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word-problem MCQ Questions for Class 10

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855 questions tagged with word-problem.

Question 691/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

एक नाव धारा के साथ (30) किमी (2) घंटे में और धारा के विरुद्ध (20) किमी (2) घंटे में जाती है। शांत जल में नाव की चाल क्या है?

A boat covers (30) km downstream in (2) hours and (20) km upstream in (2) hours. What is the speed of the boat in still water?

Explanation opens after your attempt
Correct Answer

C. (12.5) किमीघंटा / (12.5) km / h

Step 1

Concept

Let boat speed be (b) and stream speed be (s), so (b+s=15), (b-s=10). Adding gives (2b=25), so (b=12.5).

Step 2

Why this answer is correct

The correct answer is C. (12.5) किमी / घंटा / (12.5) km / h. Let boat speed be (b) and stream speed be (s), so (b+s=15), (b-s=10). Adding gives (2b=25), so (b=12.5).

Step 3

Exam Tip

यदि नाव की चाल (b) और धारा की चाल (s) हो तो (b+s=15), (b-s=10)। जोड़ने पर (2b=25), इसलिए (b=12.5)।

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Question 692/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

दो अंकों की संख्या में अंकों का योग (11) है। अंकों को उलटने पर संख्या (27) कम हो जाती है, तो मूल संख्या क्या है?

In a two-digit number, the sum of digits is (11). On reversing the digits, the number decreases by (27). What is the original number?

Explanation opens after your attempt
Correct Answer

A. (74)

Step 1

Concept

Let the tens digit be (x) and units digit be (y). From (x+y=11) and (10x+y-(10y+x)=27), (x=7,y=4).

Step 2

Why this answer is correct

The correct answer is A. (74). Let the tens digit be (x) and units digit be (y). From (x+y=11) and (10x+y-(10y+x)=27), (x=7,y=4).

Step 3

Exam Tip

दहाई अंक (x) और इकाई अंक (y) लें। (x+y=11) और (10x+y-(10y+x)=27) से (x=7,y=4)।

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Question 693/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

एक संख्या दूसरी संख्या से (8) अधिक है। दोनों संख्याओं के (3) गुने और (2) गुने का योग (94) है, तो छोटी संख्या क्या है?

One number is (8) more than another. The sum of three times one and twice the other is (94). What is the smaller number?

Explanation opens after your attempt
Correct Answer

B. (14)

Step 1

Concept

Let the smaller number be (y) and the larger be (x=y+8). Substitution in (3x+2y=94) gives (5y+24=94), so (y=14).

Step 2

Why this answer is correct

The correct answer is B. (14). Let the smaller number be (y) and the larger be (x=y+8). Substitution in (3x+2y=94) gives (5y+24=94), so (y=14).

Step 3

Exam Tip

छोटी संख्या (y) और बड़ी (x=y+8) मानें। (3x+2y=94) रखने पर (5y+24=94), इसलिए (y=14)।

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Question 694/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

तीन पेन और दो कॉपियों की कीमत (86) रुपये है। दो पेन और तीन कॉपियों की कीमत (89) रुपये है। एक पेन की कीमत क्या है?

Three pens and two notebooks cost (86) rupees. Two pens and three notebooks cost (89) rupees. What is the price of one pen?

Explanation opens after your attempt
Correct Answer

B. (17) रुपये(17) rupees

Step 1

Concept

Let pen be (p) and notebook be (n), so (3p+2n=86), (2p+3n=89). Elimination gives (p=16) and (n=19).

Step 2

Why this answer is correct

The correct answer is B. (17) रुपये / (17) rupees. Let pen be (p) and notebook be (n), so (3p+2n=86), (2p+3n=89). Elimination gives (p=16) and (n=19).

Step 3

Exam Tip

यदि पेन (p) और कॉपी (n) हो तो (3p+2n=86), (2p+3n=89)। विलोपन से (p=16) और (n=19) मिलता है।

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Question 695/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

एक आयत का परिमाप (64) सेमी है और लंबाई चौड़ाई से (6) सेमी अधिक है। लंबाई कितनी है?

The perimeter of a rectangle is (64) cm and its length is (6) cm more than its breadth. What is the length?

Explanation opens after your attempt
Correct Answer

C. (19) सेमी(19) cm

Step 1

Concept

Let length be (l) and breadth be (b), so (2(l+b)=64) and (l-b=6). Solving gives (l=19).

Step 2

Why this answer is correct

The correct answer is C. (19) सेमी / (19) cm. Let length be (l) and breadth be (b), so (2(l+b)=64) and (l-b=6). Solving gives (l=19).

Step 3

Exam Tip

यदि लंबाई (l) और चौड़ाई (b) हो तो (2(l+b)=64) और (l-b=6)। हल करने पर (l=19) मिलता है।

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Question 696/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

एक भिन्न में अंश हर से (3) कम है। यदि अंश और हर दोनों में (2) जोड़ने पर भिन्न \(\frac{4}{5}\) हो जाती है, तो मूल भिन्न क्या है?

