Class 9 Mathematics Hard Quiz

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\(3x^2-5x+7\) में \(x^2\) का गुणांक क्या है?

What is the coefficient of \(x^2\) in \(3x^2-5x+7\)?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

The number attached to \(x^2\) is (3). In exams, identify a coefficient from the numerical part attached to the term.

Step 2

Why this answer is correct

The correct answer is A. (3). The number attached to \(x^2\) is (3). In exams, identify a coefficient from the numerical part attached to the term.

Step 3

Exam Tip

\(x^2\) के साथ लगा संख्या (3) है। परीक्षा में पद का गुणांक उसके साथ लगे संख्यात्मक भाग से पहचानें।

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\(5x-2x^2+9\) को मानक रूप में लिखने पर कौन-सा रूप मिलेगा?

When \(5x-2x^2+9\) is written in standard form, which form is obtained?

Explanation opens after your attempt
Correct Answer

A. \(-2x^2+5x+9\)

Step 1

Concept

In standard form, write the \(x^2\) term, then the (x) term, then the constant. In exams, follow descending powers.

Step 2

Why this answer is correct

The correct answer is A. \(-2x^2+5x+9\). In standard form, write the \(x^2\) term, then the (x) term, then the constant. In exams, follow descending powers.

Step 3

Exam Tip

मानक रूप में \(x^2\), फिर (x), फिर स्थिर पद लिखा जाता है। परीक्षा में घटते घात क्रम का ध्यान रखें।

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\(2x^2+3x-4\) में (x=2) रखने पर मान क्या होगा?

What is the value of \(2x^2+3x-4\) when (x=2)?

Explanation opens after your attempt
Correct Answer

B. (10)

Step 1

Concept

(2(2)2+3(2)-4=8+6-4=10). In exams, calculate the square first.

Step 2

Why this answer is correct

The correct answer is B. (10). (2(2)2+3(2)-4=8+6-4=10). In exams, calculate the square first.

Step 3

Exam Tip

(2(2)2+3(2)-4=8+6-4=10) है। परीक्षा में पहले वर्ग का मान निकालें।

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\(x^2-6x+9\) को पूर्ण वर्ग के रूप में कैसे लिखा जाएगा?

How will \(x^2-6x+9\) be written as a perfect square?

Explanation opens after your attempt
Correct Answer

A. ((x-3)2)

Step 1

Concept

\(9=3^2\) and \(-6x=-2\cdot x\cdot3\). In exams, keep the sign of the middle term correct.

Step 2

Why this answer is correct

The correct answer is A. ((x-3)2). \(9=3^2\) and \(-6x=-2\cdot x\cdot3\). In exams, keep the sign of the middle term correct.

Step 3

Exam Tip

\(9=3^2\) और \(-6x=-2\cdot x\cdot3\) है। परीक्षा में मध्य पद का चिन्ह सही रखें।

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\(4x^2+12x+9\) का सही पूर्ण वर्ग रूप क्या है?

What is the correct perfect square form of \(4x^2+12x+9\)?

Explanation opens after your attempt
Correct Answer

A. ((2x+3)2)

Step 1

Concept

(4x-2=(2x)2) and \(9=3^2\). In exams, confirm using the middle term \(2\cdot2x\cdot3\).

Step 2

Why this answer is correct

The correct answer is A. ((2x+3)2). (4x-2=(2x)2) and \(9=3^2\). In exams, confirm using the middle term \(2\cdot2x\cdot3\).

Step 3

Exam Tip

(4x-2=(2x)2) और \(9=3^2\) है। परीक्षा में मध्य पद \(2\cdot2x\cdot3\) से पुष्टि करें।

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\(9x^2-24x+16\) को पूर्ण वर्ग में बदलने पर क्या मिलेगा?

What is obtained when \(9x^2-24x+16\) is changed into a perfect square?

Explanation opens after your attempt
Correct Answer

B. ((3x-4)2)

Step 1

Concept

(9x-2=(3x)2), \(16=4^2\), and the middle term is negative. In exams, identify ((a-b)2).

Step 2

Why this answer is correct

The correct answer is B. ((3x-4)2). (9x-2=(3x)2), \(16=4^2\), and the middle term is negative. In exams, identify ((a-b)2).

Step 3

Exam Tip

(9x-2=(3x)2), \(16=4^2\) और मध्य पद ऋणात्मक है। परीक्षा में ((a-b)2) पहचानें।

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\(x^2+7x+12\) में मध्य पद विभाजन के लिए कौन-सी जोड़ी सही है?

For splitting the middle term in \(x^2+7x+12\), which pair is correct?

Explanation opens after your attempt
Correct Answer

A. (3x) और (4x)(3x) and (4x)

Step 1

Concept

(3+4=7) and \(3\cdot4=12\). In exams, check both sum and product.

