\(3x^2-5x+7\) में \(x^2\) का गुणांक क्या है?
What is the coefficient of \(x^2\) in \(3x^2-5x+7\)?
#quadratic-expressions
#coefficient
#standard-form
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A (3)
B (-5)
C (7)
D (1)
Explanation opens after your attempt
Step 1
Concept
The number attached to \(x^2\) is (3). In exams, identify a coefficient from the numerical part attached to the term.
Step 2
Why this answer is correct
The correct answer is A. (3). The number attached to \(x^2\) is (3). In exams, identify a coefficient from the numerical part attached to the term.
Step 3
Exam Tip
\(x^2\) के साथ लगा संख्या (3) है। परीक्षा में पद का गुणांक उसके साथ लगे संख्यात्मक भाग से पहचानें।
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\(5x-2x^2+9\) को मानक रूप में लिखने पर कौन-सा रूप मिलेगा?
When \(5x-2x^2+9\) is written in standard form, which form is obtained?
#quadratic-expressions
#standard-form
#ordering
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A \(-2x^2+5x+9\)
B \(5x+9-2x^2\)
C \(9+5x-2x^2\)
D \(2x^2+5x+9\)
Explanation opens after your attempt
Correct Answer
A. \(-2x^2+5x+9\)
Step 1
Concept
In standard form, write the \(x^2\) term, then the (x) term, then the constant. In exams, follow descending powers.
Step 2
Why this answer is correct
The correct answer is A. \(-2x^2+5x+9\). In standard form, write the \(x^2\) term, then the (x) term, then the constant. In exams, follow descending powers.
Step 3
Exam Tip
मानक रूप में \(x^2\), फिर (x), फिर स्थिर पद लिखा जाता है। परीक्षा में घटते घात क्रम का ध्यान रखें।
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\(2x^2+3x-4\) में (x=2) रखने पर मान क्या होगा?
What is the value of \(2x^2+3x-4\) when (x=2)?
#quadratic-expressions
#value-substitution
#evaluation
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A (8)
B (10)
C (12)
D (14)
Explanation opens after your attempt
Step 1
Concept
(2(2)2 +3(2)-4=8+6-4=10). In exams, calculate the square first.
Step 2
Why this answer is correct
The correct answer is B. (10). (2(2)2 +3(2)-4=8+6-4=10). In exams, calculate the square first.
Step 3
Exam Tip
(2(2)2 +3(2)-4=8+6-4=10) है। परीक्षा में पहले वर्ग का मान निकालें।
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\(x^2-6x+9\) को पूर्ण वर्ग के रूप में कैसे लिखा जाएगा?
How will \(x^2-6x+9\) be written as a perfect square?
#quadratic-expressions
#perfect-square
#identity
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A ((x-3)2 )
B ((x+3)2 )
C ((x-6)2 )
D ((x-9)2 )
Explanation opens after your attempt
Correct Answer
A. ((x-3)2 )
Step 1
Concept
\(9=3^2\) and \(-6x=-2\cdot x\cdot3\). In exams, keep the sign of the middle term correct.
Step 2
Why this answer is correct
The correct answer is A. ((x-3)2 ). \(9=3^2\) and \(-6x=-2\cdot x\cdot3\). In exams, keep the sign of the middle term correct.
Step 3
Exam Tip
\(9=3^2\) और \(-6x=-2\cdot x\cdot3\) है। परीक्षा में मध्य पद का चिन्ह सही रखें।
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\(4x^2+12x+9\) का सही पूर्ण वर्ग रूप क्या है?
What is the correct perfect square form of \(4x^2+12x+9\)?
#quadratic-expressions
#perfect-square
#coefficient
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A ((2x+3)2 )
B ((4x+3)2 )
C ((2x-3)2 )
D ((x+6)2 )
Explanation opens after your attempt
Correct Answer
A. ((2x+3)2 )
Step 1
Concept
(4x-2 =(2x)2 ) and \(9=3^2\). In exams, confirm using the middle term \(2\cdot2x\cdot3\).
Step 2
Why this answer is correct
The correct answer is A. ((2x+3)2 ). (4x-2 =(2x)2 ) and \(9=3^2\). In exams, confirm using the middle term \(2\cdot2x\cdot3\).
Step 3
Exam Tip
(4x-2 =(2x)2 ) और \(9=3^2\) है। परीक्षा में मध्य पद \(2\cdot2x\cdot3\) से पुष्टि करें।
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\(9x^2-24x+16\) को पूर्ण वर्ग में बदलने पर क्या मिलेगा?
What is obtained when \(9x^2-24x+16\) is changed into a perfect square?
#quadratic-expressions
#negative-middle
#perfect-square
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A ((3x+4)2 )
B ((3x-4)2 )
C ((9x-4)2 )
D ((x-12)2 )
Explanation opens after your attempt
Correct Answer
B. ((3x-4)2 )
Step 1
Concept
(9x-2 =(3x)2 ), \(16=4^2\), and the middle term is negative. In exams, identify ((a-b)2 ).
Step 2
Why this answer is correct
The correct answer is B. ((3x-4)2 ). (9x-2 =(3x)2 ), \(16=4^2\), and the middle term is negative. In exams, identify ((a-b)2 ).
Step 3
Exam Tip
(9x-2 =(3x)2 ), \(16=4^2\) और मध्य पद ऋणात्मक है। परीक्षा में ((a-b)2 ) पहचानें।
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\(x^2+7x+12\) में मध्य पद विभाजन के लिए कौन-सी जोड़ी सही है?
For splitting the middle term in \(x^2+7x+12\), which pair is correct?
#quadratic-expressions
#middle-term-split
#factorisation
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A (3x) और (4x) / (3x) and (4x)
B (2x) और (5x) / (2x) and (5x)
C (6x) और (x) / (6x) and (x)
D (12x) और (-5x) / (12x) and (-5x)
Explanation opens after your attempt
Correct Answer
A. (3x) और (4x) / (3x) and (4x)
Step 1
Concept
(3+4=7) and \(3\cdot4=12\). In exams, check both sum and product.
