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25 results found for "cubes" in Class 10.

समीकरण \(x^2-7x-18=0\) के मूलों के घनों का योग क्या है?

What is the sum of cubes of the roots of \(x^2-7x-18=0\)?

Explanation opens after your attempt
Correct Answer

A. (721)

Step 1

Concept

The sum of roots is (7) and the product is (-18). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=343+378=721).

Step 2

Why this answer is correct

The correct answer is A. (721). The sum of roots is (7) and the product is (-18). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=343+378=721).

Step 3

Exam Tip

मूलों का योग (7) और गुणनफल (-18) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=343+378=721)।

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समीकरण \(x^2-6x-16=0\) के मूलों के घनों का योग क्या है?

What is the sum of cubes of the roots of \(x^2-6x-16=0\)?

Explanation opens after your attempt
Correct Answer

A. (504)

Step 1

Concept

The sum of roots is (6) and the product is (-16). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=216+288=504).

Step 2

Why this answer is correct

The correct answer is A. (504). The sum of roots is (6) and the product is (-16). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=216+288=504).

Step 3

Exam Tip

मूलों का योग (6) और गुणनफल (-16) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=216+288=504)।

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समीकरण \(x^2-5x-14=0\) के मूलों के घनों का योग क्या है?

What is the sum of cubes of the roots of \(x^2-5x-14=0\)?

Explanation opens after your attempt
Correct Answer

A. (335)

Step 1

Concept

The sum of roots is (5) and the product is (-14). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=125+210=335).

Step 2

Why this answer is correct

The correct answer is A. (335). The sum of roots is (5) and the product is (-14). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=125+210=335).

Step 3

Exam Tip

मूलों का योग (5) और गुणनफल (-14) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=125+210=335)।

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समीकरण \(x^2-3x-10=0\) के मूलों के घनों का योग क्या है?

What is the sum of cubes of the roots of \(x^2-3x-10=0\)?

Explanation opens after your attempt
Correct Answer

A. (117)

Step 1

Concept

The sum of roots is (3) and the product is (-10). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=27+90=117).

Step 2

Why this answer is correct

The correct answer is A. (117). The sum of roots is (3) and the product is (-10). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=27+90=117).

Step 3

Exam Tip

मूलों का योग (3) और गुणनफल (-10) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=27+90=117)।

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समीकरण \(x^2-2x-3=0\) के मूलों के घनों का योग क्या है?

What is the sum of cubes of the roots of \(x^2-2x-3=0\)?

Explanation opens after your attempt
Correct Answer

A. (26)

Step 1

Concept

The sum of roots is (2) and the product is (-3). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26).

Step 2

Why this answer is correct

The correct answer is A. (26). The sum of roots is (2) and the product is (-3). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26).

Step 3

Exam Tip

मूलों का योग (2) और गुणनफल (-3) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26)।

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यदि \(540=2^2\times3^3\times5\), तो (540) के ऐसे गुणनखंडों की संख्या कितनी है जो पूर्ण घन हैं?

If \(540=2^2\times3^3\times5\), how many factors of (540) are perfect cubes?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

A cube factor must have exponents that are multiples of (3).

Step 2

Why this answer is correct

For (2), only (0); for (3), (0) or (3); for (5), only (0). Total (=2).

Step 3

Exam Tip

Remember that (0) is also a multiple of (3). चरण 1: पूर्ण घन गुणनखंड में हर अभाज्य घात (3) की गुणज होनी चाहिए। चरण 2: (2) की घात केवल (0), (3) की घात (0) या (3), और (5) की घात केवल (0) हो सकती है। कुल \(1\times2\times1=2\)। चरण 3: घन गुणनखंडों में (0) भी (3) की गुणज माना जाता है।

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अनुक्रम \(1,8,27,64,\ldots\) समांतर श्रेणी है या नहीं?

Is the sequence \(1,8,27,64,\ldots\) an AP?

Explanation opens after your attempt
Correct Answer

D. नहीं, अंतर \(7,19,37,\ldots\) हैंNo, the differences are \(7,19,37,\ldots\)

Step 1

Concept

The consecutive differences are not equal, so it is not an AP. In exams, test constancy of differences, not just the visible pattern.

Step 2

Why this answer is correct

The correct answer is D. नहीं, अंतर \(7,19,37,\ldots\) हैं / No, the differences are \(7,19,37,\ldots\). The consecutive differences are not equal, so it is not an AP. In exams, test constancy of differences, not just the visible pattern.

