explanation opens after your attempt
Correct Answer

B. (4961)

Step 1

Concept

In (41n<5000), the greatest (n=121). The last term will be \(41\times121=4961\).

Step 2

Why this answer is correct

The correct answer is B. (4961). In (41n<5000), the greatest (n=121). The last term will be \(41\times121=4961\).

Step 3

Exam Tip

(41n<5000) में सबसे बड़ा (n=121) है। अंतिम पद \(41\times121=4961\) होगा।

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(3600) से कम (37) के धनात्मक गुणजों की समान्तर श्रेणी में अंतिम पद क्या होगा?

What will be the last term in the AP of positive multiples of (37) less than (3600)?

Explanation opens after your attempt
Correct Answer

C. (3589)

Step 1

Concept

In (37n<3600), the greatest (n=97). The last term will be \(37\times97=3589\).

Step 2

Why this answer is correct

The correct answer is C. (3589). In (37n<3600), the greatest (n=97). The last term will be \(37\times97=3589\).

Step 3

Exam Tip

(37n<3600) में सबसे बड़ा (n=97) है। अंतिम पद \(37\times97=3589\) होगा।

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(2500) से कम (29) के धनात्मक गुणजों की समान्तर श्रेणी में अंतिम पद क्या होगा?

What will be the last term in the AP of positive multiples of (29) less than (2500)?

Explanation opens after your attempt
Correct Answer

B. (2494)

Step 1

Concept

In (29n<2500), the greatest (n=86). The last term will be \(29\times86=2494\).

Step 2

Why this answer is correct

The correct answer is B. (2494). In (29n<2500), the greatest (n=86). The last term will be \(29\times86=2494\).

Step 3

Exam Tip

(29n<2500) में सबसे बड़ा (n=86) है। अंतिम पद \(29\times86=2494\) होगा।

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(2000) से कम (23) के धनात्मक गुणजों की समान्तर श्रेणी में अंतिम पद क्या है?

What is the last term in the AP of positive multiples of (23) less than (2000)?

Explanation opens after your attempt
Correct Answer

B. (1978)

Step 1

Concept

In (23n<2000), the greatest (n=86). The last term will be \(23\times86=1978\).

Step 2

Why this answer is correct

The correct answer is B. (1978). In (23n<2000), the greatest (n=86). The last term will be \(23\times86=1978\).

Step 3

Exam Tip

(23n<2000) में सबसे बड़ा (n=86) है। अंतिम पद \(23\times86=1978\) होगा।

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(1500) से कम (19) के धनात्मक गुणजों की समान्तर श्रेणी में अंतिम पद क्या है?

What is the last term in the AP of positive multiples of (19) less than (1500)?

Explanation opens after your attempt
Correct Answer

A. (1482)

Step 1

Concept

In (19n<1500), the greatest (n=78). The last term will be \(19\times78=1482\).

Step 2

Why this answer is correct

The correct answer is A. (1482). In (19n<1500), the greatest (n=78). The last term will be \(19\times78=1482\).

Step 3

Exam Tip

(19n<1500) में सबसे बड़ा (n=78) है। अंतिम पद \(19\times78=1482\) होगा।

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(1000) से कम (17) के धनात्मक गुणजों की AP में अंतिम पद क्या है?

What is the last term in the AP of positive multiples of (17) less than (1000)?

Explanation opens after your attempt
Correct Answer

B. (986)

Step 1

Concept

In (17n<1000), the greatest (n=58). The last term will be \(17\times58=986\).

Step 2

Why this answer is correct

The correct answer is B. (986). In (17n<1000), the greatest (n=58). The last term will be \(17\times58=986\).

Step 3

Exam Tip

(17n<1000) में सबसे बड़ा (n=58) है। अंतिम पद \(17\times58=986\) होगा।

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(600) से कम (13) के धनात्मक गुणजों में अंतिम पद क्या है?

What is the last term among the positive multiples of (13) less than (600)?

Explanation opens after your attempt
Correct Answer

B. (598)

Step 1

Concept

In (13n<600), the greatest (n=46) so the term is \(13\times46=598\). Take the greatest integer below the limit.

Step 2

Why this answer is correct

The correct answer is B. (598). In (13n<600), the greatest (n=46) so the term is \(13\times46=598\). Take the greatest integer below the limit.

Step 3

Exam Tip

(13n<600) में सबसे बड़ा (n=46) है इसलिए पद \(13\times46=598\)। सीमा से कम सबसे बड़ा पूर्णांक लें।

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(400) से बड़े (12) के गुणजों की AP \(408,420,432,\ldots\) है। इसका (18)वां पद क्या होगा?

The AP of multiples of (12) greater than (400) is \(408,420,432,\ldots\). What is its (18)th term?

Explanation opens after your attempt
Correct Answer

A. (612)

Step 1

Concept

Here (a=408) and (d=12) so \(a_{18}=408+17\times12=612\). Choose the first correct multiple after the limit.

Step 2

Why this answer is correct

The correct answer is A. (612). Here (a=408) and (d=12) so \(a_{18}=408+17\times12=612\). Choose the first correct multiple after the limit.

