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supplementary-angles MCQ Questions for Class 11

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4 questions tagged with supplementary-angles.

Question 1/4 Expert Mathematics Trigonometric Functions Angles Class 11 Level 68

यदि कोण की पूरक राशि उसकी संपूरक राशि की \(\frac{1}{5}\) है तो कोण कितना है?

If the complement of an angle is \(\frac{1}{5}\) of its supplement then what is the angle?

Explanation opens after your attempt
Correct Answer

C. \(67^\circ30'\)

Step 1

Concept

If the angle is (x) then (90^\circ-x=\frac{1}{5}\(180^\circ-x\)). Solving gives \(x=67^\circ30'\).

Step 2

Why this answer is correct

The correct answer is C. \(67^\circ30'\). If the angle is (x) then (90^\circ-x=\frac{1}{5}\(180^\circ-x\)). Solving gives \(x=67^\circ30'\).

Step 3

Exam Tip

यदि कोण (x) है तो (90^\circ-x=\frac{1}{5}\(180^\circ-x\))। हल करने पर \(x=67^\circ30'\) मिलता है।

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Question 2/4 Hard Mathematics Trigonometric Functions Angles Class 11 Level 69

किसी कोण का संपूरक कोण उसके दुगुने से \(40^\circ\) कम है। वह कोण क्या है?

The supplement of an angle is \(40^\circ\) less than twice the angle. What is the angle?

Explanation opens after your attempt
Correct Answer

C. \(\frac{220^\circ}{3}\)

Step 1

Concept

If the angle is (x) then \(180^\circ-x=2x-40^\circ\). This gives \(x=\frac{220^\circ}{3}\).

Step 2

Why this answer is correct

The correct answer is C. \(\frac{220^\circ}{3}\). If the angle is (x) then \(180^\circ-x=2x-40^\circ\). This gives \(x=\frac{220^\circ}{3}\).

Step 3

Exam Tip

यदि कोण (x) है तो \(180^\circ-x=2x-40^\circ\) होगा। इससे \(x=\frac{220^\circ}{3}\) मिलता है।

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Question 3/4 Hard Mathematics Trigonometric Functions Angles Class 11 Level 69

यदि \(\frac{7\pi}{18}\) और (x) संपूरक कोण हैं तो (x) क्या होगा?

If \(\frac{7\pi}{18}\) and (x) are supplementary angles then what is (x)?

Explanation opens after your attempt
Correct Answer

C. \(\frac{11\pi}{18}\)

Step 1

Concept

Supplementary angles add to \(\pi\). Hence \(x=\pi-\frac{7\pi}{18}=\frac{11\pi}{18}\).

Step 2

Why this answer is correct

The correct answer is C. \(\frac{11\pi}{18}\). Supplementary angles add to \(\pi\). Hence \(x=\pi-\frac{7\pi}{18}=\frac{11\pi}{18}\).

Step 3

Exam Tip

संपूरक कोणों का योग \(\pi\) होता है। इसलिए \(x=\pi-\frac{7\pi}{18}=\frac{11\pi}{18}\) है।

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Question 4/4 Hard Mathematics Trigonometric Functions Angles Class 11 Level 69

किसी कोण का संपूरक कोण उस कोण का (3) गुना है। वह कोण क्या होगा?

The supplement of an angle is (3) times the angle. What is the angle?

Explanation opens after your attempt
Correct Answer

C. \(45^\circ\)

Step 1

Concept

If the angle is (x) then \(180^\circ-x=3x\) gives \(x=45^\circ\). Supplementary angles add to \(180^\circ\).

Step 2

Why this answer is correct

The correct answer is C. \(45^\circ\). If the angle is (x) then \(180^\circ-x=3x\) gives \(x=45^\circ\). Supplementary angles add to \(180^\circ\).

Step 3

Exam Tip

यदि कोण (x) है तो \(180^\circ-x=3x\) से \(x=45^\circ\) मिलता है। संपूरक कोणों का योग \(180^\circ\) होता है।

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