Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 231-240 of 600 questions.
For the fractional part function (f(x)={x}), what is the value at (x=-2.3)?
A. (0.7)
\({x}=x-\lfloor x\rfloor\) और \(\lfloor -2.3\rfloor=-3\)। इसलिए ({-2.3}=0.7) है। / \({x}=x-\lfloor x\rfloor\), and \(\lfloor -2.3\rfloor=-3\). Therefore ({-2.3}=0.7).
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What is the value of (f(x)={2x}) at (x=1.35)?
A. (0.7)
(2x=2.7) और ({2.7}=0.7)। भिन्नात्मक भाग पूर्णांक भाग हटाकर मिलता है। / Here (2x=2.7), and ({2.7}=0.7). The fractional part is obtained by removing the integer part.
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What is the (y)-intercept of the line (3x+2y=12)?
A. (6)
(y)-अक्ष पर (x=0), इसलिए (2y=12) और (y=6)। प्रतिच्छेद के लिए दूसरे निर्देशांक को शून्य रखें। / On the (y)-axis, (x=0), so (2y=12) and (y=6). For intercepts, set the other coordinate to zero.
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What is the slope of the line (5x-y=10)?
A. (5)
(5x-y=10) को (y=5x-10) लिखें। इसलिए ढाल (5) है। / Write (5x-y=10) as (y=5x-10). So the slope is (5).
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What is the (x)-intercept of the line (2x-3y=9)?
A. \(x=\frac{9}{2}\)
(x)-अक्ष पर (y=0), इसलिए (2x=9)। इससे \(x=\frac{9}{2}\) मिलता है। / On the (x)-axis, (y=0), so (2x=9). This gives \(x=\frac{9}{2}\).
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What is the slope of a line parallel to \(y=-\frac{3}{4}x+2\)?
A. \(-\frac{3}{4}\)
समांतर रेखाओं की ढाल समान होती है। इसलिए ढाल \(-\frac{3}{4}\) ही रहेगी। / Parallel lines have equal slopes. Therefore the slope remains \(-\frac{3}{4}\).
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What is the (y)-intercept of (f(x)=x-3+3)?
A. (3)
(y)-अक्ष प्रतिच्छेद के लिए (x=0) रखें। तब (f(0)=3) मिलता है। / For the (y)-intercept, put (x=0). Then (f(0)=3).
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What is the central point of (f(x)=(x-2)3+4)?
A. ((2,4))
\(y=x^3\) का केंद्रीय बिंदु ((0,0)) है। यह आलेख (2) दाईं और (4) ऊपर खिसकता है। / The central point of \(y=x^3\) is ((0,0)). This graph shifts (2) right and (4) up.
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What is the (x)-intercept of (f(x)=x-3+27)?
A. (x=-3)
(x)-अक्ष पर \(x^3+27=0\), इसलिए \(x^3=-27\)। इससे (x=-3) मिलता है। / On the (x)-axis, \(x^3+27=0\), so \(x^3=-27\). This gives (x=-3).
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How is the graph of (f(x)=2x-3) compared with \(y=x^3\)?
A. ऊर्ध्व रूप से खिंचा हुआVertically stretched
गुणांक (2) हर (y)-मान को (2) गुना करता है। इसलिए आलेख ऊर्ध्व रूप से खिंचता है। / The coefficient (2) multiplies every (y)-value by (2). So the graph is vertically stretched.
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