समीकरण \(x^2-2x-3=0\) के मूलों के घनों का योग क्या है?

What is the sum of cubes of the roots of \(x^2-2x-3=0\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (26)

Step 1

Concept

The sum of roots is (2) and the product is (-3). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26).

Step 2

Why this answer is correct

The correct answer is A. (26). The sum of roots is (2) and the product is (-3). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26).

Step 3

Exam Tip

मूलों का योग (2) और गुणनफल (-3) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26)।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2-2x-3=0\) के मूलों के घनों का योग क्या है? / What is the sum of cubes of the roots of \(x^2-2x-3=0\)?

Correct Answer: A. (26). Explanation: मूलों का योग (2) और गुणनफल (-3) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26)। / The sum of roots is (2) and the product is (-3). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26).

Which concept should I revise for this Mathematics MCQ?

The sum of roots is (2) and the product is (-3). (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26).

What exam hint can help solve this Mathematics question?

मूलों का योग (2) और गुणनफल (-3) है। (\alpha-3+\beta-3=\(\alpha+\beta\)3-3\alpha\beta\(\alpha+\beta\)=8+18=26)।