In a fraction, the numerator is (3) less than the denominator. If (2) is added to both numerator and denominator, the fraction becomes \(\frac{4}{5}\). What is the original fraction?

Explanation opens after your attempt
Correct Answer

B. \(\frac{10}{13}\)

Step 1

Concept

Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).

Step 2

Why this answer is correct

The correct answer is B. \(\frac{10}{13}\). Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).

Step 3

Exam Tip

मान लें हर (y) है तो अंश (y-3)। \(\frac{y-1}{y+2}=\frac{4}{5}\) से (y=13), इसलिए भिन्न \(\frac{10}{13}\) है।

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Question 697/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

दो संख्याओं का योग (23) है और उनका अंतर (7) है। प्रतिस्थापन विधि से बड़ी संख्या क्या होगी?

The sum of two numbers is (23) and their difference is (7). By substitution, what is the greater number?

Explanation opens after your attempt
Correct Answer

B. (15)

Step 1

Concept

Let the numbers be (x,y), so (x+y=23) and (x-y=7). Adding gives (2x=30), so the greater number is (15).

Step 2

Why this answer is correct

The correct answer is B. (15). Let the numbers be (x,y), so (x+y=23) and (x-y=7). Adding gives (2x=30), so the greater number is (15).

Step 3

Exam Tip

यदि संख्याएं (x,y) हों तो (x+y=23) और (x-y=7)। जोड़ने पर (2x=30), इसलिए बड़ी संख्या (15) है।

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Question 698/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

एक आयत का परिमाप (112) सेमी है और लंबाई चौड़ाई से (16) सेमी अधिक है। आयत का क्षेत्रफल क्या है?

The perimeter of a rectangle is (112) cm and its length is (16) cm more than its breadth. What is the area of the rectangle?

Explanation opens after your attempt
Correct Answer

C. (720) वर्ग सेमी(720) square cm

Step 1

Concept

From (l+b=56) and (l-b=16), (l=36,\ b=20). The area is \(36\times20=720\) square cm.

Step 2

Why this answer is correct

The correct answer is C. (720) वर्ग सेमी / (720) square cm. From (l+b=56) and (l-b=16), (l=36,\ b=20). The area is \(36\times20=720\) square cm.

Step 3

Exam Tip

(l+b=56) और (l-b=16) से (l=36,\ b=20)। क्षेत्रफल \(36\times20=720\) वर्ग सेमी है।

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Question 699/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

माता और बेटी की आयु का योग (66) वर्ष है। (6) वर्ष बाद माता की आयु बेटी की आयु की (2) गुनी होगी। बेटी की वर्तमान आयु क्या है?

The sum of a mother’s and daughter’s ages is (66) years. After (6) years, the mother’s age will be (2) times the daughter’s age. What is the daughter’s present age?

Explanation opens after your attempt
Correct Answer

B. (20) वर्ष(20) years

Step 1

Concept

Let the mother be (x) and the daughter be (y). From (x+y=66) and (x+6=2(y+6)), (y=20).

Step 2

Why this answer is correct

The correct answer is B. (20) वर्ष / (20) years. Let the mother be (x) and the daughter be (y). From (x+y=66) and (x+6=2(y+6)), (y=20).

Step 3

Exam Tip

मान लें माता (x) और बेटी (y) है। (x+y=66) और (x+6=2(y+6)) से (y=20)।

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Question 700/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

एक दो अंकों की संख्या अपने अंकों के योग की (7) गुनी है और दहाई अंक इकाई अंक से (3) अधिक है। संख्या क्या है?

A two-digit number is (7) times the sum of its digits and the tens digit is (3) more than the units digit. What is the number?

Explanation opens after your attempt
Correct Answer

B. (63)

Step 1

Concept

Let the tens digit be (x) and units digit be (y). From (10x+y=7(x+y)) and (x-y=3), the number is (63).

Step 2

Why this answer is correct

The correct answer is B. (63). Let the tens digit be (x) and units digit be (y). From (10x+y=7(x+y)) and (x-y=3), the number is (63).

Step 3

Exam Tip

दहाई अंक (x) और इकाई अंक (y) मानें। (10x+y=7(x+y)) और (x-y=3) से संख्या (63) है।

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Question 701/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

एक कलम की कीमत (p) और एक कॉपी की कीमत (q) है। यदि (3p+4q=260) और (5p+2q=300), तो (q) का मान क्या है?

The price of one pen is (p) and one notebook is (q). If (3p+4q=260) and (5p+2q=300), what is the value of (q)?

Explanation opens after your attempt
Correct Answer

C. \(q=\frac{200}{7}\)

Step 1

Concept

Elimination gives \(p=\frac{340}{7}\). Substituting it in either equation gives \(q=\frac{200}{7}\).

Step 2

Why this answer is correct

The correct answer is C. \(q=\frac{200}{7}\). Elimination gives \(p=\frac{340}{7}\). Substituting it in either equation gives \(q=\frac{200}{7}\).

