Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 391-400 of 600 questions.
How many first terms of \(12,21,30,39,\ldots\) have sum (150)?
B. (5)
पहले (5) पद (12,21,30,39,48) हैं। उनका योग (150) है। / The first (5) terms are (12,21,30,39,48). Their sum is (150).
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In \(14,25,36,\ldots\), which term comes just before (91)?
C. (80)
क्रम (14,25,36,47,58,69,80,91) है। (91) से ठीक पहले (80) आता है। / The sequence is (14,25,36,47,58,69,80,91). The term just before (91) is (80).
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In \(768,384,192,96,\ldots\), which term comes just before (24)?
C. (48)
हर बार आधा हो रहा है। क्रम (768,384,192,96,48,24) है इसलिए (24) से पहले (48) है। / Each term is halved. The sequence is (768,384,192,96,48,24), so (48) comes before (24).
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Which statement is correct for the (n)th term of \(19,27,35,\ldots\)?
A. यह (8n+11) हैIt is (8n+11)
(n=1) पर (8(1)+11=19) और अंतर (8) मिलता है। इसलिए सही नियम (8n+11) है। / At (n=1), (8(1)+11=19), and the difference is (8). So the correct rule is (8n+11).
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Which is the correct rule for the (n)th term of \(156,144,132,\ldots\)?
A. \(a_n=168-12n\)
(n=1) रखने पर (168-12=156) मिलता है। यह हर बार (12) घटाने वाला नियम है। / Putting (n=1) gives (168-12=156). This rule decreases by (12) each time.
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If \(a_1=9\), \(a_2=16\), and each next term is the sum of the previous two terms, what is \(a_6\)?
D. (107)
क्रम (9,16,25,41,66,107) बनेगा। इसलिए \(a_6=107\) है। / The sequence becomes (9,16,25,41,66,107). Therefore \(a_6=107\).
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If \(a_n=5000\) in the sequence \(8,40,200,1000,\ldots\), what is (n)?
B. (5)
क्रम (8,40,200,1000,5000) है। (5000) पाँचवाँ पद है इसलिए (n=5)। / The sequence is (8,40,200,1000,5000). (5000) is the fifth term, so (n=5).
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If \(a_n=5n^2-4n+1\), what is the value of \(a_6-a_3\)?
C. (111)
(a_6=5\(6^2\)-4(6)+1=157) और (a_3=5\(3^2\)-4(3)+1=34) है। इसलिए अंतर (157-34=123) नहीं, विकल्पों में सही मान नहीं है। / (a_6=5\(6^2\)-4(6)+1=157) and (a_3=5\(3^2\)-4(3)+1=34). So the difference is (157-34=123), not listed in the options.
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What is the next term in \(6,13,29,61,\ldots\) if the rule is double the previous term and add (1)?
C. (123)
नियम के अनुसार \(61\times2+1=123\) है। अंतिम पद पर नियम लगाकर अगला पद निकालें। / By the rule, \(61\times2+1=123\). Apply the rule to the last term to get the next term.
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What will be the next term of \(20,31,46,65,88,\ldots\)?
C. (115)
अंतर (11,15,19,23) हैं और वे (4) से बढ़ रहे हैं। अगला अंतर (27) होगा इसलिए (88+27=115)। / The differences are (11,15,19,23), increasing by (4). The next difference is (27), so (88+27=115).
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