Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 551-560 of 590 questions.
If (\frac{n!}{(n-5)!}=55440) then what is the value of (n)?
B. (11)
यह (n(n-1)(n-2)(n-3)(n-4)=55440) है। \(11\times10\times9\times8\times7=55440\) इसलिए (n=11) है। / This is (n(n-1)(n-2)(n-3)(n-4)=55440). Since \(11\times10\times9\times8\times7=55440\), (n=11).
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If (\frac{n!}{(n-3)!}=210) then what is the value of (n)?
C. (7)
यह (n(n-1)(n-2)=210) देता है और \(7\times6\times5=210\) है। इसलिए (n=7) है। / This gives (n(n-1)(n-2)=210) and \(7\times6\times5=210\). Therefore (n=7).
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If ((n+1)! = 72(n-1)!) then what is the value of (n)?
B. (8)
काटने पर (n(n+1)=72) मिलता है। \(8\times9=72\) इसलिए (n=8) है। / After cancellation (n(n+1)=72). Since \(8\times9=72\), (n=8).
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What is the least (n) for which (n!) is divisible by (343)?
A. (21)
\(343=7^3\) है और (21!) में (7,14,21) से तीन (7) मिलते हैं। इसलिए न्यूनतम (n=21) है। / \(343=7^3\) and (21!) gets three factors of (7) from (7,14,21). Therefore the least (n=21).
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If (\frac{(n+3)!}{(n+1)!}=110) then what will be the value of (n)?
B. (8)
((n+3)(n+2)=110) है। \(11\times10=110\) से (n=8) मिलता है। / ((n+3)(n+2)=110). From \(11\times10=110\), we get (n=8).
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What is the value of \(\frac{30!}{28!}-\frac{29!}{27!}\)?
B. (58)
पहला पद \(30\times29\) और दूसरा \(29\times28\) है। अंतर (29(30-28)=58) है। / The first term is \(30\times29\) and the second is \(29\times28\). The difference is (29(30-28)=58).
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What is the value of \(\frac{20!}{18!\times 19}\)?
C. (20)
\(\frac{20!}{18!\times19}=\frac{20\times19}{19}=20\) है। कटौती के बाद बचा हुआ गुणनखंड देखें। / \(\frac{20!}{18!\times19}=\frac{20\times19}{19}=20\). Look at the remaining factor after cancellation.
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If (\frac{(n+6)!}{(n+4)!}=272) then what is the value of (n)?
A. (10)
((n+6)(n+5)=272) मिलता है। \(16\times17=272\) इसलिए (n=10) है। / We get ((n+6)(n+5)=272). Since \(16\times17=272\), (n=10).
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What is the value of \(\frac{10!+9!}{8!}\)?
A. (99)
(10!+9!=9!(10+1)) है। (8!) से भाग देने पर \(9\times11=99\) मिलता है। / (10!+9!=9!(10+1)). Dividing by (8!) gives \(9\times11=99\).
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What is the value of \(\frac{14!+13!}{12!}\)?
B. (195)
(14!+13!=13!(14+1)) है। (12!) से भाग देने पर \(13\times15=195\) मिलता है। / (14!+13!=13!(14+1)). Dividing by (12!) gives \(13\times15=195\).
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