Chemical Reactions and Equations

Correct answer: B. 50 g

According to the law of conservation of mass, total mass is neither created nor destroyed in a chemical reaction. Since the container is closed, no matter leaves or enters it; therefore, the total mass of the products equals the total mass of the reactants, which is 50 g. A value such as 25 g or 0 g would imply that mass has disappeared, which is not possible in this situation.

Correct answer: B. Two

The balanced equation is \(2\mathrm{H}_2 + \mathrm{O}_2 \rightarrow 2\mathrm{H}_2\mathrm{O}\). The reactant side has 4 hydrogen atoms and 2 oxygen atoms. \(2\mathrm{H}_2\mathrm{O}\) also contains 4 hydrogen atoms and 2 oxygen atoms, so 2 water molecules are formed. Writing only 1 water molecule would not balance the atoms.

Correct answer: B. Two

The balanced equation is
2 ext{Mg}+ ext{O}_2
ightarrow2 ext{MgO}
. One
ext{O}_2
molecule contains two oxygen atoms, so two Mg atoms form two units of MgO. Therefore, two magnesium atoms are required. Using only one magnesium atom would leave the equation unbalanced.

Correct answer: B. When the number of atoms of even one element differs on the two sides

According to the law of conservation of mass, a balanced chemical equation has the same number of atoms of each element on the reactant and product sides. If the number of atoms of even one element differs, the equation is unbalanced. Options C and D only state the usual arrangement for writing an equation; they do not by themselves establish that it is balanced.

Correct answer: A. Identity of the substance changes

A subscript is part of a chemical formula and specifies the ratio of atoms in one molecule or formula unit. Changing H₂O to H₂O₂, for instance, changes water into hydrogen peroxide, a different substance. During balancing, only coefficients placed before formulae may be changed because they alter quantities without changing identities. Hence, changing subscripts causes the problem stated in option A.

Correct answer: B. Combination and exothermic

When two or more reactants combine to form a single product, the reaction is a combination reaction. A hot container indicates that heat is released during the reaction, so it is also exothermic. In contrast, in a decomposition reaction, one compound breaks down into two or more substances.

Correct answer: B. It is a combination reaction that forms one product and releases heat.

The reaction is \(\mathrm{CaO + H_2O \rightarrow Ca(OH)_2}\). Calcium oxide and water combine to form only one product, calcium hydroxide, so it is a combination reaction. Heat is released, making it exothermic. In a decomposition reaction, one compound breaks down into two or more products, which does not occur here.

Correct answer: A. Calcium oxide and carbon dioxide

On heating, calcium carbonate undergoes thermal decomposition to form calcium oxide and carbon dioxide:
\(\mathrm{CaCO_3 \xrightarrow{\Delta} CaO + CO_2}\).
Therefore, option A is correct. Option B is incorrect because calcium hydroxide and oxygen are not the products formed by heating calcium carbonate.

Correct answer: A. Nitrogen dioxide and lead oxide

Lead nitrate undergoes thermal decomposition: \(2\mathrm{Pb(NO_3)_2} \xrightarrow{\Delta} 2\mathrm{PbO} + 4\mathrm{NO_2} + \mathrm{O_2}\). Here, \(\mathrm{NO_2}\) is the brown gas and \(\mathrm{PbO}\) is the solid residue. Option B is incorrect because calcium oxide is not formed during the decomposition of lead nitrate.

Correct answer: B. Heat is a condition that starts the reaction

When lead nitrate is heated, it undergoes thermal decomposition: 2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂. Heat is supplied as an external condition to provide the energy needed for decomposition; it is not one of the products. The reaction produces lead oxide, brown nitrogen dioxide gas, and oxygen. Therefore, option B correctly describes the role of heat.

Correct answer: A. Each water molecule contains two hydrogen atoms and one oxygen atom; therefore, hydrogen and oxygen are produced in a 2:1 mole ratio.

The balanced electrolysis equation is \(2H_2O(l) \rightarrow 2H_2(g) + O_2(g)\). Thus, 2 moles of water produce 2 moles of hydrogen and 1 mole of oxygen. At the same temperature and pressure, gas volume is proportional to the number of moles, so the volume ratio of hydrogen to oxygen is \(2:1\). Option B is incorrect because, at the same temperature and pressure, gas volume depends on the number of moles, not on molecular mass.

Correct answer: A. Displacement reaction

Iron is more reactive than copper, so it displaces copper from copper sulphate: \(\mathrm{Fe + CuSO_4 \rightarrow FeSO_4 + Cu}\). The iron sulphate solution is light green, and the reddish-brown deposit on the nail is copper. Unlike a combination reaction, two substances do not combine to form one product; iron replaces copper.

Correct answer: A. Silver

In sunlight, silver chloride undergoes photodecomposition: \(2\mathrm{AgCl}\xrightarrow{\text{sunlight}}2\mathrm{Ag}+\mathrm{Cl}_2\). The metallic silver formed is grey, so silver chloride appears grey. Chlorine is also produced, but it does not cause the grey colour.

