Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 421-430 of 600 questions.
If \(\frac{7\pi}{18}\) and (x) are supplementary angles then what is (x)?
C. \(\frac{11\pi}{18}\)
संपूरक कोणों का योग \(\pi\) होता है। इसलिए \(x=\pi-\frac{7\pi}{18}=\frac{11\pi}{18}\) है। / Supplementary angles add to \(\pi\). Hence \(x=\pi-\frac{7\pi}{18}=\frac{11\pi}{18}\).
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If an angle is \(\frac{2}{5}\) radians then what is its complement?
A. \(\frac{\pi}{2}-\frac{2}{5}\)
रेडियन में पूरक कोणों का योग \(\frac{\pi}{2}\) होता है। इसलिए उत्तर \(\frac{\pi}{2}-\frac{2}{5}\) है। / In radians complementary angles add to \(\frac{\pi}{2}\). So the answer is \(\frac{\pi}{2}-\frac{2}{5}\).
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If the arc length is (22) cm and the radius is (7) cm then what is the central angle in radians?
B. \(\frac{22}{7}\)
\(\theta=\frac{s}{r}\) होता है। इसलिए \(\theta=\frac{22}{7}\) रेडियन है। / \(\theta=\frac{s}{r}\). Hence \(\theta=\frac{22}{7}\) radians.
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What is the area of a sector with radius (6) cm and central angle \(\frac{5\pi}{9}\)?
C. \(10\pi\) वर्ग सेमी\(10\pi\) sq cm
त्रिज्यखंड क्षेत्रफल \(\frac{1}{2}r^2\theta\) होता है। इसलिए \(\frac{1}{2}\times36\times\frac{5\pi}{9}=10\pi\) है। / Sector area is \(\frac{1}{2}r^2\theta\). So \(\frac{1}{2}\times36\times\frac{5\pi}{9}=10\pi\).
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Approximately (1) radian is equal to how many degrees?
C. \(57.3^\circ\)
(1) रेडियन \(=\frac{180^\circ}{\pi}\approx57.3^\circ\) होता है। अनुमान वाले प्रश्नों में \(\pi\approx3.14\) लें। / (1) radian \(=\frac{180^\circ}{\pi}\approx57.3^\circ\). In approximation questions use \(\pi\approx3.14\).
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If the arc length is equal to the diameter of the circle then what is the central angle in radians?
C. (2)
व्यास (2r) होता है और \(\theta=\frac{s}{r}\) है। इसलिए \(\theta=\frac{2r}{r}=2\) रेडियन। / Diameter is (2r) and \(\theta=\frac{s}{r}\). Hence \(\theta=\frac{2r}{r}=2\) radians.
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B. (1)
एक चक्कर की दूरी \(2\pi r=220\) सेमी है। इसलिए कुल चक्कर (1) होगा। / Distance in one revolution is \(2\pi r=220\) cm. Hence the number of revolutions is (1).
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Convert the angle \(54^\circ\) into radians.
A. \(\frac{3\pi}{10}\)
\(54^\circ\times\frac{\pi}{180}=\frac{3\pi}{10}\) होता है। डिग्री से रेडियन में जाने पर \(\frac{\pi}{180}\) लगाएं। / \(54^\circ\times\frac{\pi}{180}=\frac{3\pi}{10}\). Use \(\frac{\pi}{180}\) when converting degrees to radians.
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\(\frac{13\pi}{6}\) is coterminal with which smaller positive angle?
A. \(\frac{\pi}{6}\)
\(\frac{13\pi}{6}-2\pi=\frac{\pi}{6}\) है। \(2\pi\) घटाकर मुख्य कोण प्राप्त करें। / \(\frac{13\pi}{6}-2\pi=\frac{\pi}{6}\). Subtract \(2\pi\) to obtain the principal angle.
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If \(\theta=110^\circ\) then what is the general form of all coterminal angles of \(\theta\)?
B. \(110^\circ+360^\circ k\)
डिग्री में सहप्रारंभी कोण \(360^\circ\) के गुणज जोड़कर मिलते हैं। इसलिए रूप \(110^\circ+360^\circ k\) है। / In degrees coterminal angles are obtained by adding multiples of \(360^\circ\). So the form is \(110^\circ+360^\circ k\).
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