Step 3

Exam Tip

लगातार अंतर बराबर नहीं हैं, इसलिए यह समांतर श्रेणी नहीं है। परीक्षा में नाम या पैटर्न नहीं, अंतर की स्थिरता जांचें।

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यदि \(y \neq 0\), तो (\dfrac{(x+y)3-(x-y)3}{2y}) का सरल रूप क्या है?

If \(y \neq 0\), what is the simplified form of (\dfrac{(x+y)3-(x-y)3}{2y})?

Explanation opens after your attempt
Correct Answer

A. \(,3x^2+y^2,\)

Step 1

Concept

The numerator difference is (6x-2y+2y-3=2y\(3x^2+y^2\)), so division gives \(3x^2+y^2\). In exams, take out the common factor.

Step 2

Why this answer is correct

The correct answer is A. \(,3x^2+y^2,\). The numerator difference is (6x-2y+2y-3=2y\(3x^2+y^2\)), so division gives \(3x^2+y^2\). In exams, take out the common factor.

Step 3

Exam Tip

ऊपर का अंतर (6x-2y+2y-3=2y\(3x^2+y^2\)) है, इसलिए भाग देने पर \(3x^2+y^2\) मिलता है। परीक्षा में common factor निकालें।

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((x+1)3-(x-1)3) का सरल रूप क्या है?

What is the simplified form of ((x+1)3-(x-1)3)?

Explanation opens after your attempt
Correct Answer

A. \(,6x^2+2,\)

Step 1

Concept

On expansion, ((x+1)3=x-3+3x-2+3x+1) and ((x-1)3=x-3-3x-2+3x-1), so the difference is \(6x^2+2\). In exams, expand cubes carefully.

Step 2

Why this answer is correct

The correct answer is A. \(,6x^2+2,\). On expansion, ((x+1)3=x-3+3x-2+3x+1) and ((x-1)3=x-3-3x-2+3x-1), so the difference is \(6x^2+2\). In exams, expand cubes carefully.

Step 3

Exam Tip

विस्तार करने पर ((x+1)3=x-3+3x-2+3x+1) और ((x-1)3=x-3-3x-2+3x-1), इसलिए अंतर \(6x^2+2\) है। परीक्षा में cube expansion ध्यान से करें।

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(\(8x^3+1\)) को ((2x+1)) से भाग देने पर भागफल क्या है?

What is the quotient when (\(8x^3+1\)) is divided by ((2x+1))?

Explanation opens after your attempt
Correct Answer

A. \(,4x^2-2x+1,\)

Step 1

Concept

Because (8x-3+1=(2x)3+13=(2x+1)\(4x^2-2x+1\)). In exams, remember the identity for sum of cubes.

Step 2

Why this answer is correct

The correct answer is A. \(,4x^2-2x+1,\). Because (8x-3+1=(2x)3+13=(2x+1)\(4x^2-2x+1\)). In exams, remember the identity for sum of cubes.

Step 3

Exam Tip

क्योंकि (8x-3+1=(2x)3+13=(2x+1)\(4x^2-2x+1\))। परीक्षा में sum of cubes की identity याद रखें।

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((x-2)\(x^2+2x+4\)) का विस्तार क्या है?

What is the expansion of ((x-2)\(x^2+2x+4\))?

Explanation opens after your attempt
Correct Answer

A. \(,x^3-8,\)

Step 1

Concept

This matches ((a-b)\(a^2+ab+b^2\)=a-3-b-3), so the answer is \(x^3-8\). In exams, identifying the identity makes expansion faster.

Step 2

Why this answer is correct

The correct answer is A. \(,x^3-8,\). This matches ((a-b)\(a^2+ab+b^2\)=a-3-b-3), so the answer is \(x^3-8\). In exams, identifying the identity makes expansion faster.

Step 3

Exam Tip

यह ((a-b)\(a^2+ab+b^2\)=a-3-b-3) का रूप है, इसलिए उत्तर \(x^3-8\) है। परीक्षा में identity पहचानने से विस्तार जल्दी होता है।

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(\(x^3-27\)) को ((x-3)) से भाग देने पर भागफल क्या होगा?

What is the quotient when (\(x^3-27\)) is divided by ((x-3))?

Explanation opens after your attempt
Correct Answer

A. \(,x^2+3x+9,\)

Step 1

Concept

Because (x-3-27=(x-3)\(x^2+3x+9\)), the quotient is \(x^2+3x+9\). In exams, identify the difference of cubes.

Step 2

Why this answer is correct

The correct answer is A. \(,x^2+3x+9,\). Because (x-3-27=(x-3)\(x^2+3x+9\)), the quotient is \(x^2+3x+9\). In exams, identify the difference of cubes.