Step 2

Why this answer is correct

The correct answer is A. (3x) और (4x) / (3x) and (4x). (3+4=7) and \(3\cdot4=12\). In exams, check both sum and product.

Step 3

Exam Tip

(3+4=7) और \(3\cdot4=12\) है। परीक्षा में योग और गुणनफल दोनों जाँचें।

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\(x^2-9x+20\) के मध्य पद के लिए सही विभाजन क्या है?

What is the correct split of the middle term for \(x^2-9x+20\)?

Explanation opens after your attempt
Correct Answer

A. (-4x) और (-5x)(-4x) and (-5x)

Step 1

Concept

(-4-5=-9) and ((-4)(-5)=20). In exams, when constant is positive and middle term is negative, use two negative signs.

Step 2

Why this answer is correct

The correct answer is A. (-4x) और (-5x) / (-4x) and (-5x). (-4-5=-9) and ((-4)(-5)=20). In exams, when constant is positive and middle term is negative, use two negative signs.

Step 3

Exam Tip

(-4-5=-9) और ((-4)(-5)=20) है। परीक्षा में धनात्मक स्थिर पद और ऋणात्मक मध्य पद पर दोनों चिह्न ऋण रखें।

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\(x^2+2x-15\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2+2x-15\)?

Explanation opens after your attempt
Correct Answer

A. ((x+5)(x-3))

Step 1

Concept

(5-3=2) and (5\cdot(-3)=-15). In exams, use opposite signs for a negative constant term.

Step 2

Why this answer is correct

The correct answer is A. ((x+5)(x-3)). (5-3=2) and (5\cdot(-3)=-15). In exams, use opposite signs for a negative constant term.

Step 3

Exam Tip

(5-3=2) और (5\cdot(-3)=-15) है। परीक्षा में ऋणात्मक स्थिर पद पर विपरीत चिह्न लें।

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\(x^2-4x-21\) को गुणनखंडों में लिखिए।

Write \(x^2-4x-21\) in factors.

Explanation opens after your attempt
Correct Answer

A. ((x-7)(x+3))

Step 1

Concept

(-7+3=-4) and ((-7)(3)=-21). In exams, keep the larger factor's sign like the middle term.

Step 2

Why this answer is correct

The correct answer is A. ((x-7)(x+3)). (-7+3=-4) and ((-7)(3)=-21). In exams, keep the larger factor's sign like the middle term.

Step 3

Exam Tip

(-7+3=-4) और ((-7)(3)=-21) है। परीक्षा में बड़े गुणनखंड का चिह्न मध्य पद जैसा रखें।

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\(2x^2+5x+3\) का सही गुणनखंड कौन-सा है?

Which is the correct factorisation of \(2x^2+5x+3\)?

Explanation opens after your attempt
Correct Answer

A. ((2x+3)(x+1))

Step 1

Concept

Expanding gives \(2x^2+2x+3x+3=2x^2+5x+3\). In exams, verify options by multiplication.

Step 2

Why this answer is correct

The correct answer is A. ((2x+3)(x+1)). Expanding gives \(2x^2+2x+3x+3=2x^2+5x+3\). In exams, verify options by multiplication.

Step 3

Exam Tip

विस्तार करने पर \(2x^2+2x+3x+3=2x^2+5x+3\) मिलता है। परीक्षा में गुणा करके विकल्प जाँचें।

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\(3x^2+14x+8\) का गुणनखंड रूप चुनिए।

Choose the factorised form of \(3x^2+14x+8\).

Explanation opens after your attempt
Correct Answer

A. ((3x+2)(x+4))

Step 1

Concept

((3x+2)(x+4)) gives \(3x^2+12x+2x+8\). In exams, check the sum of middle terms.

Step 2

Why this answer is correct

The correct answer is A. ((3x+2)(x+4)). ((3x+2)(x+4)) gives \(3x^2+12x+2x+8\). In exams, check the sum of middle terms.

Step 3

Exam Tip

((3x+2)(x+4)) से \(3x^2+12x+2x+8\) मिलता है। परीक्षा में मध्य पदों का योग देखें।

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\(2x^2-7x+6\) का सही गुणनखंड क्या है?

What is the correct factorisation of \(2x^2-7x+6\)?

Explanation opens after your attempt
Correct Answer

A. ((2x-3)(x-2))

Step 1

Concept

((2x-3)(x-2)) gives \(2x^2-4x-3x+6\). In exams, add both negative middle terms.

Step 2

Why this answer is correct

The correct answer is A. ((2x-3)(x-2)). ((2x-3)(x-2)) gives \(2x^2-4x-3x+6\). In exams, add both negative middle terms.

