Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
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Showing 91-100 of 601 questions.
If \(a_1=5\), \(a_2=7\), and \(a_n=a_{n-1}+a_{n-2}\), what is \(a_5\)?
C. (31)
पद (5,7,12,19,31) हैं इसलिए \(a_5=31\) है। पिछले दो पदों को जोड़कर नया पद बनता है। / The terms are (5,7,12,19,31), so \(a_5=31\). Exam tip: add the previous two terms to get the new term.
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According to the recursive rule in the sequence \(9,13,17,21,\ldots\), what is the next term?
C. (25)
हर बार (4) जोड़ा गया है इसलिए अगला पद (21+4=25) है। अंतर देखकर अगला पद निकालें। / (4) is added each time, so the next term is (21+4=25). Exam tip: use the difference to find the next term.
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According to the recursive rule in the sequence \(64,32,16,8,\ldots\), what will be the next term?
C. (4)
हर बार पद आधा हो रहा है इसलिए अगला पद (4) है। पिछले पद को (2) से भाग दें। / Each term is being halved, so the next term is (4). Exam tip: divide the previous term by (2).
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For the sequence \(8,16,24,32,\ldots\), \(a_1=8\). What is added in the recursive rule?
C. (8)
हर अगला पद पिछले से (8) अधिक है। इसलिए नियम \(a_{n+1}=a_n+8\) होगा। / Each next term is (8) more than the previous term. So the rule is \(a_{n+1}=a_n+8\).
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For the sequence \(42,36,30,24,\ldots\), what is subtracted in the recursive rule?
C. (6)
हर अगला पद पिछले से (6) कम है। इसलिए \(a_{n+1}=a_n-6\) होगा। / Each next term is (6) less than the previous term. So \(a_{n+1}=a_n-6\).
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In the sequence \(5,20,80,320,\ldots\), what is the multiplier in the recursive rule?
C. (4)
हर अगला पद पिछले पद का (4) गुना है। इसलिए गुणक (4) है। / Each next term is (4) times the previous term. Therefore the multiplier is (4).
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If \(a_1=14\) and \(a_{n+1}=a_n+7\), what is \(a_4\)?
B. (35)
पद (14,21,28,35) हैं इसलिए \(a_4=35\) है। तीन बार (7) जोड़ना है। / The terms are (14,21,28,35), so \(a_4=35\). Exam tip: add (7) three times.
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If \(a_1=6\) and \(a_{n+1}=a_n+10\), what is the value of \(a_3\)?
C. (26)
पद (6,16,26) हैं इसलिए \(a_3=26\) है। समान जोड़ को हर चरण में दोहराएँ। / The terms are (6,16,26), so \(a_3=26\). Exam tip: repeat the constant addition at every step.
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If \(a_1=96\) and \(a_{n+1}=\frac{a_n}{4}\), what is \(a_3\)?
B. (6)
पद (96,24,6) हैं इसलिए \(a_3=6\) है। हर बार पिछले पद को (4) से भाग दें। / The terms are (96,24,6), so \(a_3=6\). Exam tip: divide the previous term by (4) each time.
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If \(a_1=1\), \(a_2=5\), and \(a_n=a_{n-1}+a_{n-2}\), what is \(a_5\)?
C. (17)
पद (1,5,6,11,17) हैं इसलिए \(a_5=17\) है। पिछले दो पदों को सही क्रम में जोड़ें। / The terms are (1,5,6,11,17), so \(a_5=17\). Exam tip: add the previous two terms in the correct order.
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