Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 571-580 of 600 questions.
In the line \(y=\frac{9}{4}x-15\), how much should (x) increase to increase (y) by (36)?
C. (16)
परिवर्तन \(\frac{9}{4}\Delta x=36\) होगा। इससे \(\Delta x=16\) मिलता है। / The change is \(\frac{9}{4}\Delta x=36\). This gives \(\Delta x=16\).
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If (p=-9) and (q=14) in (y=px+q), which statement is correct?
B. रेखा घटती है और (y)-अवरोध धनात्मक हैThe line decreases and the (y)-intercept is positive
(p=-9) ऋणात्मक ढाल देता है और (q=14) धनात्मक (y)-अवरोध देता है। इसलिए रेखा घटती है। / (p=-9) gives a negative slope and (q=14) gives a positive (y)-intercept. So the line decreases.
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If (6x+ay=54) has (y)-intercept (9), what is (a)?
C. (6)
(x=0) रखने पर (ay=54) और \(y=\frac{54}{a}\) मिलता है। \(\frac{54}{a}=9\) से (a=6) है। / Putting (x=0) gives (ay=54) and \(y=\frac{54}{a}\). From \(\frac{54}{a}=9\), (a=6).
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If (bx+12y=96) has slope (-4), what is (b)?
C. (48)
(12y=-bx+96) से ढाल \(-\frac{b}{12}\) है। \(-\frac{b}{12}=-4\) से (b=48) है। / From (12y=-bx+96), the slope is \(-\frac{b}{12}\). From \(-\frac{b}{12}=-4\), (b=48).
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The line (y=(n-9)x+(5n-7)) has (y)-intercept (38). What is its slope?
A. (0)
(5n-7=38) से (n=9) मिलता है। ढाल (n-9=0) है। / From (5n-7=38), (n=9). The slope is (n-9=0).
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The line (y=(t-12)x+(4t-3)) has slope (6). What is its (y)-intercept?
C. (69)
(t-12=6) से (t=18) मिलता है। (y)-अवरोध (4t-3=69) है। / From (t-12=6), (t=18). The (y)-intercept is (4t-3=69).
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Which line cuts the (y)-axis at ((0,-16)) and increases (y) by (70) when (x) increases by (7)?
A. (y=10x-16)
ढाल \(\frac{70}{7}=10\) है और (y)-अवरोध (-16) है। इसलिए रेखा (y=10x-16) है। / The slope is \(\frac{70}{7}=10\) and the (y)-intercept is (-16). So the line is (y=10x-16).
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Which line cuts the (y)-axis at ((0,20)) and decreases (y) by (72) when (x) increases by (8)?
B. (y=-9x+20)
ढाल \(-\frac{72}{8}=-9\) है और (y)-अवरोध (20) है। इसलिए (y=-9x+20) सही है। / The slope is \(-\frac{72}{8}=-9\) and the (y)-intercept is (20). So (y=-9x+20) is correct.
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If (y=(a+11)x+(a-18)) passes through the origin, what will be its slope?
C. (29)
मूल बिंदु से गुजरने के लिए (a-18=0) होगा। इसलिए (a=18) और ढाल (29) है। / To pass through the origin, (a-18=0). Thus (a=18) and the slope is (29).
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If (y=(4u-3)x+(u+7)) has (y)-intercept (19), what is the slope?
B. (45)
(u+7=19) से (u=12) मिलता है। ढाल (4u-3=45) है। / From (u+7=19), (u=12). The slope is (4u-3=45).
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