Step 2
Why this answer is correct
The correct answer is A. (3x) और (4x) / (3x) and (4x). (3+4=7) and \(3\cdot4=12\). In exams, check both sum and product.
Step 3
Exam Tip
(3+4=7) और \(3\cdot4=12\) है। परीक्षा में योग और गुणनफल दोनों जाँचें।
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\(x^2-9x+20\) के मध्य पद के लिए सही विभाजन क्या है?
What is the correct split of the middle term for \(x^2-9x+20\)?
#quadratic-expressions
#negative-middle
#split
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A (-4x) और (-5x) / (-4x) and (-5x)
B (4x) और (5x) / (4x) and (5x)
C (-2x) और (-10x) / (-2x) and (-10x)
D (-1x) और (-20x) / (-1x) and (-20x)
Explanation opens after your attempt
Correct Answer
A. (-4x) और (-5x) / (-4x) and (-5x)
Step 1
Concept
(-4-5=-9) and ((-4)(-5)=20). In exams, when constant is positive and middle term is negative, use two negative signs.
Step 2
Why this answer is correct
The correct answer is A. (-4x) और (-5x) / (-4x) and (-5x). (-4-5=-9) and ((-4)(-5)=20). In exams, when constant is positive and middle term is negative, use two negative signs.
Step 3
Exam Tip
(-4-5=-9) और ((-4)(-5)=20) है। परीक्षा में धनात्मक स्थिर पद और ऋणात्मक मध्य पद पर दोनों चिह्न ऋण रखें।
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\(x^2+2x-15\) का गुणनखंड रूप क्या है?
What is the factorised form of \(x^2+2x-15\)?
#quadratic-expressions
#factorisation
#signed-factors
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A ((x+5)(x-3))
B ((x-5)(x+3))
C ((x+15)(x-1))
D ((x+2)(x-15))
Explanation opens after your attempt
Correct Answer
A. ((x+5)(x-3))
Step 1
Concept
(5-3=2) and (5\cdot(-3)=-15). In exams, use opposite signs for a negative constant term.
Step 2
Why this answer is correct
The correct answer is A. ((x+5)(x-3)). (5-3=2) and (5\cdot(-3)=-15). In exams, use opposite signs for a negative constant term.
Step 3
Exam Tip
(5-3=2) और (5\cdot(-3)=-15) है। परीक्षा में ऋणात्मक स्थिर पद पर विपरीत चिह्न लें।
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\(x^2-4x-21\) को गुणनखंडों में लिखिए।
Write \(x^2-4x-21\) in factors.
#quadratic-expressions
#factor-pair
#signs
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A ((x-7)(x+3))
B ((x+7)(x-3))
C ((x-21)(x+1))
D ((x-4)(x-21))
Explanation opens after your attempt
Correct Answer
A. ((x-7)(x+3))
Step 1
Concept
(-7+3=-4) and ((-7)(3)=-21). In exams, keep the larger factor's sign like the middle term.
Step 2
Why this answer is correct
The correct answer is A. ((x-7)(x+3)). (-7+3=-4) and ((-7)(3)=-21). In exams, keep the larger factor's sign like the middle term.
Step 3
Exam Tip
(-7+3=-4) और ((-7)(3)=-21) है। परीक्षा में बड़े गुणनखंड का चिह्न मध्य पद जैसा रखें।
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\(2x^2+5x+3\) का सही गुणनखंड कौन-सा है?
Which is the correct factorisation of \(2x^2+5x+3\)?
#quadratic-expressions
#coefficient-quadratic
#factorisation
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A ((2x+3)(x+1))
B ((2x+1)(x+3))
C ((x+2)(x+3))
D ((2x-3)(x-1))
Explanation opens after your attempt
Correct Answer
A. ((2x+3)(x+1))
Step 1
Concept
Expanding gives \(2x^2+2x+3x+3=2x^2+5x+3\). In exams, verify options by multiplication.
Step 2
Why this answer is correct
The correct answer is A. ((2x+3)(x+1)). Expanding gives \(2x^2+2x+3x+3=2x^2+5x+3\). In exams, verify options by multiplication.
Step 3
Exam Tip
विस्तार करने पर \(2x^2+2x+3x+3=2x^2+5x+3\) मिलता है। परीक्षा में गुणा करके विकल्प जाँचें।
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\(3x^2+14x+8\) का गुणनखंड रूप चुनिए।
Choose the factorised form of \(3x^2+14x+8\).
#quadratic-expressions
#hard-factorisation
#expansion-check
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A ((3x+2)(x+4))
B ((3x+4)(x+2))
C ((x+6)(3x+2))
D ((3x-2)(x-4))
Explanation opens after your attempt
Correct Answer
A. ((3x+2)(x+4))
Step 1
Concept
((3x+2)(x+4)) gives \(3x^2+12x+2x+8\). In exams, check the sum of middle terms.
Step 2
Why this answer is correct
The correct answer is A. ((3x+2)(x+4)). ((3x+2)(x+4)) gives \(3x^2+12x+2x+8\). In exams, check the sum of middle terms.
Step 3
Exam Tip
((3x+2)(x+4)) से \(3x^2+12x+2x+8\) मिलता है। परीक्षा में मध्य पदों का योग देखें।
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\(2x^2-7x+6\) का सही गुणनखंड क्या है?
What is the correct factorisation of \(2x^2-7x+6\)?
#quadratic-expressions
#negative-middle
#factorisation
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A ((2x-3)(x-2))
B ((2x-1)(x-6))
C ((x-3)(x-2))
D ((2x+3)(x+2))
Explanation opens after your attempt
Correct Answer
A. ((2x-3)(x-2))
Step 1
Concept
((2x-3)(x-2)) gives \(2x^2-4x-3x+6\). In exams, add both negative middle terms.