Step 3

Exam Tip

((2x-3)(x-2)) से \(2x^2-4x-3x+6\) मिलता है। परीक्षा में दोनों ऋणात्मक मध्य पद जोड़ें।

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\(5x^2-13x+6\) के गुणनखंड कौन-से होंगे?

What will be the factors of \(5x^2-13x+6\)?

Explanation opens after your attempt
Correct Answer

A. ((5x-3)(x-2))

Step 1

Concept

((5x-3)(x-2)) gives \(5x^2-10x-3x+6\). In exams, confirm the middle term (-13x).

Step 2

Why this answer is correct

The correct answer is A. ((5x-3)(x-2)). ((5x-3)(x-2)) gives \(5x^2-10x-3x+6\). In exams, confirm the middle term (-13x).

Step 3

Exam Tip

((5x-3)(x-2)) से \(5x^2-10x-3x+6\) मिलता है। परीक्षा में मध्य पद (-13x) की पुष्टि करें।

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\(6x^2+x-2\) को गुणनखंडित कीजिए।

Factorise \(6x^2+x-2\).

Explanation opens after your attempt
Correct Answer

A. ((3x+2)(2x-1))

Step 1

Concept

((3x+2)(2x-1)) gives \(6x^2-3x+4x-2\). In exams, add middle terms with opposite signs.

Step 2

Why this answer is correct

The correct answer is A. ((3x+2)(2x-1)). ((3x+2)(2x-1)) gives \(6x^2-3x+4x-2\). In exams, add middle terms with opposite signs.

Step 3

Exam Tip

((3x+2)(2x-1)) से \(6x^2-3x+4x-2\) मिलता है। परीक्षा में विपरीत चिह्न वाले मध्य पद जोड़ें।

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\(x^2+px+24\) में यदि एक गुणनखंड (x+6) है, तो (p) का मान क्या होगा?

In \(x^2+px+24\), if one factor is (x+6), what is the value of (p)?

Explanation opens after your attempt
Correct Answer

A. (10)

Step 1

Concept

The other factor is (x+4) because \(6\cdot4=24\), so (p=6+4=10). In exams, find the other factor from the constant term.

Step 2

Why this answer is correct

The correct answer is A. (10). The other factor is (x+4) because \(6\cdot4=24\), so (p=6+4=10). In exams, find the other factor from the constant term.

Step 3

Exam Tip

दूसरा गुणनखंड (x+4) होगा क्योंकि \(6\cdot4=24\), इसलिए (p=6+4=10)। परीक्षा में स्थिर पद से दूसरा गुणनखंड खोजें।

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\(x^2+kx+36\) को ((x+4)(x+9)) के बराबर बनाया गया है। (k) का मान क्या है?

\(x^2+kx+36\) is made equal to ((x+4)(x+9)). What is the value of (k)?

Explanation opens after your attempt
Correct Answer

A. (13)

Step 1

Concept

((x+4)(x+9)=x-2+13x+36). In exams, add the constant parts of the factors.

Step 2

Why this answer is correct

The correct answer is A. (13). ((x+4)(x+9)=x-2+13x+36). In exams, add the constant parts of the factors.

Step 3

Exam Tip

((x+4)(x+9)=x-2+13x+36) है। परीक्षा में गुणनखंडों के स्थिर भाग जोड़ें।

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\(x^2-11x+k\) के गुणनखंड (x-5) और (x-6) हैं। (k) का मान क्या होगा?

The factors of \(x^2-11x+k\) are (x-5) and (x-6). What will be the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (30)

Step 1

Concept

The constant term is ((-5)(-6)=30). In exams, multiply the constant parts of the factors.

Step 2

Why this answer is correct

The correct answer is B. (30). The constant term is ((-5)(-6)=30). In exams, multiply the constant parts of the factors.

Step 3

Exam Tip

स्थिर पद ((-5)(-6)=30) है। परीक्षा में गुणनखंडों के स्थिर भागों का गुणन करें।

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\(x^2+8x+c\) को पूर्ण वर्ग बनाने के लिए (c) का मान क्या होना चाहिए?

What should be the value of (c) to make \(x^2+8x+c\) a perfect square?

Explanation opens after your attempt
Correct Answer

B. (16)

Step 1

Concept

Half of (8) is (4), and \(4^2=16\). In exams, square half of the middle coefficient.

Step 2

Why this answer is correct

The correct answer is B. (16). Half of (8) is (4), and \(4^2=16\). In exams, square half of the middle coefficient.

Step 3

Exam Tip

(8) का आधा (4) है और \(4^2=16\) है। परीक्षा में मध्य पद के आधे का वर्ग लें।

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\(x^2-14x+c\) पूर्ण वर्ग हो, तो (c) का मान क्या होगा?

If \(x^2-14x+c\) is a perfect square, what will be the value of (c)?

