Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects

What is the solution of (x+5y=22) and (x+2y=10) by elimination?

Advertisement

Answer and explanation

Correct answer: \((2,4)\)

Subtracting the second equation, \(x+2y=10\), from the first equation, \(x+5y=22\), gives \(3y=12\). Hence, \(y=4\). Substituting this into \(x+2y=10\) gives \(x+8=10\), so \(x=2\). Therefore, the solution is \((2,4)\). The close distractor \((4,3)\) does not satisfy either equation. Exam tip: Always substitute the ordered pair back into an original equation to verify the answer.

Tags

pair of linear equationselimination methodordered pairalgebraclass 10

Frequently asked questions

What is the correct answer to this question?

\((2,4)\)

Why is this the correct answer?

Subtracting the second equation, \(x+2y=10\), from the first equation, \(x+5y=22\), gives \(3y=12\). Hence, \(y=4\). Substituting this into \(x+2y=10\) gives \(x+8=10\), so \(x=2\). Therefore, the solution is \((2,4)\). The close distractor \((4,3)\) does not satisfy either equation. Exam tip: Always substitute the ordered pair back into an original equation to verify the answer.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Algebraic methods: Substitution method and Elimination method..

Advertisement