Correct answer: A. To prevent decomposition caused by light

Silver chloride is photosensitive. In sunlight, it undergoes photodecomposition to form silver and chlorine:
\[2\mathrm{AgCl}(s)\xrightarrow{\text{sunlight}}2\mathrm{Ag}(s)+\mathrm{Cl_2}(g)\]
A dark-coloured bottle reduces exposure to light and therefore helps prevent this decomposition. Option B refers to thermal decomposition, whereas light is the cause of decomposition in this case.

Correct answer: A. \(2AgCl \xrightarrow{sunlight} 2Ag + Cl_2\)

Silver chloride decomposes in sunlight to form silver and chlorine gas: \(2AgCl \xrightarrow{sunlight} 2Ag + Cl_2\). Therefore, it is a photochemical decomposition reaction. In options B and D, heat provides the energy for decomposition, whereas in option C, electricity does so.

Correct answer: A. Iron sulphate

Iron is more reactive than copper, so it displaces copper from copper sulphate solution. The balanced reaction is Fe + CuSO₄ → FeSO₄ + Cu. The sulphate ion remains associated with iron, producing iron sulphate, while copper is deposited as a reddish-brown solid. Copper sulphate is the reactant, and sodium or barium sulphate is not formed. Therefore, option A is correct.

Correct answer: A. Copper is less reactive than zinc

A displacement reaction occurs only when the metal placed in the solution is more reactive than the metal ion present in it. Zinc is above copper in the reactivity series, so copper is less reactive and \(\text{Cu} + \text{ZnSO}_4\) gives no reaction. Unlike option B, copper cannot displace zinc ions from zinc sulphate solution to form zinc metal.

Correct answer: A. Barium sulphate is insoluble in water

The reaction is \(\mathrm{BaCl_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaCl(aq)}\). In solution, \(\mathrm{Ba^{2+}}\) and \(\mathrm{SO_4^{2-}}\) ions combine to form insoluble \(\mathrm{BaSO_4}\), which separates as a solid precipitate. \(\mathrm{NaCl}\) remains soluble in water, so it does not form the precipitate.

Correct answer: A. \(\mathrm{Na_2SO_4(aq) + BaCl_2(aq) \rightarrow BaSO_4(s) + 2NaCl(aq)}\)

In a double displacement reaction, the ions of two ionic compounds exchange partners. In option A, \(\mathrm{Na^+}\) and \(\mathrm{Ba^{2+}}\) form new ionic pairs with the anions, producing insoluble \(\mathrm{BaSO_4}\) as a precipitate. Option B is a single displacement reaction because zinc displaces copper from its salt.

Correct answer: A. BaCl_2(aq) + Na_2SO_4(aq) → BaSO_4(s) + 2NaCl(aq)

In reaction A, Ba^{2+} and Na^+ exchange partners, so it is a double displacement reaction. Insoluble white BaSO_4 forms as a precipitate, so it is also a precipitation reaction. In contrast, option B is a combination/oxidation reaction of magnesium, not an exchange of ions.

Correct answer: A. Copper

The correct answer is copper. On heating, hydrogen removes oxygen from black copper(II) oxide, reducing it to copper: \(\mathrm{CuO + H_2 \rightarrow Cu + H_2O}\). The copper formed is reddish-brown. Copper(II) sulphate, chloride, or carbonate cannot form because no source of sulphate, chloride, or carbonate ions is present in the reaction.

Correct answer: B. Hydrogen

The reaction is CuO + H₂ → Cu + H₂O. Hydrogen combines with oxygen from copper(II) oxide to form water, so hydrogen gains oxygen and is oxidised. Copper(II) oxide loses oxygen and becomes copper, so it is reduced. The copper and water shown among the options are products rather than the substance undergoing oxidation. Therefore, option B is correct.

Correct answer: C. Copper(II) oxide

The reaction is \(\mathrm{CuO + H_2 \rightarrow Cu + H_2O}\). Oxygen is removed from copper(II) oxide to form copper. Removal of oxygen is reduction, so copper(II) oxide is reduced. In contrast, hydrogen gains oxygen to form water and is oxidised. Copper is the product of reduction, not the reactant that undergoes reduction.

Correct answer: B. Redox reaction

Oxidation traditionally means addition of oxygen, while reduction means removal of oxygen. If these two processes occur simultaneously in the same reaction, the reaction is called a redox reaction, meaning reduction and oxidation together. A precipitation reaction forms an insoluble solid, an exothermic reaction releases heat, and a displacement reaction concerns replacement of one element by another. Hence, option B is correct.

Correct answer: B. Reduction

Reduction is defined, in the oxygen-transfer sense, as removal of oxygen from a substance or addition of hydrogen to it. For example, CuO + H₂ → Cu + H₂O involves removal of oxygen from copper(II) oxide and addition of oxygen to hydrogen. Oxidation is generally the reverse process, while combustion and precipitation describe different reaction features. Therefore, option B is correct.