Step 3

Exam Tip

क्योंकि (x-3-27=(x-3)\(x^2+3x+9\)), इसलिए भागफल \(x^2+3x+9\) है। परीक्षा में घन के अंतर की पहचान करें।

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(\(x^3-8\)) को ((x-2)) से भाग देने पर भागफल क्या होगा?

What is the quotient when (\(x^3-8\)) is divided by ((x-2))?

Explanation opens after your attempt
Correct Answer

A. \(,x^2+2x+4,\)

Step 1

Concept

Because (x-3-8=(x-2)\(x^2+2x+4\)), the quotient is \(x^2+2x+4\). In exams, remember the identity for cubes.

Step 2

Why this answer is correct

The correct answer is A. \(,x^2+2x+4,\). Because (x-3-8=(x-2)\(x^2+2x+4\)), the quotient is \(x^2+2x+4\). In exams, remember the identity for cubes.

Step 3

Exam Tip

क्योंकि (x-3-8=(x-2)\(x^2+2x+4\)), इसलिए भागफल \(x^2+2x+4\) है। परीक्षा में cubes की identity याद रखें।

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यदि \(x^2-10x+21=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\alpha^3+\beta^3\) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-10x+21=0\), what is the value of \(\alpha^3+\beta^3\)?

Explanation opens after your attempt
Correct Answer

A. (370)

Step 1

Concept

\(\alpha+\beta=10\) and \(\alpha\beta=21\). (\alpha-3+\beta-3=103-3(21)(10)=370).

Step 2

Why this answer is correct

The correct answer is A. (370). \(\alpha+\beta=10\) and \(\alpha\beta=21\). (\alpha-3+\beta-3=103-3(21)(10)=370).

Step 3

Exam Tip

\(\alpha+\beta=10\) और \(\alpha\beta=21\) है। (\alpha-3+\beta-3=103-3(21)(10)=370) होगा।

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यदि \(x^2-9x+20=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\alpha^3+\beta^3\) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-9x+20=0\), what is the value of \(\alpha^3+\beta^3\)?

Explanation opens after your attempt
Correct Answer

A. (369)

Step 1

Concept

\(\alpha+\beta=9\) and \(\alpha\beta=20\). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=729-540=189).

Step 2

Why this answer is correct

The correct answer is A. (369). \(\alpha+\beta=9\) and \(\alpha\beta=20\). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=729-540=189).

Step 3

Exam Tip

\(\alpha+\beta=9\) और \(\alpha\beta=20\) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=729-540=189) नहीं बल्कि (189) होगा।

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कौन सा विकल्प \(\sqrt[3]{20}\) के बारे में सही है?

Which option is correct about \(\sqrt[3]{20}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(20) is not a perfect cube so \(\sqrt[3]{20}\) is irrational. Identify perfect cubes in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (20) is not a perfect cube so \(\sqrt[3]{20}\) is irrational. Identify perfect cubes in cube roots.

Step 3

Exam Tip

(20) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{20}\) अपरिमेय है। घनमूल में पूर्ण घन पहचानें।

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कौन सा विकल्प \(\sqrt[3]{12}\) के लिए सही है?

Which option is correct for \(\sqrt[3]{12}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(12) is not a perfect cube so \(\sqrt[3]{12}\) is irrational. Check perfect cubes in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (12) is not a perfect cube so \(\sqrt[3]{12}\) is irrational. Check perfect cubes in cube roots.

Step 3

Exam Tip

(12) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{12}\) अपरिमेय है। घनमूल में पूर्ण घन देखें।

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कौन सा विकल्प \(\sqrt[3]{16}\) के लिए सही है?

Which option is correct for \(\sqrt[3]{16}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(16) is not a perfect cube so its cube root is irrational. Identify perfect cubes in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (16) is not a perfect cube so its cube root is irrational. Identify perfect cubes in cube roots.

Step 3

Exam Tip

(16) पूर्ण घन नहीं है इसलिए इसकी घनमूल अपरिमेय है। घनमूल में पूर्ण घन पहचानें।

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\(\sqrt[3]{9}\) के बारे में सही कथन कौन सा है?

Which statement is correct about \(\sqrt[3]{9}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(9) is not a perfect cube so \(\sqrt[3]{9}\) is irrational. Identifying perfect cubes is important in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (9) is not a perfect cube so \(\sqrt[3]{9}\) is irrational. Identifying perfect cubes is important in cube roots.

Step 3

Exam Tip

(9) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{9}\) अपरिमेय है। घनमूल में पूर्ण घन पहचानना जरूरी है।

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\(\sqrt[3]{4}\) के बारे में कौन सा कथन सही है?