Step 3

Exam Tip

यहां (a=408) और (d=12) है इसलिए \(a_{18}=408+17\times12=612\)। सीमा के बाद पहला सही गुणज चुनें।

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(500) से कम (11) के धनात्मक गुणजों में अंतिम पद क्या है?

What is the last term among the positive multiples of (11) less than (500)?

Explanation opens after your attempt
Correct Answer

B. (495)

Step 1

Concept

In (11n<500), the greatest (n=45), so the term is \(11\times45=495\). Take the greatest integer below the limit.

Step 2

Why this answer is correct

The correct answer is B. (495). In (11n<500), the greatest (n=45), so the term is \(11\times45=495\). Take the greatest integer below the limit.

Step 3

Exam Tip

(11n<500) में सबसे बड़ा (n=45) है इसलिए पद \(11\times45=495\)। सीमा से कम सबसे बड़ा पूर्णांक लें।

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(300) से बड़े (8) के गुणजों की समान्तर श्रेणी \(304,312,320,\ldots\) है। इसका (25)वां पद क्या होगा?

The AP of multiples of (8) greater than (300) is \(304,312,320,\ldots\). What is its (25)th term?

Explanation opens after your attempt
Correct Answer

A. (496)

Step 1

Concept

Here (a=304) and (d=8) so \(a_{25}=304+24\times8=496\). Choose the first correct multiple after the limit.

Step 2

Why this answer is correct

The correct answer is A. (496). Here (a=304) and (d=8) so \(a_{25}=304+24\times8=496\). Choose the first correct multiple after the limit.

Step 3

Exam Tip

यहां (a=304) और (d=8) है इसलिए \(a_{25}=304+24\times8=496\)। सीमा के बाद पहला सही गुणज चुनें।

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(200) से कम (9) के धनात्मक गुणजों में अंतिम पद क्या है?

What is the last term among the positive multiples of (9) less than (200)?

Explanation opens after your attempt
Correct Answer

C. (198)

Step 1

Concept

In \(9,18,27,\ldots\), (9n<200), so the greatest (n=22) and the term is (198). For multiples, take the largest integer below the limit.

Step 2

Why this answer is correct

The correct answer is C. (198). In \(9,18,27,\ldots\), (9n<200), so the greatest (n=22) and the term is (198). For multiples, take the largest integer below the limit.

Step 3

Exam Tip

\(9,18,27,\ldots\) में (9n<200), इसलिए सबसे बड़ा (n=22) और पद (198) है। गुणजों में सीमा से कम सबसे बड़ा पूर्णांक लें।

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समांतर श्रेढ़ी \(2,9,16,\ldots\) के पहले (50) पदों में उन पदों का योग ज्ञात कीजिए जिनके क्रमांक (5) के गुणज हैं।

In the first (50) terms of the AP \(2,9,16,\ldots\), find the sum of the terms whose positions are multiples of (5).

Explanation opens after your attempt
Correct Answer

B. (1875)

Step 1

Concept

The selected terms are \(a_5,a_{10},\ldots,a_{50}\), and their sum is (1875). In position-based questions, form the new AP of selected terms.

Step 2

Why this answer is correct

The correct answer is B. (1875). The selected terms are \(a_5,a_{10},\ldots,a_{50}\), and their sum is (1875). In position-based questions, form the new AP of selected terms.

Step 3

Exam Tip

चुने गए पद \(a_5,a_{10},\ldots,a_{50}\) हैं और उनका योग (1875) है। क्रमांक आधारित प्रश्न में चुने गए पदों की नई श्रेढ़ी बनाएँ।

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समांतर श्रेढ़ी \(1,6,11,\ldots\) के पहले (40) पदों में उन पदों का योग ज्ञात कीजिए जिनके क्रमांक (4) के गुणज हैं।

In the first (40) terms of the AP \(1,6,11,\ldots\), find the sum of the terms whose positions are multiples of (4).

Explanation opens after your attempt
Correct Answer

A. (1060)

Step 1

Concept

The selected terms are \(a_4,a_8,\ldots,a_{40}\), and their sum is (1060). In position-based questions, form the new AP of selected terms.

Step 2

Why this answer is correct

The correct answer is A. (1060). The selected terms are \(a_4,a_8,\ldots,a_{40}\), and their sum is (1060). In position-based questions, form the new AP of selected terms.

Step 3

Exam Tip

चुने गए पद \(a_4,a_8,\ldots,a_{40}\) हैं और उनका योग (1060) है। क्रमांक आधारित प्रश्न में चुने गए पदों की नई श्रेढ़ी बनाएँ।

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समांतर श्रेढ़ी \(2,5,8,\ldots\) के पहले (30) पदों में उन पदों का योग ज्ञात कीजिए जिनके क्रमांक (3) के गुणज हैं।

In the first (30) terms of the AP \(2,5,8,\ldots\), find the sum of the terms whose positions are multiples of (3).

Explanation opens after your attempt
Correct Answer

A. (485)

Step 1

Concept

The selected terms are \(a_3,a_6,\ldots,a_{30}\), and their sum is (485). In position-based questions, form the new AP of selected terms.

Step 2

Why this answer is correct

The correct answer is A. (485). The selected terms are \(a_3,a_6,\ldots,a_{30}\), and their sum is (485). In position-based questions, form the new AP of selected terms.