Step 2
Why this answer is correct
The correct answer is A. ((2x-3)(x-2)). ((2x-3)(x-2)) gives \(2x^2-4x-3x+6\). In exams, add both negative middle terms.
Step 3
Exam Tip
((2x-3)(x-2)) से \(2x^2-4x-3x+6\) मिलता है। परीक्षा में दोनों ऋणात्मक मध्य पद जोड़ें।
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\(5x^2-13x+6\) के गुणनखंड कौन-से होंगे?
What will be the factors of \(5x^2-13x+6\)?
#quadratic-expressions
#coefficient
#signs
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A ((5x-3)(x-2))
B ((5x-2)(x-3))
C ((x-5)(5x-6))
D ((5x+3)(x+2))
Explanation opens after your attempt
Correct Answer
A. ((5x-3)(x-2))
Step 1
Concept
((5x-3)(x-2)) gives \(5x^2-10x-3x+6\). In exams, confirm the middle term (-13x).
Step 2
Why this answer is correct
The correct answer is A. ((5x-3)(x-2)). ((5x-3)(x-2)) gives \(5x^2-10x-3x+6\). In exams, confirm the middle term (-13x).
Step 3
Exam Tip
((5x-3)(x-2)) से \(5x^2-10x-3x+6\) मिलता है। परीक्षा में मध्य पद (-13x) की पुष्टि करें।
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\(6x^2+x-2\) को गुणनखंडित कीजिए।
Factorise \(6x^2+x-2\).
#quadratic-expressions
#hard-factorisation
#signed-middle
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A ((3x+2)(2x-1))
B ((3x-2)(2x+1))
C ((6x-2)(x+1))
D ((x+2)(6x-1))
Explanation opens after your attempt
Correct Answer
A. ((3x+2)(2x-1))
Step 1
Concept
((3x+2)(2x-1)) gives \(6x^2-3x+4x-2\). In exams, add middle terms with opposite signs.
Step 2
Why this answer is correct
The correct answer is A. ((3x+2)(2x-1)). ((3x+2)(2x-1)) gives \(6x^2-3x+4x-2\). In exams, add middle terms with opposite signs.
Step 3
Exam Tip
((3x+2)(2x-1)) से \(6x^2-3x+4x-2\) मिलता है। परीक्षा में विपरीत चिह्न वाले मध्य पद जोड़ें।
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\(x^2+px+24\) में यदि एक गुणनखंड (x+6) है, तो (p) का मान क्या होगा?
In \(x^2+px+24\), if one factor is (x+6), what is the value of (p)?
#quadratic-expressions
#unknown-coefficient
#factors
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A (10)
B (12)
C (14)
D (18)
Explanation opens after your attempt
Step 1
Concept
The other factor is (x+4) because \(6\cdot4=24\), so (p=6+4=10). In exams, find the other factor from the constant term.
Step 2
Why this answer is correct
The correct answer is A. (10). The other factor is (x+4) because \(6\cdot4=24\), so (p=6+4=10). In exams, find the other factor from the constant term.
Step 3
Exam Tip
दूसरा गुणनखंड (x+4) होगा क्योंकि \(6\cdot4=24\), इसलिए (p=6+4=10)। परीक्षा में स्थिर पद से दूसरा गुणनखंड खोजें।
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\(x^2+kx+36\) को ((x+4)(x+9)) के बराबर बनाया गया है। (k) का मान क्या है?
\(x^2+kx+36\) is made equal to ((x+4)(x+9)). What is the value of (k)?
#quadratic-expressions
#unknown-middle
#expansion
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A (13)
B (36)
C (5)
D (9)
Explanation opens after your attempt
Step 1
Concept
((x+4)(x+9)=x-2 +13x+36). In exams, add the constant parts of the factors.
Step 2
Why this answer is correct
The correct answer is A. (13). ((x+4)(x+9)=x-2 +13x+36). In exams, add the constant parts of the factors.
Step 3
Exam Tip
((x+4)(x+9)=x-2 +13x+36) है। परीक्षा में गुणनखंडों के स्थिर भाग जोड़ें।
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\(x^2-11x+k\) के गुणनखंड (x-5) और (x-6) हैं। (k) का मान क्या होगा?
The factors of \(x^2-11x+k\) are (x-5) and (x-6). What will be the value of (k)?
#quadratic-expressions
#constant-term
#factorisation
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A (11)
B (30)
C (-30)
D (-11)
Explanation opens after your attempt
Step 1
Concept
The constant term is ((-5)(-6)=30). In exams, multiply the constant parts of the factors.
Step 2
Why this answer is correct
The correct answer is B. (30). The constant term is ((-5)(-6)=30). In exams, multiply the constant parts of the factors.
Step 3
Exam Tip
स्थिर पद ((-5)(-6)=30) है। परीक्षा में गुणनखंडों के स्थिर भागों का गुणन करें।
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\(x^2+8x+c\) को पूर्ण वर्ग बनाने के लिए (c) का मान क्या होना चाहिए?
What should be the value of (c) to make \(x^2+8x+c\) a perfect square?
#quadratic-expressions
#complete-square
#unknown-constant
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A (8)
B (16)
C (32)
D (64)
Explanation opens after your attempt
Step 1
Concept
Half of (8) is (4), and \(4^2=16\). In exams, square half of the middle coefficient.
Step 2
Why this answer is correct
The correct answer is B. (16). Half of (8) is (4), and \(4^2=16\). In exams, square half of the middle coefficient.
Step 3
Exam Tip
(8) का आधा (4) है और \(4^2=16\) है। परीक्षा में मध्य पद के आधे का वर्ग लें।
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\(x^2-14x+c\) पूर्ण वर्ग हो, तो (c) का मान क्या होगा?