Explanation opens after your attempt
Correct Answer

A. (49)

Step 1

Concept

Half of (-14) is (-7), and ((-7)2=49). In exams, even if the sign is negative, the square is positive.

Step 2

Why this answer is correct

The correct answer is A. (49). Half of (-14) is (-7), and ((-7)2=49). In exams, even if the sign is negative, the square is positive.

Step 3

Exam Tip

(-14) का आधा (-7) है और ((-7)2=49) है। परीक्षा में चिह्न चाहे ऋण हो, वर्ग धनात्मक होता है।

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\(9x^2-mx+16\) पूर्ण वर्ग है। (m) का मान क्या होगा?

\(9x^2-mx+16\) is a perfect square. What will be the value of (m)?

Explanation opens after your attempt
Correct Answer

C. (24)

Step 1

Concept

(9x-2=(3x)2) and \(16=4^2\), so the middle coefficient is \(2\cdot3\cdot4=24\). In exams, view the negative sign and coefficient separately.

Step 2

Why this answer is correct

The correct answer is C. (24). (9x-2=(3x)2) and \(16=4^2\), so the middle coefficient is \(2\cdot3\cdot4=24\). In exams, view the negative sign and coefficient separately.

Step 3

Exam Tip

(9x-2=(3x)2) और \(16=4^2\), इसलिए मध्य गुणांक \(2\cdot3\cdot4=24\) है। परीक्षा में ऋण चिन्ह अलग और गुणांक अलग देखें।

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\(2x^2+7x+5\) में (x=1) रखने पर मान क्या होगा?

What is the value of \(2x^2+7x+5\) when (x=1)?

Explanation opens after your attempt
Correct Answer

B. (14)

Step 1

Concept

(2(1)2+7(1)+5=14). In exams, when substituting (1), all terms add directly.

Step 2

Why this answer is correct

The correct answer is B. (14). (2(1)2+7(1)+5=14). In exams, when substituting (1), all terms add directly.

Step 3

Exam Tip

(2(1)2+7(1)+5=14) है। परीक्षा में (1) रखने पर सभी पद सीधे जुड़ते हैं।

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\(3x^2-2x-8\) में (x=-1) रखने पर मान क्या होगा?

What is the value of \(3x^2-2x-8\) when (x=-1)?

Explanation opens after your attempt
Correct Answer

A. (-3)

Step 1

Concept

(3(-1)2-2(-1)-8=3+2-8=-3). In exams, the square of a negative number is positive.

Step 2

Why this answer is correct

The correct answer is A. (-3). (3(-1)2-2(-1)-8=3+2-8=-3). In exams, the square of a negative number is positive.

Step 3

Exam Tip

(3(-1)2-2(-1)-8=3+2-8=-3) है। परीक्षा में ऋण संख्या का वर्ग धनात्मक होता है।

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\(x^2-5x+6\) का मान (x=2) पर क्या होगा?

What is the value of \(x^2-5x+6\) at (x=2)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

\(2^2-5\cdot2+6=4-10+6=0\). In exams, do square, multiplication, and addition in order.

Step 2

Why this answer is correct

The correct answer is A. (0). \(2^2-5\cdot2+6=4-10+6=0\). In exams, do square, multiplication, and addition in order.

Step 3

Exam Tip

\(2^2-5\cdot2+6=4-10+6=0\) है। परीक्षा में क्रम से वर्ग, गुणन और जोड़ करें।

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\(x^2+ax+18\) में यदि दो स्थिर गुणनखंड (3) और (6) हैं, तो (a) क्या है?

In \(x^2+ax+18\), if the two constant factors are (3) and (6), what is (a)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

The middle coefficient will be (3+6=9). In exams, identify the form (x-2+(p+q)x+pq).

Step 2

Why this answer is correct

The correct answer is A. (9). The middle coefficient will be (3+6=9). In exams, identify the form (x-2+(p+q)x+pq).

Step 3

Exam Tip

मध्य गुणांक (3+6=9) होगा। परीक्षा में (x-2+(p+q)x+pq) का रूप पहचानें।

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\(x^2+bx-28\) के गुणनखंड (x+7) और (x-4) हैं। (b) का मान क्या है?

The factors of \(x^2+bx-28\) are (x+7) and (x-4). What is the value of (b)?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

((x+7)(x-4)=x-2+3x-28). In exams, the middle coefficient comes from the sum of constant parts.

Step 2

Why this answer is correct

The correct answer is A. (3). ((x+7)(x-4)=x-2+3x-28). In exams, the middle coefficient comes from the sum of constant parts.

Step 3

Exam Tip

((x+7)(x-4)=x-2+3x-28) है। परीक्षा में मध्य गुणांक स्थिर भागों के योग से मिलता है।

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\(2x^2+kx+12\) में यदि गुणनखंड ((2x+3)(x+4)) हैं, तो (k) क्या होगा?