Step 3

Exam Tip

चुने गए पद \(a_3,a_6,\ldots,a_{30}\) हैं और उनका योग (485) है। क्रमांक आधारित प्रश्न में चुने गए पदों की नई श्रेढ़ी बनाएँ।

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(1500) से बड़े (37) के गुणजों की AP \(1517,1554,1591,\ldots\) है। इसका (31)वां पद क्या होगा?

The AP of multiples of (37) greater than (1500) is \(1517,1554,1591,\ldots\). What will be its (31)st term?

Explanation opens after your attempt
Correct Answer

B. (2627)

Step 1

Concept

Here (a=1517) and (d=37). \(a_{31}=1517+30\times37=2627\).

Step 2

Why this answer is correct

The correct answer is B. (2627). Here (a=1517) and (d=37). \(a_{31}=1517+30\times37=2627\).

Step 3

Exam Tip

यहां (a=1517) और (d=37)। \(a_{31}=1517+30\times37=2627\)।

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(1200) से बड़े (31) के गुणजों की AP \(1209,1240,1271,\ldots\) है। इसका (29)वां पद क्या होगा?

The AP of multiples of (31) greater than (1200) is \(1209,1240,1271,\ldots\). What will be its (29)th term?

Explanation opens after your attempt
Correct Answer

A. (2077)

Step 1

Concept

Here (a=1209) and (d=31). \(a_{29}=1209+28\times31=2077\).

Step 2

Why this answer is correct

The correct answer is A. (2077). Here (a=1209) and (d=31). \(a_{29}=1209+28\times31=2077\).

Step 3

Exam Tip

यहां (a=1209) और (d=31)। \(a_{29}=1209+28\times31=2077\)।

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(900) से बड़े (23) के गुणजों की समान्तर श्रेणी \(920,943,966,\ldots\) है। इसका (27)वां पद क्या होगा?

The AP of multiples of (23) greater than (900) is \(920,943,966,\ldots\). What will be its (27)th term?

Explanation opens after your attempt
Correct Answer

A. (1518)

Step 1

Concept

Here (a=920) and (d=23). \(a_{27}=920+26\times23=1518\).

Step 2

Why this answer is correct

The correct answer is A. (1518). Here (a=920) and (d=23). \(a_{27}=920+26\times23=1518\).

Step 3

Exam Tip

यहां (a=920) और (d=23)। \(a_{27}=920+26\times23=1518\)।

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(700) से बड़े (19) के गुणजों की समान्तर श्रेणी \(703,722,741,\ldots\) है। इसका (24)वां पद क्या होगा?

The AP of multiples of (19) greater than (700) is \(703,722,741,\ldots\). What is its (24)th term?

Explanation opens after your attempt
Correct Answer

B. (1140)

Step 1

Concept

Here (a=703) and (d=19). \(a_{24}=703+23\times19=1140\).

Step 2

Why this answer is correct

The correct answer is B. (1140). Here (a=703) and (d=19). \(a_{24}=703+23\times19=1140\).

Step 3

Exam Tip

यहां (a=703) और (d=19)। \(a_{24}=703+23\times19=1140\)।

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(500) से बड़े (17) के गुणजों की समान्तर श्रेणी \(510,527,544,\ldots\) है। इसका (19)वां पद क्या होगा?

The AP of multiples of (17) greater than (500) is \(510,527,544,\ldots\). What is its (19)th term?

Explanation opens after your attempt
Correct Answer

B. (816)

Step 1

Concept

Here (a=510) and (d=17). \(a_{19}=510+18\times17=816\).

Step 2

Why this answer is correct

The correct answer is B. (816). Here (a=510) and (d=17). \(a_{19}=510+18\times17=816\).

Step 3

Exam Tip

यहां (a=510) और (d=17)। \(a_{19}=510+18\times17=816\)।

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(250) से बड़े (13) के गुणजों की AP \(260,273,286,\ldots\) है। इसका (22)वां पद क्या होगा?

The AP of multiples of (13) greater than (250) is \(260,273,286,\ldots\). What is its (22)nd term?

Explanation opens after your attempt
Correct Answer

B. (533)

Step 1

Concept

Here (a=260) and (d=13). \(a_{22}=260+21\times13=533\).

Step 2

Why this answer is correct

The correct answer is B. (533). Here (a=260) and (d=13). \(a_{22}=260+21\times13=533\).

Step 3

Exam Tip

यहां (a=260) और (d=13)। \(a_{22}=260+21\times13=533\)।

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तीन अंकों वाली पहली संख्या (100) है जो (7) से विभाज्य नहीं है, लेकिन \(105,112,119,\ldots\) तीन अंकों वाली (7) की गुणज AP है। इस AP का (50)वां पद क्या होगा?

The first three-digit number is (100), which is not divisible by (7), but \(105,112,119,\ldots\) is the AP of three-digit multiples of (7). What is the (50)th term of this AP?

Explanation opens after your attempt
Correct Answer

B. (448)

Step 1

Concept

In this AP, (a=105), (d=7), so \(a_{50}=105+49\times7=448\). In an AP of multiples, choose the first correct multiple.