If \(x^2-14x+c\) is a perfect square, what will be the value of (c)?
#quadratic-expressions
#perfect-square
#complete-square
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A (49)
B (14)
C (196)
D (7)
Explanation opens after your attempt
Step 1
Concept
Half of (-14) is (-7), and ((-7)2 =49). In exams, even if the sign is negative, the square is positive.
Step 2
Why this answer is correct
The correct answer is A. (49). Half of (-14) is (-7), and ((-7)2 =49). In exams, even if the sign is negative, the square is positive.
Step 3
Exam Tip
(-14) का आधा (-7) है और ((-7)2 =49) है। परीक्षा में चिह्न चाहे ऋण हो, वर्ग धनात्मक होता है।
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\(9x^2-mx+16\) पूर्ण वर्ग है। (m) का मान क्या होगा?
\(9x^2-mx+16\) is a perfect square. What will be the value of (m)?
#quadratic-expressions
#unknown-coefficient
#perfect-square
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A (12)
B (16)
C (24)
D (48)
Explanation opens after your attempt
Step 1
Concept
(9x-2 =(3x)2 ) and \(16=4^2\), so the middle coefficient is \(2\cdot3\cdot4=24\). In exams, view the negative sign and coefficient separately.
Step 2
Why this answer is correct
The correct answer is C. (24). (9x-2 =(3x)2 ) and \(16=4^2\), so the middle coefficient is \(2\cdot3\cdot4=24\). In exams, view the negative sign and coefficient separately.
Step 3
Exam Tip
(9x-2 =(3x)2 ) और \(16=4^2\), इसलिए मध्य गुणांक \(2\cdot3\cdot4=24\) है। परीक्षा में ऋण चिन्ह अलग और गुणांक अलग देखें।
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\(2x^2+7x+5\) में (x=1) रखने पर मान क्या होगा?
What is the value of \(2x^2+7x+5\) when (x=1)?
#quadratic-expressions
#evaluation
#value
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A (12)
B (14)
C (15)
D (10)
Explanation opens after your attempt
Step 1
Concept
(2(1)2 +7(1)+5=14). In exams, when substituting (1), all terms add directly.
Step 2
Why this answer is correct
The correct answer is B. (14). (2(1)2 +7(1)+5=14). In exams, when substituting (1), all terms add directly.
Step 3
Exam Tip
(2(1)2 +7(1)+5=14) है। परीक्षा में (1) रखने पर सभी पद सीधे जुड़ते हैं।
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\(3x^2-2x-8\) में (x=-1) रखने पर मान क्या होगा?
What is the value of \(3x^2-2x-8\) when (x=-1)?
#quadratic-expressions
#negative-substitution
#evaluation
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A (-3)
B (-7)
C (3)
D (1)
Explanation opens after your attempt
Step 1
Concept
(3(-1)2 -2(-1)-8=3+2-8=-3). In exams, the square of a negative number is positive.
Step 2
Why this answer is correct
The correct answer is A. (-3). (3(-1)2 -2(-1)-8=3+2-8=-3). In exams, the square of a negative number is positive.
Step 3
Exam Tip
(3(-1)2 -2(-1)-8=3+2-8=-3) है। परीक्षा में ऋण संख्या का वर्ग धनात्मक होता है।
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\(x^2-5x+6\) का मान (x=2) पर क्या होगा?
What is the value of \(x^2-5x+6\) at (x=2)?
#quadratic-expressions
#value
#zero
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A (0)
B (2)
C (-2)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(2^2-5\cdot2+6=4-10+6=0\). In exams, do square, multiplication, and addition in order.
Step 2
Why this answer is correct
The correct answer is A. (0). \(2^2-5\cdot2+6=4-10+6=0\). In exams, do square, multiplication, and addition in order.
Step 3
Exam Tip
\(2^2-5\cdot2+6=4-10+6=0\) है। परीक्षा में क्रम से वर्ग, गुणन और जोड़ करें।
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\(x^2+ax+18\) में यदि दो स्थिर गुणनखंड (3) और (6) हैं, तो (a) क्या है?
In \(x^2+ax+18\), if the two constant factors are (3) and (6), what is (a)?
#quadratic-expressions
#coefficient
#sum-product
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A (9)
B (18)
C (3)
D (6)
Explanation opens after your attempt
Step 1
Concept
The middle coefficient will be (3+6=9). In exams, identify the form (x-2 +(p+q)x+pq).
Step 2
Why this answer is correct
The correct answer is A. (9). The middle coefficient will be (3+6=9). In exams, identify the form (x-2 +(p+q)x+pq).
Step 3
Exam Tip
मध्य गुणांक (3+6=9) होगा। परीक्षा में (x-2 +(p+q)x+pq) का रूप पहचानें।
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\(x^2+bx-28\) के गुणनखंड (x+7) और (x-4) हैं। (b) का मान क्या है?
The factors of \(x^2+bx-28\) are (x+7) and (x-4). What is the value of (b)?
#quadratic-expressions
#unknown-middle
#factors
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A (3)
B (-3)
C (11)
D (-28)
Explanation opens after your attempt
Step 1
Concept
((x+7)(x-4)=x-2 +3x-28). In exams, the middle coefficient comes from the sum of constant parts.
Step 2
Why this answer is correct
The correct answer is A. (3). ((x+7)(x-4)=x-2 +3x-28). In exams, the middle coefficient comes from the sum of constant parts.
Step 3
Exam Tip
((x+7)(x-4)=x-2 +3x-28) है। परीक्षा में मध्य गुणांक स्थिर भागों के योग से मिलता है।
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\(2x^2+kx+12\) में यदि गुणनखंड ((2x+3)(x+4)) हैं, तो (k) क्या होगा?
In \(2x^2+kx+12\), if the factors are ((2x+3)(x+4)), what is (k)?