In \(2x^2+kx+12\), if the factors are ((2x+3)(x+4)), what is (k)?

Explanation opens after your attempt
Correct Answer

B. (11)

Step 1

Concept

Expansion gives \(2x^2+8x+3x+12=2x^2+11x+12\). In exams, add the cross terms.

Step 2

Why this answer is correct

The correct answer is B. (11). Expansion gives \(2x^2+8x+3x+12=2x^2+11x+12\). In exams, add the cross terms.

Step 3

Exam Tip

विस्तार से \(2x^2+8x+3x+12=2x^2+11x+12\) मिलता है। परीक्षा में क्रॉस पद जोड़ें।

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कौन-सा द्विघात व्यंजक पूर्ण वर्ग नहीं है?

Which quadratic expression is not a perfect square?

Explanation opens after your attempt
Correct Answer

D. \(x^2+8x+18\)

Step 1

Concept

For \(x^2+8x+18\), the constant should be (16) for a perfect square. In exams, check the square of half the middle coefficient.

Step 2

Why this answer is correct

The correct answer is D. \(x^2+8x+18\). For \(x^2+8x+18\), the constant should be (16) for a perfect square. In exams, check the square of half the middle coefficient.

Step 3

Exam Tip

\(x^2+8x+18\) में पूर्ण वर्ग के लिए स्थिर पद (16) चाहिए था। परीक्षा में आधे मध्य गुणांक का वर्ग जाँचें।

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\(x^2+4x+4\) और \(x^2-4\) में क्या संबंध है?

What is the relation between \(x^2+4x+4\) and \(x^2-4\)?

Explanation opens after your attempt
Correct Answer

A. पहला पूर्ण वर्ग है और दूसरा वर्गों का अंतर हैFirst is a perfect square and second is difference of squares

Step 1

Concept

(x-2+4x+4=(x+2)2) and (x-2-4=(x-2)(x+2)). In exams, check signs and the middle term.

Step 2

Why this answer is correct

The correct answer is A. पहला पूर्ण वर्ग है और दूसरा वर्गों का अंतर है / First is a perfect square and second is difference of squares. (x-2+4x+4=(x+2)2) and (x-2-4=(x-2)(x+2)). In exams, check signs and the middle term.

Step 3

Exam Tip

(x-2+4x+4=(x+2)2) और (x-2-4=(x-2)(x+2)) है। परीक्षा में चिन्ह और मध्य पद देखें।

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\(x^2+6x+5\) को ((x+3)2) से तुलना करने पर कितना अंतर है?

When \(x^2+6x+5\) is compared with ((x+3)2), what is the difference?

Explanation opens after your attempt
Correct Answer

A. (1) कम(1) less

Step 1

Concept

((x+3)2=x-2+6x+9), so the given expression is not (1) less but (4) less. The correct comparison should be (4) less.

Step 2

Why this answer is correct

The correct answer is A. (1) कम / (1) less. ((x+3)2=x-2+6x+9), so the given expression is not (1) less but (4) less. The correct comparison should be (4) less.

Step 3

Exam Tip

((x+3)2=x-2+6x+9) है, इसलिए दिया व्यंजक (4) नहीं बल्कि (1) नहीं, (4) कम है। सही तुलना (4) कम होनी चाहिए।

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\(x^2+6x+5\) को पूर्ण वर्ग पूरा करने के लिए कौन-सा पद जोड़ना होगा?

Which term must be added to complete the square for \(x^2+6x+5\)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

To make \(x^2+6x\) a perfect square, (9) is needed, and (5) is already present, so add (4). In exams, square half the middle coefficient.

Step 2

Why this answer is correct

The correct answer is B. (4). To make \(x^2+6x\) a perfect square, (9) is needed, and (5) is already present, so add (4). In exams, square half the middle coefficient.

Step 3

Exam Tip

\(x^2+6x\) को पूर्ण वर्ग बनाने के लिए (9) चाहिए और (5) पहले है, इसलिए (4) जोड़ना होगा। परीक्षा में आधे मध्य गुणांक का वर्ग लें।

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\(x^2-8x+10\) को पूर्ण वर्ग पूरा करने के लिए कितना जोड़ना होगा?

How much must be added to \(x^2-8x+10\) to complete the square?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

For \(x^2-8x\), the perfect square constant should be (16), so add (16-10=6). In exams, subtract the current constant.

Step 2

Why this answer is correct

The correct answer is A. (6). For \(x^2-8x\), the perfect square constant should be (16), so add (16-10=6). In exams, subtract the current constant.

Step 3

Exam Tip

\(x^2-8x\) के लिए पूर्ण वर्ग स्थिर पद (16) चाहिए, इसलिए (16-10=6) जोड़ें। परीक्षा में वर्तमान स्थिर पद घटाएँ।

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\(12x^2-18x\) का पूर्ण सामान्य गुणनखंड रूप क्या है?