Step 2

Why this answer is correct

The correct answer is B. (448). In this AP, (a=105), (d=7), so \(a_{50}=105+49\times7=448\). In an AP of multiples, choose the first correct multiple.

Step 3

Exam Tip

इस AP में (a=105), (d=7), इसलिए \(a_{50}=105+49\times7=448\)। गुणजों की AP में पहला सही गुणज चुनें।

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तीन अंकों वाली (19) से विभाज्य सभी संख्याओं का योग कितना होगा?

What is the sum of all three-digit numbers divisible by (19)?

Explanation opens after your attempt
Correct Answer

D. (25897)

Step 1

Concept

The numbers are \(114,133,\ldots,988\), and there are (47) terms. Exam tip: find the first and last three-digit multiples.

Step 2

Why this answer is correct

The correct answer is D. (25897). The numbers are \(114,133,\ldots,988\), and there are (47) terms. Exam tip: find the first and last three-digit multiples.

Step 3

Exam Tip

संख्याएँ \(114,133,\ldots,988\) हैं और कुल (47) पद हैं। परीक्षा में पहला और अंतिम तीन अंकीय गुणज निकालें।

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(10) और (130) के बीच (4) और (6) दोनों से विभाज्य संख्याओं का योग कितना होगा?

What is the sum of numbers between (10) and (130) that are divisible by both (4) and (6)?

Explanation opens after your attempt
Correct Answer

B. (840)

Step 1

Concept

The numbers are \(12,24,\ldots,120\), and there are (10) terms. Exam tip: divisible by both means use the least common multiple.

Step 2

Why this answer is correct

The correct answer is B. (840). The numbers are \(12,24,\ldots,120\), and there are (10) terms. Exam tip: divisible by both means use the least common multiple.

Step 3

Exam Tip

ऐसी संख्याएँ \(12,24,\ldots,120\) हैं और कुल (10) पद हैं। परीक्षा में दोनों से विभाज्य का अर्थ लघुत्तम समापवर्त्य लें।

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तीन अंकों वाली (17) से विभाज्य सभी संख्याओं का योग कितना होगा?

What is the sum of all three-digit numbers divisible by (17)?

Explanation opens after your attempt
Correct Answer

C. (31518)

Step 1

Concept

The numbers are \(102,119,\ldots,986\), and there are (53) terms. Exam tip: find the first and last three-digit multiples.

Step 2

Why this answer is correct

The correct answer is C. (31518). The numbers are \(102,119,\ldots,986\), and there are (53) terms. Exam tip: find the first and last three-digit multiples.

Step 3

Exam Tip

संख्याएँ \(102,119,\ldots,986\) हैं और कुल (53) पद हैं। परीक्षा में पहला और अंतिम तीन अंकीय गुणज निकालें।

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(75) और (255) के बीच (12) से विभाज्य संख्याओं का योग कितना होगा?

What is the sum of numbers divisible by (12) between (75) and (255)?

Explanation opens after your attempt
Correct Answer

C. (2592)

Step 1

Concept

The terms are \(84,96,\ldots,252\), making (15) terms. Exam tip: choose the first and last valid terms carefully.

Step 2

Why this answer is correct

The correct answer is C. (2592). The terms are \(84,96,\ldots,252\), making (15) terms. Exam tip: choose the first and last valid terms carefully.

Step 3

Exam Tip

पद \(84,96,\ldots,252\) हैं और कुल (15) पद बनते हैं। परीक्षा में पहला और अंतिम मान सावधानी से चुनें।

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(200) से (1200) तक (19) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।

Find the sum of all numbers divisible by (19) from (200) to (1200).

Explanation opens after your attempt
Correct Answer

A. (37259)

Step 1

Concept

The first multiple is (209), the last is (1197), and there are (53) terms, so the sum is (37259). Choose the first multiple within the range correctly.

Step 2

Why this answer is correct

The correct answer is A. (37259). The first multiple is (209), the last is (1197), and there are (53) terms, so the sum is (37259). Choose the first multiple within the range correctly.

Step 3

Exam Tip

पहला गुणज (209), अंतिम (1197) और (53) पद हैं, इसलिए योग (37259) है। सीमा के अंदर पहला गुणज सही चुनें।

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(1) से (1500) तक उन सभी संख्याओं का योग ज्ञात कीजिए जो (9) से विभाज्य हैं लेकिन (12) से विभाज्य नहीं हैं।

Find the sum of all numbers from (1) to (1500) that are divisible by (9) but not by (12).

Explanation opens after your attempt
Correct Answer

A. (93753)

Step 1

Concept

Subtracting the sum of multiples of (36) from the sum of multiples of (9) gives (93753). Numbers divisible by both are multiples of (\operatorname{lcm}(9,12)).

Step 2

Why this answer is correct

The correct answer is A. (93753). Subtracting the sum of multiples of (36) from the sum of multiples of (9) gives (93753). Numbers divisible by both are multiples of (\operatorname{lcm}(9,12)).

