Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 371-380 of 600 questions.
What will \(a_6\) be for the rule \(a_n=3n^2+4n\)?
C. (132)
(n=6) रखने पर (a_6=3\(6^2\)+4(6)=132) है। वर्ग और गुणा दोनों सावधानी से करें। / Putting (n=6), (a_6=3\(6^2\)+4(6)=132). Handle both the square and multiplication carefully.
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What is the (8)th term formed by \(a_n=140-9n\)?
C. (68)
(n=8) रखने पर \(a_8=140-72=68\) है। घटाव वाले नियम में चिन्ह पर ध्यान दें। / Putting (n=8), \(a_8=140-72=68\). Pay attention to the sign in subtraction rules.
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Which sequence is formed by \(a_n=7n^2\)?
B. (7,28,63,112)
(n=1,2,3,4) रखने पर (7,28,63,112) मिलते हैं। \(n^2\) को (7) से गुणा करें। / Putting (n=1,2,3,4) gives (7,28,63,112). Multiply \(n^2\) by (7).
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Which sequence shows the first four terms of \(a_n=3^n+n\)?
A. (4,11,30,85)
\(3^1+1=4\), \(3^2+2=11\), \(3^3+3=30\), \(3^4+4=85\)। घात के बाद (n) जोड़ें। / \(3^1+1=4\), \(3^2+2=11\), \(3^3+3=30\), and \(3^4+4=85\). Add (n) after evaluating the power.
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What is the difference between the (12)th terms of \(7,14,21,28,\ldots\) and \(3,10,17,24,\ldots\)?
B. (4)
दोनों क्रमों का समान अंतर (7) है इसलिए पदों का अंतर हमेशा (4) रहेगा। (12)वें पदों में भी यही अंतर है। / Both sequences have common difference (7), so the term difference always remains (4). The (12)th terms also differ by (4).
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How are the (9)th term of \(22,30,38,\ldots\) and the (9)th term of \(13,21,29,\ldots\) related?
B. पहला (9) अधिक हैThe first is greater by (9)
दोनों क्रमों का अंतर (8) है और पहले पदों का अंतर (9) है। इसलिए (9)वें पदों का अंतर भी (9) होगा। / Both sequences have difference (8), and their first terms differ by (9). So their (9)th terms also differ by (9).
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What is the sum of the first (9) terms of \(8,16,24,\ldots\)?
C. (360)
पहले (9) पद (8) से (72) तक हैं। उनका योग (360) है। / The first (9) terms run from (8) to (72). Their sum is (360).
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What is the sum of the first (6) terms of \(132,121,110,\ldots\)?
B. (627)
पहले (6) पद (132,121,110,99,88,77) हैं। इनका योग (627) है। / The first (6) terms are (132,121,110,99,88,77). Their sum is (627).
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Which term is (90) in \(10,18,26,34,\ldots\)?
C. (11)वाँ(11)th
पहला पद (10) और अंतर (8) है। (10+(n-1)8=90) से (n=11) मिलता है। / The first term is (10) and the difference is (8). From (10+(n-1)8=90), (n=11).
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What is the value of \(a_8+a_9\) in \(11,17,23,29,\ldots\)?
C. (106)
\(a_8=53\) और \(a_9=59\) है। इसलिए \(a_8+a_9=112\), अतः विकल्पों में सही मान नहीं है। / \(a_8=53\) and \(a_9=59\). Therefore \(a_8+a_9=112\), so the correct value is not in the options.
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