What is the complete common-factor form of \(12x^2-18x\)?

Explanation opens after your attempt
Correct Answer

A. (6x(2x-3))

Step 1

Concept

The greatest common factor is (6x). In exams, take the common part of both number and variable.

Step 2

Why this answer is correct

The correct answer is A. (6x(2x-3)). The greatest common factor is (6x). In exams, take the common part of both number and variable.

Step 3

Exam Tip

महत्तम सामान्य गुणनखंड (6x) है। परीक्षा में संख्या और चर दोनों का सामान्य भाग लें।

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\(x^2-16\) और \(x^2-8x+16\) के सही रूपों की जोड़ी कौन-सी है?

Which pair of forms is correct for \(x^2-16\) and \(x^2-8x+16\)?

Explanation opens after your attempt
Correct Answer

A. ((x-4)(x+4)) और ((x-4)2)((x-4)(x+4)) and ((x-4)2)

Step 1

Concept

The first is a difference of squares and the second is a perfect square. In exams, identify by the presence of the middle term.

Step 2

Why this answer is correct

The correct answer is A. ((x-4)(x+4)) और ((x-4)2) / ((x-4)(x+4)) and ((x-4)2). The first is a difference of squares and the second is a perfect square. In exams, identify by the presence of the middle term.

Step 3

Exam Tip

पहला वर्गों का अंतर है और दूसरा पूर्ण वर्ग है। परीक्षा में मध्य पद की उपस्थिति से पहचान करें।

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\(x^2+4x+3\) का मान (x=-1) पर क्या होगा?

What is the value of \(x^2+4x+3\) at (x=-1)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

((-1)2+4(-1)+3=1-4+3=0). In exams, be careful with negative numbers.

Step 2

Why this answer is correct

The correct answer is A. (0). ((-1)2+4(-1)+3=1-4+3=0). In exams, be careful with negative numbers.

Step 3

Exam Tip

((-1)2+4(-1)+3=1-4+3=0) है। परीक्षा में ऋण संख्या के साथ सावधानी रखें।

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यदि \(x^2+mx+16\) पूर्ण वर्ग है और (m) ऋणात्मक है, तो (m) क्या होगा?

If \(x^2+mx+16\) is a perfect square and (m) is negative, what is (m)?

Explanation opens after your attempt
Correct Answer

A. (-8)

Step 1

Concept

\(16=4^2\), and the negative middle term is \(-2\cdot x\cdot4=-8x\). In exams, choose the coefficient according to the given sign.

Step 2

Why this answer is correct

The correct answer is A. (-8). \(16=4^2\), and the negative middle term is \(-2\cdot x\cdot4=-8x\). In exams, choose the coefficient according to the given sign.

Step 3

Exam Tip

\(16=4^2\) है और ऋणात्मक मध्य पद \(-2\cdot x\cdot4=-8x\) होगा। परीक्षा में दिए गए चिन्ह के अनुसार गुणांक चुनें।

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\(4x^2+kx+1\) को ((2x+1)2) बनाने के लिए (k) क्या होगा?

What should (k) be to make \(4x^2+kx+1\) equal to ((2x+1)2)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

((2x+1)2=4x-2+4x+1). In exams, check the middle term (2ab).

Step 2

Why this answer is correct

The correct answer is B. (4). ((2x+1)2=4x-2+4x+1). In exams, check the middle term (2ab).

Step 3

Exam Tip

((2x+1)2=4x-2+4x+1) है। परीक्षा में (2ab) वाला मध्य पद देखें।

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\(x^2-2x-24\) के गुणनखंड कौन-से हैं?

What are the factors of \(x^2-2x-24\)?

Explanation opens after your attempt
Correct Answer

A. ((x-6)(x+4))

Step 1

Concept

(-6+4=-2) and ((-6)(4)=-24). In exams, use different signs for a negative constant term.

Step 2

Why this answer is correct

The correct answer is A. ((x-6)(x+4)). (-6+4=-2) and ((-6)(4)=-24). In exams, use different signs for a negative constant term.

Step 3

Exam Tip

(-6+4=-2) और ((-6)(4)=-24) है। परीक्षा में ऋणात्मक स्थिर पद के लिए अलग चिह्न लें।

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\(x^2+13x+42\) के लिए सही गुणनखंड जोड़ी कौन-सी है?

Which is the correct factor pair for \(x^2+13x+42\)?

Explanation opens after your attempt
Correct Answer

A. ((x+6)(x+7))

Step 1

Concept

(6+7=13) and \(6\cdot7=42\). In exams, first check close factor pairs.

Step 2

Why this answer is correct

The correct answer is A. ((x+6)(x+7)). (6+7=13) and \(6\cdot7=42\). In exams, first check close factor pairs.

