\(x^2+px+24\) में यदि एक गुणनखंड (x+6) है, तो (p) का मान क्या होगा?
In \(x^2+px+24\), if one factor is (x+6), what is the value of (p)?
Explanation opens after your attempt
A. (10)
Concept
The other factor is (x+4) because \(6\cdot4=24\), so (p=6+4=10). In exams, find the other factor from the constant term.
Why this answer is correct
The correct answer is A. (10). The other factor is (x+4) because \(6\cdot4=24\), so (p=6+4=10). In exams, find the other factor from the constant term.
Exam Tip
दूसरा गुणनखंड (x+4) होगा क्योंकि \(6\cdot4=24\), इसलिए (p=6+4=10)। परीक्षा में स्थिर पद से दूसरा गुणनखंड खोजें।
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