Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 521-530 of 600 questions.
What is the value of (\(\sqrt{80}+\sqrt{45}\)\(\sqrt{80}-\sqrt{45}\))?
C. (35)
यह \(a^2-b^2\) रूप है। इसलिए मान (80-45=35) है। / This is the \(a^2-b^2\) form. So the value is (80-45=35).
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If \(y=\sqrt{27}+\sqrt{75}\), what is the value of \(\frac{y}{\sqrt{3}}\)?
B. (8)
\(\sqrt{27}=3\sqrt{3}\) और \(\sqrt{75}=5\sqrt{3}\), इसलिए \(y=8\sqrt{3}\) है। भाग देने पर (8) मिलता है। / \(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{75}=5\sqrt{3}\), so \(y=8\sqrt{3}\). Dividing gives (8).
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Which is the simplified form of \(\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}\)?
C. \(2-\sqrt{3}\)
संयुग्मी से गुणा करने पर (\frac{\(\sqrt{6}-\sqrt{2}\)2}{4}=2-\sqrt{3}) मिलता है। हर को परिमेय बनाएं। / Multiplying by the conjugate gives (\frac{\(\sqrt{6}-\sqrt{2}\)2}{4}=2-\sqrt{3}). Make the denominator rational.
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If \(m=\sqrt{180}-\sqrt{80}\) and \(n=2\sqrt{5}\), what is (m-n)?
A. (0)
\(\sqrt{180}=6\sqrt{5}\) और \(\sqrt{80}=4\sqrt{5}\), इसलिए \(m=2\sqrt{5}\) है। अतः (m-n=0) है। / \(\sqrt{180}=6\sqrt{5}\) and \(\sqrt{80}=4\sqrt{5}\), so \(m=2\sqrt{5}\). Hence (m-n=0).
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What is the value of (\sqrt{7}\left\(\sqrt{175}-\sqrt{63}\right\))?
B. (14)
\(\sqrt{175}=5\sqrt{7}\) और \(\sqrt{63}=3\sqrt{7}\), इसलिए कोष्ठक \(2\sqrt{7}\) है। \(\sqrt{7}\) से गुणा करने पर (14) मिलता है। / \(\sqrt{175}=5\sqrt{7}\) and \(\sqrt{63}=3\sqrt{7}\), so the bracket is \(2\sqrt{7}\). Multiplying by \(\sqrt{7}\) gives (14).
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If \(z=\sqrt{23}-\sqrt{14}\), which is the value of \(z^2\)?
C. \(37-2\sqrt{322}\)
(\(\sqrt{23}-\sqrt{14}\)2=23+14-2\sqrt{322}) है। मध्य पद का चिन्ह ऋणात्मक रखें। / (\(\sqrt{23}-\sqrt{14}\)2=23+14-2\sqrt{322}). Keep the middle term negative.
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What is the rationalised form of \(\frac{3}{\sqrt{17}+\sqrt{8}}\)?
C. \(\frac{\sqrt{17}-\sqrt{8}}{3}\)
संयुग्मी से गुणा करने पर हर (17-8=9) बनता है। इसलिए रूप \(\frac{\sqrt{17}-\sqrt{8}}{3}\) है। / Multiplying by the conjugate makes the denominator (17-8=9). So the form is \(\frac{\sqrt{17}-\sqrt{8}}{3}\).
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If \(x=\sqrt{3}+\sqrt{12}\) and \(y=\sqrt{27}\), what is the value of (x-y)?
A. (0)
\(x=\sqrt{3}+2\sqrt{3}=3\sqrt{3}\) और \(y=3\sqrt{3}\) है। इसलिए (x-y=0) है। / \(x=\sqrt{3}+2\sqrt{3}=3\sqrt{3}\) and \(y=3\sqrt{3}\). Therefore (x-y=0).
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Which number definitely lies between \(\sqrt{18}\) and \(\sqrt{20}\)?
C. \(\sqrt{19}\)
क्योंकि (18<19<20), इसलिए \(\sqrt{19}\) दोनों के बीच होगा। वर्गमूलों में अंदर की संख्या से तुलना करें। / Since (18<19<20), \(\sqrt{19}\) lies between them. Compare square roots using the numbers inside.
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If \(u=\sqrt{28}+\sqrt{63}\) and \(v=5\sqrt{7}\), which statement is correct?
C. (u=v)
\(\sqrt{28}=2\sqrt{7}\) और \(\sqrt{63}=3\sqrt{7}\), इसलिए \(u=5\sqrt{7}\) है। अतः (u=v) है। / \(\sqrt{28}=2\sqrt{7}\) and \(\sqrt{63}=3\sqrt{7}\), so \(u=5\sqrt{7}\). Hence (u=v).
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