फलन (f(x)=x-3+27) का (x)-अक्ष प्रतिच्छेद क्या है?
What is the (x)-intercept of (f(x)=x-3+27)?
Explanation opens after your attempt
A. (x=-3)
Concept
On the (x)-axis, \(x^3+27=0\), so \(x^3=-27\). This gives (x=-3).
Why this answer is correct
The correct answer is A. (x=-3). On the (x)-axis, \(x^3+27=0\), so \(x^3=-27\). This gives (x=-3).
Exam Tip
(x)-अक्ष पर \(x^3+27=0\), इसलिए \(x^3=-27\)। इससे (x=-3) मिलता है।
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