#quadratic-expressions
#coefficient
#expansion
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A (8)
B (11)
C (12)
D (15)
Explanation opens after your attempt
Step 1
Concept
Expansion gives \(2x^2+8x+3x+12=2x^2+11x+12\). In exams, add the cross terms.
Step 2
Why this answer is correct
The correct answer is B. (11). Expansion gives \(2x^2+8x+3x+12=2x^2+11x+12\). In exams, add the cross terms.
Step 3
Exam Tip
विस्तार से \(2x^2+8x+3x+12=2x^2+11x+12\) मिलता है। परीक्षा में क्रॉस पद जोड़ें।
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कौन-सा द्विघात व्यंजक पूर्ण वर्ग नहीं है?
Which quadratic expression is not a perfect square?
#quadratic-expressions
#perfect-square
#identification
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A \(x^2+12x+36\)
B \(4x^2+20x+25\)
C \(9x^2-30x+25\)
D \(x^2+8x+18\)
Explanation opens after your attempt
Correct Answer
D. \(x^2+8x+18\)
Step 1
Concept
For \(x^2+8x+18\), the constant should be (16) for a perfect square. In exams, check the square of half the middle coefficient.
Step 2
Why this answer is correct
The correct answer is D. \(x^2+8x+18\). For \(x^2+8x+18\), the constant should be (16) for a perfect square. In exams, check the square of half the middle coefficient.
Step 3
Exam Tip
\(x^2+8x+18\) में पूर्ण वर्ग के लिए स्थिर पद (16) चाहिए था। परीक्षा में आधे मध्य गुणांक का वर्ग जाँचें।
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\(x^2+4x+4\) और \(x^2-4\) में क्या संबंध है?
What is the relation between \(x^2+4x+4\) and \(x^2-4\)?
#quadratic-expressions
#identity-comparison
#concept
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A पहला पूर्ण वर्ग है और दूसरा वर्गों का अंतर है / First is a perfect square and second is difference of squares
B दोनों समान हैं / Both are equal
C पहला वर्गों का अंतर है और दूसरा पूर्ण वर्ग है / First is difference of squares and second is a perfect square
D दोनों रैखिक व्यंजक हैं / Both are linear expressions
Explanation opens after your attempt
Correct Answer
A. पहला पूर्ण वर्ग है और दूसरा वर्गों का अंतर है / First is a perfect square and second is difference of squares
Step 1
Concept
(x-2 +4x+4=(x+2)2 ) and (x-2 -4=(x-2)(x+2)). In exams, check signs and the middle term.
Step 2
Why this answer is correct
The correct answer is A. पहला पूर्ण वर्ग है और दूसरा वर्गों का अंतर है / First is a perfect square and second is difference of squares. (x-2 +4x+4=(x+2)2 ) and (x-2 -4=(x-2)(x+2)). In exams, check signs and the middle term.
Step 3
Exam Tip
(x-2 +4x+4=(x+2)2 ) और (x-2 -4=(x-2)(x+2)) है। परीक्षा में चिन्ह और मध्य पद देखें।
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\(x^2+6x+5\) को ((x+3)2 ) से तुलना करने पर कितना अंतर है?
When \(x^2+6x+5\) is compared with ((x+3)2 ), what is the difference?
#quadratic-expressions
#comparison
#error-check
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A (1) कम / (1) less
B (1) अधिक / (1) more
C (3) कम / (3) less
D (5) अधिक / (5) more
Explanation opens after your attempt
Correct Answer
A. (1) कम / (1) less
Step 1
Concept
((x+3)2 =x-2 +6x+9), so the given expression is not (1) less but (4) less. The correct comparison should be (4) less.
Step 2
Why this answer is correct
The correct answer is A. (1) कम / (1) less. ((x+3)2 =x-2 +6x+9), so the given expression is not (1) less but (4) less. The correct comparison should be (4) less.
Step 3
Exam Tip
((x+3)2 =x-2 +6x+9) है, इसलिए दिया व्यंजक (4) नहीं बल्कि (1) नहीं, (4) कम है। सही तुलना (4) कम होनी चाहिए।
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\(x^2+6x+5\) को पूर्ण वर्ग पूरा करने के लिए कौन-सा पद जोड़ना होगा?
Which term must be added to complete the square for \(x^2+6x+5\)?
#quadratic-expressions
#completing-square
#constant
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A (1)
B (4)
C (5)
D (9)
Explanation opens after your attempt
Step 1
Concept
To make \(x^2+6x\) a perfect square, (9) is needed, and (5) is already present, so add (4). In exams, square half the middle coefficient.
Step 2
Why this answer is correct
The correct answer is B. (4). To make \(x^2+6x\) a perfect square, (9) is needed, and (5) is already present, so add (4). In exams, square half the middle coefficient.
Step 3
Exam Tip
\(x^2+6x\) को पूर्ण वर्ग बनाने के लिए (9) चाहिए और (5) पहले है, इसलिए (4) जोड़ना होगा। परीक्षा में आधे मध्य गुणांक का वर्ग लें।
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\(x^2-8x+10\) को पूर्ण वर्ग पूरा करने के लिए कितना जोड़ना होगा?
How much must be added to \(x^2-8x+10\) to complete the square?
#quadratic-expressions
#complete-square
#hard
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A (6)
B (8)
C (16)
D (10)
Explanation opens after your attempt
Step 1
Concept
For \(x^2-8x\), the perfect square constant should be (16), so add (16-10=6). In exams, subtract the current constant.
Step 2
Why this answer is correct
The correct answer is A. (6). For \(x^2-8x\), the perfect square constant should be (16), so add (16-10=6). In exams, subtract the current constant.
Step 3
Exam Tip
\(x^2-8x\) के लिए पूर्ण वर्ग स्थिर पद (16) चाहिए, इसलिए (16-10=6) जोड़ें। परीक्षा में वर्तमान स्थिर पद घटाएँ।
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\(12x^2-18x\) का पूर्ण सामान्य गुणनखंड रूप क्या है?
