Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
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Choose the solution of (x+2y=12) and (x-2y=4) by elimination.
C. ( (8,2) )
दोनों समीकरण जोड़ने पर (2x=16), इसलिए (x=8) और (y=2)। विपरीत (2y) पदों को जोड़कर हटाएँ। / Adding both equations gives (2x=16), so (x=8) and (y=2). Add opposite (2y) terms to eliminate them.
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If (y=10-x) and (x=4), what is the value of (y)?
D. (y=6)
(y=10-4=6)। प्रतिस्थापन में दिए गए मान को सही स्थान पर रखें। / (y=10-4=6). In substitution, place the given value in the correct position.
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In (3x-y=7), if (x=3), what is (y)?
A. (y=2)
(9-y=7), इसलिए (y=2)। ऋण चिह्न वाले पद को हल करते समय सावधानी रखें। / (9-y=7), so (y=2). Be careful while solving a term with a negative sign.
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What is the solution of (x+y=15) and (x=2y)?
B. ( (10,5) )
(x=2y) रखने पर (3y=15), इसलिए (y=5) और (x=10)। अनुपात वाले संबंध में प्रतिस्थापन सबसे आसान रहता है। / Putting (x=2y) gives (3y=15), so (y=5) and (x=10). Substitution is easiest when a ratio relation is given.
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In elimination method, what is (y) after subtracting (2x+y=13) from (2x+5y=29)?
C. (y=4)
घटाने पर (4y=16), इसलिए (y=4)। समान (2x) पदों को हटाकर गणना सरल करें। / Subtracting gives (4y=16), so (y=4). Remove equal (2x) terms to simplify calculation.
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If (x-3y=1) and (y=2), what is the value of (x)?
D. (x=7)
(x-6=1), इसलिए (x=7)। प्रतिस्थापन के बाद स्थिर पद को दूसरी तरफ ले जाएँ। / (x-6=1), so (x=7). After substitution, move the constant term to the other side.
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By elimination, what is (x) after adding (3x+2y=20) and (3x-2y=4)?
B. (x=4)
जोड़ने पर (6x=24), इसलिए (x=4)। विपरीत (2y) पदों को जोड़कर हटाएँ। / Adding gives (6x=24), so (x=4). Add opposite (2y) terms to eliminate them.
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In (y=12-2x), if (x=5), what is (y)?
B. (y=2)
(y=12-10=2)। पहले गुणा करें और फिर घटाव करें। / (y=12-10=2). Multiply first and then subtract.
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Find the solution of (x+y=17) and (y=x+3) by substitution.
C. ( (7,10) )
(y=x+3) रखने पर (2x+3=17), इसलिए (x=7) और (y=10)। प्रतिस्थापन के बाद बने एक चर के समीकरण को हल करें। / Putting (y=x+3) gives (2x+3=17), so (x=7) and (y=10). Solve the one-variable equation formed after substitution.
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What is the solution of (x+5y=22) and (x+2y=10) by elimination?
A. ( (2,4) )
घटाने पर (3y=12), इसलिए (y=4) और (x=2)। समान (x) पदों को हटाकर पहले (y) निकालें। / Subtracting gives (3y=12), so (y=4) and (x=2). Remove equal (x) terms to find (y) first.
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