\(\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}\)?
Explanation opens after your attempt
Correct Answer
C. \(2-\sqrt{3}\)
Concept
Multiplying by the conjugate gives (\frac{\(\sqrt{6}-\sqrt{2}\)2}{4}=2-\sqrt{3}). Make the denominator rational.
Why this answer is correct
The correct answer is C. \(2-\sqrt{3}\). Multiplying by the conjugate gives (\frac{\(\sqrt{6}-\sqrt{2}\)2}{4}=2-\sqrt{3}). Make the denominator rational.
Exam Tip
संयुग्मी से गुणा करने पर (\frac{\(\sqrt{6}-\sqrt{2}\)2}{4}=2-\sqrt{3}) मिलता है। हर को परिमेय बनाएं।
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