Step 3

Exam Tip

(9) के गुणजों के योग से (36) के गुणजों का योग घटाने पर (93753) मिलता है। दोनों से विभाज्य संख्याएँ (\operatorname{lcm}(9,12)) की गुणज होती हैं।

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(1) से (1000) तक उन सभी संख्याओं का योग ज्ञात कीजिए जो (5) या (8) से विभाज्य हैं।

Find the sum of all numbers from (1) to (1000) that are divisible by (5) or (8).

Explanation opens after your attempt
Correct Answer

B. (150500)

Step 1

Concept

Adding sums of multiples of (5) and (8), then subtracting multiples of (40), gives (150500). Avoiding double counting is important.

Step 2

Why this answer is correct

The correct answer is B. (150500). Adding sums of multiples of (5) and (8), then subtracting multiples of (40), gives (150500). Avoiding double counting is important.

Step 3

Exam Tip

(5) और (8) के गुणजों के योग जोड़कर (40) के गुणजों का योग घटाने से (150500) मिलता है। दोहरी गिनती से बचना जरूरी है।

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(120) से (900) तक (16) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।

Find the sum of all numbers divisible by (16) from (120) to (900).

Explanation opens after your attempt
Correct Answer

A. (25088)

Step 1

Concept

The first multiple is (128), the last is (896), and there are (49) terms, so the sum is (25088). Choose the first term according to the range carefully.

Step 2

Why this answer is correct

The correct answer is A. (25088). The first multiple is (128), the last is (896), and there are (49) terms, so the sum is (25088). Choose the first term according to the range carefully.

Step 3

Exam Tip

पहला गुणज (128), अंतिम (896) और कुल (49) पद हैं, इसलिए योग (25088) है। सीमा के अनुसार पहला पद ध्यान से चुनें।

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(150) से (750) तक (17) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।

Find the sum of all numbers divisible by (17) from (150) to (750).

Explanation opens after your attempt
Correct Answer

B. (16218)

Step 1

Concept

The numbers are \(153,170,\ldots,748\), and their sum is (16218). Choose the first and last multiples within the limits correctly.

Step 2

Why this answer is correct

The correct answer is B. (16218). The numbers are \(153,170,\ldots,748\), and their sum is (16218). Choose the first and last multiples within the limits correctly.

Step 3

Exam Tip

संख्याएँ \(153,170,\ldots,748\) हैं और उनका योग (16218) है। सीमा के अंदर पहला और अंतिम गुणज सही चुनें।

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(1) से (1000) तक उन सभी संख्याओं का योग ज्ञात कीजिए जो (6) से विभाज्य हैं लेकिन (15) से विभाज्य नहीं हैं।

Find the sum of all numbers from (1) to (1000) that are divisible by (6) but not by (15).

Explanation opens after your attempt
Correct Answer

C. (66336)

Step 1

Concept

Subtracting the sum of multiples of (30) from the sum of multiples of (6) gives (66336). Numbers divisible by both (6) and (15) are multiples of (30).

Step 2

Why this answer is correct

The correct answer is C. (66336). Subtracting the sum of multiples of (30) from the sum of multiples of (6) gives (66336). Numbers divisible by both (6) and (15) are multiples of (30).

Step 3

Exam Tip

(6) के गुणजों के योग से (30) के गुणजों का योग घटाने पर (66336) मिलता है। (6) और (15) दोनों से विभाज्य संख्याएँ (30) की गुणज होती हैं।

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(1) से (700) तक उन सभी संख्याओं का योग ज्ञात कीजिए जो (4) या (7) से विभाज्य हैं।

Find the sum of all numbers from (1) to (700) that are divisible by (4) or (7).

Explanation opens after your attempt
Correct Answer

A. (87850)

Step 1

Concept

Adding sums of multiples of (4) and (7), then subtracting multiples of (28), gives (87850). Avoiding double counting is important.

Step 2

Why this answer is correct

The correct answer is A. (87850). Adding sums of multiples of (4) and (7), then subtracting multiples of (28), gives (87850). Avoiding double counting is important.

Step 3

Exam Tip

(4) और (7) के गुणजों के योग जोड़कर (28) के गुणजों का योग घटाने से (87850) मिलता है। दोहरी गिनती से बचना जरूरी है।

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(80) से (600) तक (13) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।

Find the sum of all numbers divisible by (13) from (80) to (600).

Explanation opens after your attempt
Correct Answer

C. (13780)

Step 1

Concept

The first multiple is (91), the last is (598), and there are (40) terms, so the sum is (13780). Choose the first term according to the range carefully.

Step 2

Why this answer is correct

The correct answer is C. (13780). The first multiple is (91), the last is (598), and there are (40) terms, so the sum is (13780). Choose the first term according to the range carefully.

Step 3

Exam Tip

पहला गुणज (91), अंतिम (598) और कुल (40) पद हैं, इसलिए योग (13780) है। सीमा के अनुसार पहला पद ध्यान से चुनें।

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(200) से (800) तक (14) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।

Find the sum of all numbers divisible by (14) from (200) to (800).

Explanation opens after your attempt
Correct Answer

D. (21672)

Step 1

Concept

The numbers are \(210,224,\ldots,798\), and their sum is (21672). Choose the first and last multiples within the limits correctly.

Step 2

Why this answer is correct

The correct answer is D. (21672). The numbers are \(210,224,\ldots,798\), and their sum is (21672). Choose the first and last multiples within the limits correctly.