What is the complete common-factor form of \(12x^2-18x\)?
#quadratic-expressions
#gcf
#factorisation
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A (6x(2x-3))
B (3x(4x-6))
C (6\(2x^2-3x\))
D (12x(x-18))
Explanation opens after your attempt
Correct Answer
A. (6x(2x-3))
Step 1
Concept
The greatest common factor is (6x). In exams, take the common part of both number and variable.
Step 2
Why this answer is correct
The correct answer is A. (6x(2x-3)). The greatest common factor is (6x). In exams, take the common part of both number and variable.
Step 3
Exam Tip
महत्तम सामान्य गुणनखंड (6x) है। परीक्षा में संख्या और चर दोनों का सामान्य भाग लें।
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\(x^2-16\) और \(x^2-8x+16\) के सही रूपों की जोड़ी कौन-सी है?
Which pair of forms is correct for \(x^2-16\) and \(x^2-8x+16\)?
#quadratic-expressions
#difference-of-squares
#perfect-square
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A ((x-4)(x+4)) और ((x-4)2 ) / ((x-4)(x+4)) and ((x-4)2 )
B ((x-4)2 ) और ((x-4)(x+4)) / ((x-4)2 ) and ((x-4)(x+4))
C ((x+4)2 ) और ((x-4)2 ) / ((x+4)2 ) and ((x-4)2 )
D ((x-16)(x+1)) और ((x-8)2 ) / ((x-16)(x+1)) and ((x-8)2 )
Explanation opens after your attempt
Correct Answer
A. ((x-4)(x+4)) और ((x-4)2 ) / ((x-4)(x+4)) and ((x-4)2 )
Step 1
Concept
The first is a difference of squares and the second is a perfect square. In exams, identify by the presence of the middle term.
Step 2
Why this answer is correct
The correct answer is A. ((x-4)(x+4)) और ((x-4)2 ) / ((x-4)(x+4)) and ((x-4)2 ). The first is a difference of squares and the second is a perfect square. In exams, identify by the presence of the middle term.
Step 3
Exam Tip
पहला वर्गों का अंतर है और दूसरा पूर्ण वर्ग है। परीक्षा में मध्य पद की उपस्थिति से पहचान करें।
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\(x^2+4x+3\) का मान (x=-1) पर क्या होगा?
What is the value of \(x^2+4x+3\) at (x=-1)?
#quadratic-expressions
#evaluation
#negative-value
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A (0)
B (-2)
C (2)
D (8)
Explanation opens after your attempt
Step 1
Concept
((-1)2 +4(-1)+3=1-4+3=0). In exams, be careful with negative numbers.
Step 2
Why this answer is correct
The correct answer is A. (0). ((-1)2 +4(-1)+3=1-4+3=0). In exams, be careful with negative numbers.
Step 3
Exam Tip
((-1)2 +4(-1)+3=1-4+3=0) है। परीक्षा में ऋण संख्या के साथ सावधानी रखें।
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यदि \(x^2+mx+16\) पूर्ण वर्ग है और (m) ऋणात्मक है, तो (m) क्या होगा?
If \(x^2+mx+16\) is a perfect square and (m) is negative, what is (m)?
#quadratic-expressions
#unknown-coefficient
#perfect-square
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A (-8)
B (8)
C (-16)
D (4)
Explanation opens after your attempt
Step 1
Concept
\(16=4^2\), and the negative middle term is \(-2\cdot x\cdot4=-8x\). In exams, choose the coefficient according to the given sign.
Step 2
Why this answer is correct
The correct answer is A. (-8). \(16=4^2\), and the negative middle term is \(-2\cdot x\cdot4=-8x\). In exams, choose the coefficient according to the given sign.
Step 3
Exam Tip
\(16=4^2\) है और ऋणात्मक मध्य पद \(-2\cdot x\cdot4=-8x\) होगा। परीक्षा में दिए गए चिन्ह के अनुसार गुणांक चुनें।
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\(4x^2+kx+1\) को ((2x+1)2 ) बनाने के लिए (k) क्या होगा?
What should (k) be to make \(4x^2+kx+1\) equal to ((2x+1)2 )?
#quadratic-expressions
#expansion
#unknown-middle
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A (2)
B (4)
C (1)
D (8)
Explanation opens after your attempt
Step 1
Concept
((2x+1)2 =4x-2 +4x+1). In exams, check the middle term (2ab).
Step 2
Why this answer is correct
The correct answer is B. (4). ((2x+1)2 =4x-2 +4x+1). In exams, check the middle term (2ab).
Step 3
Exam Tip
((2x+1)2 =4x-2 +4x+1) है। परीक्षा में (2ab) वाला मध्य पद देखें।
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\(x^2-2x-24\) के गुणनखंड कौन-से हैं?
What are the factors of \(x^2-2x-24\)?
#quadratic-expressions
#factors
#negative-constant
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A ((x-6)(x+4))
B ((x+6)(x-4))
C ((x-8)(x+3))
D ((x-24)(x+1))
Explanation opens after your attempt
Correct Answer
A. ((x-6)(x+4))
Step 1
Concept
(-6+4=-2) and ((-6)(4)=-24). In exams, use different signs for a negative constant term.
Step 2
Why this answer is correct
The correct answer is A. ((x-6)(x+4)). (-6+4=-2) and ((-6)(4)=-24). In exams, use different signs for a negative constant term.
Step 3
Exam Tip
(-6+4=-2) और ((-6)(4)=-24) है। परीक्षा में ऋणात्मक स्थिर पद के लिए अलग चिह्न लें।
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\(x^2+13x+42\) के लिए सही गुणनखंड जोड़ी कौन-सी है?
Which is the correct factor pair for \(x^2+13x+42\)?