Which statement is correct about \(\sqrt[3]{4}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(4) is not a perfect cube so \(\sqrt[3]{4}\) is irrational. Identify perfect cubes in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (4) is not a perfect cube so \(\sqrt[3]{4}\) is irrational. Identify perfect cubes in cube roots.

Step 3

Exam Tip

(4) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{4}\) अपरिमेय है। घनमूल में पूर्ण घन पहचानें।

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(729) के अभाज्य गुणनखंडन में (3) की घात कितनी है?

What is the exponent of (3) in the prime factorisation of (729)?

Explanation opens after your attempt
Correct Answer

C. 6

Step 1

Concept

\(729=27 \times 27\).

Step 2

Why this answer is correct

Since \(27=3^3\), \(729=3^3 \times 3^3=3^6\).

Step 3

Exam Tip

For larger powers, split the number into familiar cubes. चरण 1: \(729=27 \times 27\) है। चरण 2: \(27=3^3\), इसलिए \(729=3^3 \times 3^3=3^6\)। चरण 3: बड़ी घातों के लिए संख्या को पहचाने हुए घनों में तोड़ें।

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कौन सा विकल्प (675) का सही अभाज्य गुणनखंडन है?

Which option is the correct prime factorisation of (675)?

Explanation opens after your attempt
Correct Answer

B. \(3^3 \times 5^2\)

Step 1

Concept

Write (675) as \(27 \times 25\).

Step 2

Why this answer is correct

\(27=3^3\) and \(25=5^2\), so \(675=3^3 \times 5^2\).

Step 3

Exam Tip

Splitting a number into familiar squares and cubes is a good method. चरण 1: (675) को \(27 \times 25\) लिखें। चरण 2: \(27=3^3\) और \(25=5^2\), इसलिए \(675=3^3 \times 5^2\)। चरण 3: संख्या को आसान वर्ग और घन में तोड़ना अच्छा तरीका है।

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AI Video Prompt 16:9 + 9:16

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कौन सा विकल्प (432) का सही अभाज्य गुणनखंडन है?

Which option is the correct prime factorisation of (432)?

Explanation opens after your attempt
Correct Answer

B. \(2^4 \times 3^3\)

Step 1

Concept

Write (432) as \(16 \times 27\).

Step 2

Why this answer is correct

\(16=2^4\) and \(27=3^3\), so \(432=2^4 \times 3^3\).

Step 3

Exam Tip

Recognising squares and cubes makes factorisation faster. चरण 1: (432) को \(16 \times 27\) लिखें। चरण 2: \(16=2^4\) और \(27=3^3\), इसलिए \(432=2^4 \times 3^3\)। चरण 3: वर्ग और घन संख्याएं पहचानना अभाज्य गुणनखंडन को तेज बनाता है।

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AI Video Prompt 16:9 + 9:16

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किस विकल्प में (72) का अभाज्य गुणनखंडन सही रूप में दिया गया है?

Which option gives the prime factorisation of (72) correctly?

Explanation opens after your attempt
Correct Answer

A. \(2^3 \times 3^2\)

Step 1

Concept

Write \(72=8 \times 9\).

Step 2

Why this answer is correct

\(8=2^3\) and \(9=3^2\), so \(72=2^3 \times 3^2\).

Step 3

Exam Tip

Recognising simple squares and cubes speeds up factorisation. चरण 1: \(72=8 \times 9\) लिखें। चरण 2: \(8=2^3\) और \(9=3^2\), इसलिए \(72=2^3 \times 3^2\)। चरण 3: आसान वर्ग और घन पहचानना गुणनखंडन को तेज बनाता है।

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AI Video Prompt 16:9 + 9:16

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यदि \(N=2^6 \times 3^2\) है, तो (N) को पूर्ण घन बनाने के लिए कम से कम किससे गुणा करना होगा?

If \(N=2^6 \times 3^2\), by the least number should (N) be multiplied to make it a perfect cube?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

In a perfect cube, every prime exponent must be a multiple of (3).

Step 2

Why this answer is correct

\(2^6\) is fine, but \(3^2\) needs one more (3) to become \(3^3\).

Step 3

Exam Tip

For cubes, make exponents multiples of (3). चरण 1: पूर्ण घन में हर अभाज्य की घात (3) की गुणज होनी चाहिए। चरण 2: \(2^6\) ठीक है क्योंकि (6), (3) की गुणज है; \(3^2\) को \(3^3\) बनाने के लिए एक (3) और चाहिए। चरण 3: पूर्ण घन के लिए घातों को (3,6,9) जैसे गुणज बनाएं।

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AI Video Prompt 16:9 + 9:16

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