Step 3

Exam Tip

संख्याएँ \(210,224,\ldots,798\) हैं और उनका योग (21672) है। सीमा के अंदर पहला और अंतिम गुणज सही चुनें।

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(1) से (1000) तक उन सभी संख्याओं का योग ज्ञात कीजिए जो (4) से विभाज्य हैं लेकिन (10) से विभाज्य नहीं हैं।

Find the sum of all numbers from (1) to (1000) that are divisible by (4) but not by (10).

Explanation opens after your attempt
Correct Answer

D. (100000)

Step 1

Concept

The sum of multiples of (4) is (125500), and the sum of multiples of (20) is (25500), so the answer is (100000). Remove overlap using \(\operatorname{lcm}\).

Step 2

Why this answer is correct

The correct answer is D. (100000). The sum of multiples of (4) is (125500), and the sum of multiples of (20) is (25500), so the answer is (100000). Remove overlap using \(\operatorname{lcm}\).

Step 3

Exam Tip

(4) के गुणजों का योग (125500) और (20) के गुणजों का योग (25500) है, इसलिए उत्तर (100000) है। \(\operatorname{lcm}\) से overlap हटाएँ।

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(1) से (500) तक उन सभी संख्याओं का योग ज्ञात कीजिए जो (3) या (5) से विभाज्य हैं।

Find the sum of all numbers from (1) to (500) that are divisible by (3) or (5).

Explanation opens after your attempt
Correct Answer

A. (58418)

Step 1

Concept

Adding sums of multiples of (3) and (5), then subtracting multiples of (15), gives (58418). Avoiding double counting is important.

Step 2

Why this answer is correct

The correct answer is A. (58418). Adding sums of multiples of (3) and (5), then subtracting multiples of (15), gives (58418). Avoiding double counting is important.

Step 3

Exam Tip

(3) और (5) के गुणजों के योग जोड़कर (15) के गुणजों का योग घटाने से (58418) मिलता है। दोहरी गिनती से बचना जरूरी है।

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(50) से (250) तक (7) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।

Find the sum of all numbers divisible by (7) from (50) to (250).

Explanation opens after your attempt
Correct Answer

C. (4214)

Step 1

Concept

The AP is \(56,63,\ldots,245\) with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.

Step 2

Why this answer is correct

The correct answer is C. (4214). The AP is \(56,63,\ldots,245\) with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.

Step 3

Exam Tip

श्रेढ़ी \(56,63,\ldots,245\) है जिसमें (28) पद हैं और योग (4214) है। सीमा के अंदर पहला और अंतिम गुणज सही चुनें।

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तीन अंकों वाली उन सभी विषम संख्याओं का योग ज्ञात कीजिए जो (9) से विभाज्य हैं।

Find the sum of all three-digit odd numbers that are divisible by (9).

Explanation opens after your attempt
Correct Answer

B. (27900)

Step 1

Concept

The numbers are \(117,135,\ldots,999\), and the sum of (50) terms is (27900). For odd multiples, the common difference is (18).

Step 2

Why this answer is correct

The correct answer is B. (27900). The numbers are \(117,135,\ldots,999\), and the sum of (50) terms is (27900). For odd multiples, the common difference is (18).

Step 3

Exam Tip

संख्याएँ \(117,135,\ldots,999\) हैं और (50) पदों का योग (27900) है। विषम गुणजों में अंतर (18) होगा।

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(100) और (500) के बीच (11) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।

Find the sum of all numbers divisible by (11) between (100) and (500).

Explanation opens after your attempt
Correct Answer

D. (10890)

Step 1

Concept

The numbers are \(110,121,\ldots,495\), and their sum is (10890). When between is written, check carefully whether endpoints are included.

Step 2

Why this answer is correct

The correct answer is D. (10890). The numbers are \(110,121,\ldots,495\), and their sum is (10890). When between is written, check carefully whether endpoints are included.

Step 3

Exam Tip

संख्याएँ \(110,121,\ldots,495\) हैं और उनका योग (10890) है। between लिखे होने पर सिरों को शामिल करना है या नहीं यह ध्यान से देखें।

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एक सड़क पर खंभों की दूरी के क्रम \(6,12,18,\ldots\) मीटर हैं। पहले (25) अंतरालों की कुल दूरी कितनी होगी?

On a road, the distances of intervals are \(6,12,18,\ldots\) meters. What is the total distance of the first (25) intervals?

Explanation opens after your attempt
Correct Answer

C. (1950)

Step 1

Concept

This is the sum of the first (25) multiples of (6), so the total distance is (1950) meters. In sums of multiples, (a=d).

Step 2

Why this answer is correct

The correct answer is C. (1950). This is the sum of the first (25) multiples of (6), so the total distance is (1950) meters. In sums of multiples, (a=d).

Step 3

Exam Tip

यह (6) के पहले (25) गुणजों का योग है, इसलिए कुल दूरी (1950) मीटर है। गुणजों के योग में (a=d) होता है।

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समांतर श्रेणी \(11,22,33,\ldots\) के पहले (14) पदों का योग ज्ञात कीजिए।

Find the sum of the first (14) terms of the arithmetic progression \(11,22,33,\ldots\).

