यदि (\frac{n!}{(n-3)!}=210) है तो (n) का मान क्या है?
If (\frac{n!}{(n-3)!}=210) then what is the value of (n)?
Explanation opens after your attempt
C. (7)
Concept
This gives (n(n-1)(n-2)=210) and \(7\times6\times5=210\). Therefore (n=7).
Why this answer is correct
The correct answer is C. (7). This gives (n(n-1)(n-2)=210) and \(7\times6\times5=210\). Therefore (n=7).
Exam Tip
यह (n(n-1)(n-2)=210) देता है और \(7\times6\times5=210\) है। इसलिए (n=7) है।
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