#quadratic-expressions
#sum-product
#factorisation
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A ((x+6)(x+7))
B ((x+3)(x+14))
C ((x+2)(x+21))
D ((x-6)(x-7))
Explanation opens after your attempt
Correct Answer
A. ((x+6)(x+7))
Step 1
Concept
(6+7=13) and \(6\cdot7=42\). In exams, first check close factor pairs.
Step 2
Why this answer is correct
The correct answer is A. ((x+6)(x+7)). (6+7=13) and \(6\cdot7=42\). In exams, first check close factor pairs.
Step 3
Exam Tip
(6+7=13) और \(6\cdot7=42\) है। परीक्षा में निकट गुणनखंडों की जोड़ी पहले देखें।
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\(x^2-15x+56\) का सही गुणनखंड रूप क्या है?
What is the correct factorised form of \(x^2-15x+56\)?
#quadratic-expressions
#negative-middle
#quadratic-factors
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A ((x-7)(x-8))
B ((x+7)(x+8))
C ((x-4)(x-14))
D ((x+4)(x+14))
Explanation opens after your attempt
Correct Answer
A. ((x-7)(x-8))
Step 1
Concept
(-7-8=-15) and ((-7)(-8)=56). In exams, keep both factors negative.
Step 2
Why this answer is correct
The correct answer is A. ((x-7)(x-8)). (-7-8=-15) and ((-7)(-8)=56). In exams, keep both factors negative.
Step 3
Exam Tip
(-7-8=-15) और ((-7)(-8)=56) है। परीक्षा में दोनों गुणनखंड ऋणात्मक रखें।
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\(3x^2+x-10\) का गुणनखंड रूप चुनिए।
Choose the factorised form of \(3x^2+x-10\).
#quadratic-expressions
#coefficient-factorisation
#signs
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A ((3x-5)(x+2))
B ((3x+5)(x-2))
C ((x-5)(3x+2))
D ((3x-1)(x+10))
Explanation opens after your attempt
Correct Answer
A. ((3x-5)(x+2))
Step 1
Concept
((3x-5)(x+2)) gives \(3x^2+6x-5x-10\). In exams, check until the middle term becomes (x).
Step 2
Why this answer is correct
The correct answer is A. ((3x-5)(x+2)). ((3x-5)(x+2)) gives \(3x^2+6x-5x-10\). In exams, check until the middle term becomes (x).
Step 3
Exam Tip
((3x-5)(x+2)) से \(3x^2+6x-5x-10\) मिलता है। परीक्षा में मध्य पद (x) बनने तक जाँचें।
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\(4x^2-11x+6\) को गुणनखंडित कीजिए।
Factorise \(4x^2-11x+6\).
#quadratic-expressions
#hard-factorisation
#negative-middle
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A ((4x-3)(x-2))
B ((4x-2)(x-3))
C ((2x-3)(2x-2))
D ((4x+3)(x+2))
Explanation opens after your attempt
Correct Answer
A. ((4x-3)(x-2))
Step 1
Concept
((4x-3)(x-2)) gives \(4x^2-8x-3x+6\). In exams, check the middle term (-11x).
Step 2
Why this answer is correct
The correct answer is A. ((4x-3)(x-2)). ((4x-3)(x-2)) gives \(4x^2-8x-3x+6\). In exams, check the middle term (-11x).
Step 3
Exam Tip
((4x-3)(x-2)) से \(4x^2-8x-3x+6\) मिलता है। परीक्षा में मध्य पद (-11x) जाँचें।
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\(x^2+4x-45\) का सही गुणनखंड कौन-सा है?
Which is the correct factorisation of \(x^2+4x-45\)?
#quadratic-expressions
#signed-factors
#factorisation
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A ((x+9)(x-5))
B ((x-9)(x+5))
C ((x+15)(x-3))
D ((x+45)(x-1))
Explanation opens after your attempt
Correct Answer
A. ((x+9)(x-5))
Step 1
Concept
(9-5=4) and (9\cdot(-5)=-45). In exams, keep the larger number's sign like the middle term.
Step 2
Why this answer is correct
The correct answer is A. ((x+9)(x-5)). (9-5=4) and (9\cdot(-5)=-45). In exams, keep the larger number's sign like the middle term.
Step 3
Exam Tip
(9-5=4) और (9\cdot(-5)=-45) है। परीक्षा में बड़ी संख्या का चिह्न मध्य पद जैसा रखें।
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\(x^2-18x+81\) का पूर्ण वर्ग रूप क्या है?
What is the perfect square form of \(x^2-18x+81\)?
#quadratic-expressions
#perfect-square
#minus
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A ((x-9)2 )
B ((x+9)2 )
C ((x-18)2 )
D ((x+81)2 )
Explanation opens after your attempt
Correct Answer
A. ((x-9)2 )
Step 1
Concept
\(81=9^2\) and \(-18x=-2\cdot x\cdot9\). In exams, identify the subtraction square from the negative middle term.
Step 2
Why this answer is correct
The correct answer is A. ((x-9)2 ). \(81=9^2\) and \(-18x=-2\cdot x\cdot9\). In exams, identify the subtraction square from the negative middle term.
Step 3
Exam Tip
\(81=9^2\) और \(-18x=-2\cdot x\cdot9\) है। परीक्षा में ऋण मध्य पद से घटाव वाला वर्ग पहचानें।
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\(16x^2+40x+25\) को किस रूप में लिखा जा सकता है?
In which form can \(16x^2+40x+25\) be written?
#quadratic-expressions
#perfect-square
#coefficient
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A ((4x+5)2 )
B ((16x+5)2 )
C ((4x-5)2 )
D ((2x+10)2 )
Explanation opens after your attempt
Correct Answer
A. ((4x+5)2 )
Step 1
Concept
(16x-2 =(4x)2 ), \(25=5^2\), and \(40x=2\cdot4x\cdot5\). In exams, check the square roots of first and last terms.