Explanation opens after your attempt
Correct Answer

B. (1155)

Step 1

Concept

This is the sum of the first (14) multiples of (11), so \(11\times\frac{14\times15}{2}=1155\). For multiples, use the sum of natural numbers.

Step 2

Why this answer is correct

The correct answer is B. (1155). This is the sum of the first (14) multiples of (11), so \(11\times\frac{14\times15}{2}=1155\). For multiples, use the sum of natural numbers.

Step 3

Exam Tip

यह (11) के पहले (14) गुणजों का योग है, इसलिए \(11\times\frac{14\times15}{2}=1155\)। गुणजों में प्राकृतिक संख्याओं के योग का उपयोग करें।

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यदि (a=9), (d=9), और (n=8) है, तो समांतर श्रेणी के पहले (8) पदों का योग क्या होगा?

If (a=9), (d=9), and (n=8), what will be the sum of the first (8) terms of the arithmetic progression?

Explanation opens after your attempt
Correct Answer

C. (324)

Step 1

Concept

This is the sum of the first (8) multiples of (9), so \(9\times36=324\). If (a=d), the multiples method is faster.

Step 2

Why this answer is correct

The correct answer is C. (324). This is the sum of the first (8) multiples of (9), so \(9\times36=324\). If (a=d), the multiples method is faster.

Step 3

Exam Tip

यह (9) के पहले (8) गुणजों का योग है, इसलिए \(9\times36=324\)। (a=d) हो तो गुणज वाला तरीका तेज है।

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समांतर श्रेणी \(16,32,48,\ldots\) के पहले (6) पदों का योग ज्ञात करें।

Find the sum of the first (6) terms of the arithmetic progression \(16,32,48,\ldots\).

Explanation opens after your attempt
Correct Answer

A. (336)

Step 1

Concept

This is the sum of the first (6) multiples of (16), so \(16\times21=336\). For multiples, use \(1+2+\cdots+n\).

Step 2

Why this answer is correct

The correct answer is A. (336). This is the sum of the first (6) multiples of (16), so \(16\times21=336\). For multiples, use \(1+2+\cdots+n\).

Step 3

Exam Tip

यह (16) के पहले (6) गुणजों का योग है, इसलिए \(16\times21=336\)। गुणजों में \(1+2+\cdots+n\) का उपयोग करें।

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समांतर श्रेणी \(8,16,24,\ldots\) के पहले (11) पदों का योग क्या है?

What is the sum of the first (11) terms of the arithmetic progression \(8,16,24,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (528)

Step 1

Concept

This is the sum of the first (11) multiples of (8), so \(8\times66=528\). For multiples, use the sum of natural numbers.

Step 2

Why this answer is correct

The correct answer is B. (528). This is the sum of the first (11) multiples of (8), so \(8\times66=528\). For multiples, use the sum of natural numbers.

Step 3

Exam Tip

यह (8) के पहले (11) गुणजों का योग है, इसलिए \(8\times66=528\)। गुणजों में प्राकृतिक संख्याओं के योग का उपयोग करें।

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समांतर श्रेढ़ी \(21,28,35,\ldots\) के पहले (6) पदों का योग कितना होगा?

What will be the sum of the first (6) terms of the arithmetic progression \(21,28,35,\ldots\)?

Explanation opens after your attempt
Correct Answer

A. (231)

Step 1

Concept

These are the (3)rd to (8)th multiples of (7), or directly (a=21), (d=7), (n=6) gives (231). Look carefully at the first term.

Step 2

Why this answer is correct

The correct answer is A. (231). These are the (3)rd to (8)th multiples of (7), or directly (a=21), (d=7), (n=6) gives (231). Look carefully at the first term.

Step 3

Exam Tip

यह (7) के (3)वें से (8)वें गुणजों का योग है, या सीधे (a=21), (d=7), (n=6) से (231) मिलता है। प्रश्न में पहले पद को ध्यान से देखें।

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समांतर श्रेढ़ी \(11,22,33,\ldots\) के पहले (5) पदों का योग ज्ञात करें।

Find the sum of the first (5) terms of the arithmetic progression \(11,22,33,\ldots\).

Explanation opens after your attempt
Correct Answer

B. (165)

Step 1

Concept

This is the sum of the first (5) multiples of (11), so \(11\times15=165\). For multiples, the sum of the first (n) natural numbers is useful.

Step 2

Why this answer is correct

The correct answer is B. (165). This is the sum of the first (5) multiples of (11), so \(11\times15=165\). For multiples, the sum of the first (n) natural numbers is useful.

Step 3

Exam Tip

यह (11) के पहले (5) गुणजों का योग है, इसलिए \(11\times15=165\)। गुणजों में पहले (n) प्राकृतिक संख्याओं का योग काम आता है।

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समांतर श्रेढ़ी \(7,14,21,\ldots\) के पहले (8) पदों का योग क्या है?

What is the sum of the first (8) terms of the arithmetic progression \(7,14,21,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (252)

Step 1

Concept

This is the sum of the first (8) multiples of (7), so \(7\times36=252\). For multiples, use the sum of natural numbers.