Step 3

Exam Tip

(6+7=13) और \(6\cdot7=42\) है। परीक्षा में निकट गुणनखंडों की जोड़ी पहले देखें।

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\(x^2-15x+56\) का सही गुणनखंड रूप क्या है?

What is the correct factorised form of \(x^2-15x+56\)?

Explanation opens after your attempt
Correct Answer

A. ((x-7)(x-8))

Step 1

Concept

(-7-8=-15) and ((-7)(-8)=56). In exams, keep both factors negative.

Step 2

Why this answer is correct

The correct answer is A. ((x-7)(x-8)). (-7-8=-15) and ((-7)(-8)=56). In exams, keep both factors negative.

Step 3

Exam Tip

(-7-8=-15) और ((-7)(-8)=56) है। परीक्षा में दोनों गुणनखंड ऋणात्मक रखें।

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\(3x^2+x-10\) का गुणनखंड रूप चुनिए।

Choose the factorised form of \(3x^2+x-10\).

Explanation opens after your attempt
Correct Answer

A. ((3x-5)(x+2))

Step 1

Concept

((3x-5)(x+2)) gives \(3x^2+6x-5x-10\). In exams, check until the middle term becomes (x).

Step 2

Why this answer is correct

The correct answer is A. ((3x-5)(x+2)). ((3x-5)(x+2)) gives \(3x^2+6x-5x-10\). In exams, check until the middle term becomes (x).

Step 3

Exam Tip

((3x-5)(x+2)) से \(3x^2+6x-5x-10\) मिलता है। परीक्षा में मध्य पद (x) बनने तक जाँचें।

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\(4x^2-11x+6\) को गुणनखंडित कीजिए।

Factorise \(4x^2-11x+6\).

Explanation opens after your attempt
Correct Answer

A. ((4x-3)(x-2))

Step 1

Concept

((4x-3)(x-2)) gives \(4x^2-8x-3x+6\). In exams, check the middle term (-11x).

Step 2

Why this answer is correct

The correct answer is A. ((4x-3)(x-2)). ((4x-3)(x-2)) gives \(4x^2-8x-3x+6\). In exams, check the middle term (-11x).

Step 3

Exam Tip

((4x-3)(x-2)) से \(4x^2-8x-3x+6\) मिलता है। परीक्षा में मध्य पद (-11x) जाँचें।

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\(x^2+4x-45\) का सही गुणनखंड कौन-सा है?

Which is the correct factorisation of \(x^2+4x-45\)?

Explanation opens after your attempt
Correct Answer

A. ((x+9)(x-5))

Step 1

Concept

(9-5=4) and (9\cdot(-5)=-45). In exams, keep the larger number's sign like the middle term.

Step 2

Why this answer is correct

The correct answer is A. ((x+9)(x-5)). (9-5=4) and (9\cdot(-5)=-45). In exams, keep the larger number's sign like the middle term.

Step 3

Exam Tip

(9-5=4) और (9\cdot(-5)=-45) है। परीक्षा में बड़ी संख्या का चिह्न मध्य पद जैसा रखें।

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\(x^2-18x+81\) का पूर्ण वर्ग रूप क्या है?

What is the perfect square form of \(x^2-18x+81\)?

Explanation opens after your attempt
Correct Answer

A. ((x-9)2)

Step 1

Concept

\(81=9^2\) and \(-18x=-2\cdot x\cdot9\). In exams, identify the subtraction square from the negative middle term.

Step 2

Why this answer is correct

The correct answer is A. ((x-9)2). \(81=9^2\) and \(-18x=-2\cdot x\cdot9\). In exams, identify the subtraction square from the negative middle term.

Step 3

Exam Tip

\(81=9^2\) और \(-18x=-2\cdot x\cdot9\) है। परीक्षा में ऋण मध्य पद से घटाव वाला वर्ग पहचानें।

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\(16x^2+40x+25\) को किस रूप में लिखा जा सकता है?

In which form can \(16x^2+40x+25\) be written?

Explanation opens after your attempt
Correct Answer

A. ((4x+5)2)

Step 1

Concept

(16x-2=(4x)2), \(25=5^2\), and \(40x=2\cdot4x\cdot5\). In exams, check the square roots of first and last terms.

Step 2

Why this answer is correct

The correct answer is A. ((4x+5)2). (16x-2=(4x)2), \(25=5^2\), and \(40x=2\cdot4x\cdot5\). In exams, check the square roots of first and last terms.

Step 3

Exam Tip

(16x-2=(4x)2), \(25=5^2\) और \(40x=2\cdot4x\cdot5\) है। परीक्षा में पहले और अंतिम पद के वर्गमूल देखें।

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\(x^2+mx+49\) पूर्ण वर्ग है और (m) धनात्मक है। (m) का मान क्या होगा?