Step 2
Why this answer is correct
The correct answer is A. ((4x+5)2 ). (16x-2 =(4x)2 ), \(25=5^2\), and \(40x=2\cdot4x\cdot5\). In exams, check the square roots of first and last terms.
Step 3
Exam Tip
(16x-2 =(4x)2 ), \(25=5^2\) और \(40x=2\cdot4x\cdot5\) है। परीक्षा में पहले और अंतिम पद के वर्गमूल देखें।
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\(x^2+mx+49\) पूर्ण वर्ग है और (m) धनात्मक है। (m) का मान क्या होगा?
\(x^2+mx+49\) is a perfect square and (m) is positive. What will be the value of (m)?
#quadratic-expressions
#unknown-coefficient
#perfect-square
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A (7)
B (14)
C (49)
D (98)
Explanation opens after your attempt
Step 1
Concept
\(49=7^2\), so the middle term is \(2\cdot x\cdot7=14x\). In exams, take the positive middle coefficient for a positive perfect square.
Step 2
Why this answer is correct
The correct answer is B. (14). \(49=7^2\), so the middle term is \(2\cdot x\cdot7=14x\). In exams, take the positive middle coefficient for a positive perfect square.
Step 3
Exam Tip
\(49=7^2\) है इसलिए मध्य पद \(2\cdot x\cdot7=14x\) होगा। परीक्षा में धनात्मक पूर्ण वर्ग के लिए धनात्मक मध्य गुणांक लें।
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\(2x^2+px+8\) के गुणनखंड ((2x+4)(x+2)) नहीं हो सकते। सही कारण क्या है?
The factors of \(2x^2+px+8\) cannot be ((2x+4)(x+2)). What is the correct reason?
#quadratic-expressions
#expansion-check
#factors
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A क्योंकि विस्तार में \(2x^2+8x+8\) मिलता है / Because expansion gives \(2x^2+8x+8\)
B क्योंकि विस्तार में \(2x^2+4x+8\) मिलता है / Because expansion gives \(2x^2+4x+8\)
C क्योंकि स्थिर पद (6) बनता है / Because the constant term becomes (6)
D क्योंकि \(x^2\) पद नहीं बनता / Because the \(x^2\) term is not formed
Explanation opens after your attempt
Correct Answer
A. क्योंकि विस्तार में \(2x^2+8x+8\) मिलता है / Because expansion gives \(2x^2+8x+8\)
Step 1
Concept
Expanding ((2x+4)(x+2)) gives \(2x^2+8x+8\). In exams, verify the option by expansion.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि विस्तार में \(2x^2+8x+8\) मिलता है / Because expansion gives \(2x^2+8x+8\). Expanding ((2x+4)(x+2)) gives \(2x^2+8x+8\). In exams, verify the option by expansion.
Step 3
Exam Tip
((2x+4)(x+2)) फैलाने पर \(2x^2+8x+8\) मिलता है। परीक्षा में विकल्प को विस्तार करके सत्यापित करें।
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\(3x^2+kx+12\) में यदि गुणनखंड ((3x+4)(x+3)) हैं, तो (k) का मान क्या है?
In \(3x^2+kx+12\), if the factors are ((3x+4)(x+3)), what is the value of (k)?
#quadratic-expressions
#unknown-coefficient
#product
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A (7)
B (9)
C (13)
D (15)
Explanation opens after your attempt
Step 1
Concept
((3x+4)(x+3)=3x-2 +9x+4x+12=3x-2 +13x+12). In exams, add the cross terms.
Step 2
Why this answer is correct
The correct answer is C. (13). ((3x+4)(x+3)=3x-2 +9x+4x+12=3x-2 +13x+12). In exams, add the cross terms.
Step 3
Exam Tip
((3x+4)(x+3)=3x-2 +9x+4x+12=3x-2 +13x+12) है। परीक्षा में क्रॉस पदों को जोड़ें।
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\(x^2-12x+32\) का सही गुणनखंड रूप क्या है?
What is the correct factorised form of \(x^2-12x+32\)?
#quadratic-expressions
#factorisation
#negative-middle
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A ((x-4)(x-8))
B ((x+4)(x+8))
C ((x-2)(x-16))
D ((x+2)(x+16))
Explanation opens after your attempt
Correct Answer
A. ((x-4)(x-8))
Step 1
Concept
(-4-8=-12) and ((-4)(-8)=32). In exams, use both negative signs when the constant is positive and middle term is negative.
Step 2
Why this answer is correct
The correct answer is A. ((x-4)(x-8)). (-4-8=-12) and ((-4)(-8)=32). In exams, use both negative signs when the constant is positive and middle term is negative.
Step 3
Exam Tip
(-4-8=-12) और ((-4)(-8)=32) है। परीक्षा में धनात्मक स्थिर पद और ऋणात्मक मध्य पद पर दोनों चिह्न ऋण रखें।
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\(25x^2+mx+36\) पूर्ण वर्ग है और (m) धनात्मक है। (m) का मान क्या होगा?
\(25x^2+mx+36\) is a perfect square and (m) is positive. What will be the value of (m)?
#quadratic-expressions
#perfect-square
#unknown-middle
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A (30)
B (60)
C (90)
D (150)
Explanation opens after your attempt
Step 1
Concept
(25x-2 =(5x)2 ) and \(36=6^2\), so the middle term is \(2\cdot5x\cdot6=60x\). In exams, multiply twice the two square roots.
Step 2
Why this answer is correct
The correct answer is B. (60). (25x-2 =(5x)2 ) and \(36=6^2\), so the middle term is \(2\cdot5x\cdot6=60x\). In exams, multiply twice the two square roots.
Step 3
Exam Tip
(25x-2 =(5x)2 ) और \(36=6^2\), इसलिए मध्य पद \(2\cdot5x\cdot6=60x\) है। परीक्षा में दोनों वर्गमूलों का दुगुना गुणन करें।
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