Step 2

Why this answer is correct

The correct answer is B. (252). This is the sum of the first (8) multiples of (7), so \(7\times36=252\). For multiples, use the sum of natural numbers.

Step 3

Exam Tip

यह (7) के पहले (8) गुणजों का योग है, इसलिए \(7\times36=252\)। गुणजों के प्रश्न में प्राकृतिक संख्याओं के योग का उपयोग करें।

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समांतर श्रेढ़ी \(6,12,18,\ldots\) के पहले (10) पदों का योग क्या है?

What is the sum of the first (10) terms of the arithmetic progression \(6,12,18,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (330)

Step 1

Concept

These are the first (10) multiples of (6), whose sum is (330). Treat multiples as an arithmetic progression.

Step 2

Why this answer is correct

The correct answer is C. (330). These are the first (10) multiples of (6), whose sum is (330). Treat multiples as an arithmetic progression.

Step 3

Exam Tip

यह (6) के पहले (10) गुणज हैं, जिनका योग (330) है। गुणजों को भी समांतर श्रेढ़ी की तरह हल करें।

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एक AP में (a=11), (d=11), (n=20) है। योग क्या है?

In an AP (a=11), (d=11), (n=20). What is the sum?

Explanation opens after your attempt
Correct Answer

A. (2310)

Step 1

Concept

This is the sum of the first (20) multiples of (11). (S_{20}=\frac{20}{2}(11+220)=2310).

Step 2

Why this answer is correct

The correct answer is A. (2310). This is the sum of the first (20) multiples of (11). (S_{20}=\frac{20}{2}(11+220)=2310).

Step 3

Exam Tip

यह (11) के पहले (20) गुणजों का योग है। (S_{20}=\frac{20}{2}(11+220)=2310)।

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समान्तर श्रेणी \(9,18,27,\ldots\) के पहले (12) पदों का योग कितना है?

What is the sum of the first (12) terms of the AP \(9,18,27,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (702)

Step 1

Concept

The last term is (108). (S_{12}=\frac{12}{2}(9+108)=702).

Step 2

Why this answer is correct

The correct answer is B. (702). The last term is (108). (S_{12}=\frac{12}{2}(9+108)=702).

Step 3

Exam Tip

अंतिम पद (108) है। (S_{12}=\frac{12}{2}(9+108)=702)।

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समान्तर श्रेणी \(11,22,33,\ldots\) के पहले (9) पदों का योग कितना है?

What is the sum of the first (9) terms of the AP \(11,22,33,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (495)

Step 1

Concept

The last term is (99). (S_9=\frac{9}{2}(11+99)=495).

Step 2

Why this answer is correct

The correct answer is B. (495). The last term is (99). (S_9=\frac{9}{2}(11+99)=495).

Step 3

Exam Tip

अंतिम पद (99) है। (S_9=\frac{9}{2}(11+99)=495)।

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समान्तर श्रेणी \(5,10,15,\ldots\) के पहले (18) पदों का योग क्या होगा?

What will be the sum of the first (18) terms of the AP \(5,10,15,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (855)

Step 1

Concept

Here the last term is (90). (S_{18}=\frac{18}{2}(5+90)=855).

Step 2

Why this answer is correct

The correct answer is B. (855). Here the last term is (90). (S_{18}=\frac{18}{2}(5+90)=855).

Step 3

Exam Tip

यहां अंतिम पद (90) है। (S_{18}=\frac{18}{2}(5+90)=855)।

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समान्तर श्रेणी \(7,14,21,\ldots\) के पहले (10) पदों का योग क्या होगा?

What will be the sum of the first (10) terms of the AP \(7,14,21,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (385)

Step 1

Concept

This is the sequence of multiples of (7). (S_{10}=\frac{10}{2}(7+70)=385).

Step 2

Why this answer is correct

The correct answer is C. (385). This is the sequence of multiples of (7). (S_{10}=\frac{10}{2}(7+70)=385).

Step 3

Exam Tip

यह (7) के गुणजों की श्रेणी है। (S_{10}=\frac{10}{2}(7+70)=385)।

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समान्तर श्रेणी \(10,20,30,\ldots\) के पहले (12) पदों का योग कितना है?

What is the sum of the first (12) terms of the AP \(10,20,30,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (780)

Step 1

Concept

Here (a=10), (d=10), (n=12). \(S_{12}=6[20+110]=780\).

Step 2

Why this answer is correct

The correct answer is B. (780). Here (a=10), (d=10), (n=12). \(S_{12}=6[20+110]=780\).

Step 3

Exam Tip

यहां (a=10), (d=10), (n=12)। \(S_{12}=6[20+110]=780\)।

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अनुक्रम \(81,72,63,54,\ldots\) का सामान्य अंतर क्या है?

What is the common difference of \(81,72,63,54,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (-9)

Step 1

Concept

Each step subtracts (9), so (d=-9). In exams, keep the difference negative for descending order.

Step 2

Why this answer is correct

The correct answer is B. (-9). Each step subtracts (9), so (d=-9). In exams, keep the difference negative for descending order.

Step 3

Exam Tip

हर कदम पर (9) घट रहा है, इसलिए (d=-9)। परीक्षा में अवरोही क्रम में अंतर ऋणात्मक रखें।

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