\(x^2+mx+49\) is a perfect square and (m) is positive. What will be the value of (m)?

Explanation opens after your attempt
Correct Answer

B. (14)

Step 1

Concept

\(49=7^2\), so the middle term is \(2\cdot x\cdot7=14x\). In exams, take the positive middle coefficient for a positive perfect square.

Step 2

Why this answer is correct

The correct answer is B. (14). \(49=7^2\), so the middle term is \(2\cdot x\cdot7=14x\). In exams, take the positive middle coefficient for a positive perfect square.

Step 3

Exam Tip

\(49=7^2\) है इसलिए मध्य पद \(2\cdot x\cdot7=14x\) होगा। परीक्षा में धनात्मक पूर्ण वर्ग के लिए धनात्मक मध्य गुणांक लें।

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\(2x^2+px+8\) के गुणनखंड ((2x+4)(x+2)) नहीं हो सकते। सही कारण क्या है?

The factors of \(2x^2+px+8\) cannot be ((2x+4)(x+2)). What is the correct reason?

Explanation opens after your attempt
Correct Answer

A. क्योंकि विस्तार में \(2x^2+8x+8\) मिलता हैBecause expansion gives \(2x^2+8x+8\)

Step 1

Concept

Expanding ((2x+4)(x+2)) gives \(2x^2+8x+8\). In exams, verify the option by expansion.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि विस्तार में \(2x^2+8x+8\) मिलता है / Because expansion gives \(2x^2+8x+8\). Expanding ((2x+4)(x+2)) gives \(2x^2+8x+8\). In exams, verify the option by expansion.

Step 3

Exam Tip

((2x+4)(x+2)) फैलाने पर \(2x^2+8x+8\) मिलता है। परीक्षा में विकल्प को विस्तार करके सत्यापित करें।

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\(3x^2+kx+12\) में यदि गुणनखंड ((3x+4)(x+3)) हैं, तो (k) का मान क्या है?

In \(3x^2+kx+12\), if the factors are ((3x+4)(x+3)), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (13)

Step 1

Concept

((3x+4)(x+3)=3x-2+9x+4x+12=3x-2+13x+12). In exams, add the cross terms.

Step 2

Why this answer is correct

The correct answer is C. (13). ((3x+4)(x+3)=3x-2+9x+4x+12=3x-2+13x+12). In exams, add the cross terms.

Step 3

Exam Tip

((3x+4)(x+3)=3x-2+9x+4x+12=3x-2+13x+12) है। परीक्षा में क्रॉस पदों को जोड़ें।

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\(x^2-12x+32\) का सही गुणनखंड रूप क्या है?

What is the correct factorised form of \(x^2-12x+32\)?

Explanation opens after your attempt
Correct Answer

A. ((x-4)(x-8))

Step 1

Concept

(-4-8=-12) and ((-4)(-8)=32). In exams, use both negative signs when the constant is positive and middle term is negative.

Step 2

Why this answer is correct

The correct answer is A. ((x-4)(x-8)). (-4-8=-12) and ((-4)(-8)=32). In exams, use both negative signs when the constant is positive and middle term is negative.

Step 3

Exam Tip

(-4-8=-12) और ((-4)(-8)=32) है। परीक्षा में धनात्मक स्थिर पद और ऋणात्मक मध्य पद पर दोनों चिह्न ऋण रखें।

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\(25x^2+mx+36\) पूर्ण वर्ग है और (m) धनात्मक है। (m) का मान क्या होगा?

\(25x^2+mx+36\) is a perfect square and (m) is positive. What will be the value of (m)?

Explanation opens after your attempt
Correct Answer

B. (60)

Step 1

Concept

(25x-2=(5x)2) and \(36=6^2\), so the middle term is \(2\cdot5x\cdot6=60x\). In exams, multiply twice the two square roots.

Step 2

Why this answer is correct

The correct answer is B. (60). (25x-2=(5x)2) and \(36=6^2\), so the middle term is \(2\cdot5x\cdot6=60x\). In exams, multiply twice the two square roots.

Step 3

Exam Tip

(25x-2=(5x)2) और \(36=6^2\), इसलिए मध्य पद \(2\cdot5x\cdot6=60x\) है। परीक्षा में दोनों वर्गमूलों का दुगुना गुणन करें।

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FAQs

Class 9 Mathematics Quiz FAQs

How many questions are in this quiz?

This level is designed for 50 active questions. Currently 50 questions are available for the selected class and difficulty.

Is there a timer in this quiz?

Yes, the timer uses 30 seconds per question for Hard difficulty and shows the total remaining time on the page.

Can I open each question separately?

Yes, every question has its own SEO-friendly page with answer, explanation and related practice links.