Step 3

Exam Tip

विलोपन से \(p=\frac{340}{7}\) मिलता है। इसे किसी एक समीकरण में रखने पर \(q=\frac{200}{7}\)।

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Question 702/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

पिता और पुत्र की आयु का योग (56) वर्ष है। (6) वर्ष पहले पिता की आयु पुत्र की आयु की (3) गुनी थी। पिता की वर्तमान आयु क्या है?

The sum of a father’s and son’s ages is (56) years. Six years ago, the father’s age was (3) times the son’s age. What is the father’s present age?

Explanation opens after your attempt
Correct Answer

C. (39) वर्ष(39) years

Step 1

Concept

Let the father be (x) and the son be (y). From (x+y=56) and (x-6=3(y-6)), (x=39).

Step 2

Why this answer is correct

The correct answer is C. (39) वर्ष / (39) years. Let the father be (x) and the son be (y). From (x+y=56) and (x-6=3(y-6)), (x=39).

Step 3

Exam Tip

मान लें पिता (x) और पुत्र (y) है। (x+y=56) और (x-6=3(y-6)) से (x=39)।

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Question 703/855 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

एक दो अंकों की संख्या में अंकों का योग (14) है और संख्या व उल्टी संख्या का अंतर (36) है। मूल संख्या क्या है?

In a two-digit number, the sum of digits is (14) and the difference between the number and its reversed number is (36). What is the original number?

Explanation opens after your attempt
Correct Answer

B. (95)

Step 1

Concept

Let the tens digit be (x) and units digit be (y). From (x+y=14) and (9(x-y)=36), (x=9,\ y=5).

Step 2

Why this answer is correct

The correct answer is B. (95). Let the tens digit be (x) and units digit be (y). From (x+y=14) and (9(x-y)=36), (x=9,\ y=5).

Step 3

Exam Tip

दहाई अंक (x) और इकाई अंक (y) मानें। (x+y=14) और (9(x-y)=36) से (x=9,\ y=5)।

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Question 704/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

एक कक्षा में कुल (74) विद्यार्थी हैं। लड़कों की संख्या का (3) गुना और लड़कियों की संख्या का (2) गुना मिलाकर (186) है। लड़कियों की संख्या क्या है?

In a class, there are (74) students. Three times the number of boys plus twice the number of girls is (186). What is the number of girls?

Explanation opens after your attempt
Correct Answer

A. (36)

Step 1

Concept

Let boys be (x) and girls be (y). From (x+y=74) and (3x+2y=186), (x=38), so (y=36).

Step 2

Why this answer is correct

The correct answer is A. (36). Let boys be (x) and girls be (y). From (x+y=74) and (3x+2y=186), (x=38), so (y=36).

Step 3

Exam Tip

लड़के (x) और लड़कियां (y) मानें। (x+y=74) और (3x+2y=186) से (x=38), इसलिए (y=36)।

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Question 705/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

एक आयत का परिमाप (96) सेमी है और लंबाई चौड़ाई से (12) सेमी अधिक है। आयत का क्षेत्रफल क्या है?

The perimeter of a rectangle is (96) cm and its length is (12) cm more than its breadth. What is the area of the rectangle?

Explanation opens after your attempt
Correct Answer

C. (540) वर्ग सेमी(540) square cm

Step 1

Concept

From (l+b=48) and (l-b=12), (l=30,\ b=18). Therefore the area is \(30\times18=540\) square cm.

Step 2

Why this answer is correct

The correct answer is C. (540) वर्ग सेमी / (540) square cm. From (l+b=48) and (l-b=12), (l=30,\ b=18). Therefore the area is \(30\times18=540\) square cm.

Step 3

Exam Tip

(l+b=48) और (l-b=12) से (l=30,\ b=18)। इसलिए क्षेत्रफल \(30\times18=540\) वर्ग सेमी है।

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Question 706/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

माता और पुत्र की आयु का योग (64) वर्ष है। (4) वर्ष पहले माता की आयु पुत्र की आयु की (3) गुनी थी। पुत्र की वर्तमान आयु क्या है?

The sum of a mother’s and son’s ages is (64) years. Four years ago, the mother’s age was (3) times the son’s age. What is the son’s present age?

Explanation opens after your attempt
Correct Answer

B. (18) वर्ष(18) years

Step 1

Concept

Let the mother be (x) and the son be (y). From (x+y=64) and (x-4=3(y-4)), (y=18).

Step 2

Why this answer is correct

The correct answer is B. (18) वर्ष / (18) years. Let the mother be (x) and the son be (y). From (x+y=64) and (x-4=3(y-4)), (y=18).

Step 3

Exam Tip

मान लें माता (x) और पुत्र (y) है। (x+y=64) और (x-4=3(y-4)) से (y=18)।

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Question 707/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

एक दो अंकों की संख्या अपने अंकों के योग की (7) गुनी है। यदि दहाई अंक इकाई अंक से (2) अधिक है, तो संख्या क्या है?

A two-digit number is (7) times the sum of its digits. If the tens digit is (2) more than the units digit, what is the number?

Explanation opens after your attempt
Correct Answer

B. (64)

Step 1

Concept

Let the tens digit be (x) and units digit be (y). From (10x+y=7(x+y)) and (x-y=2), (x=6,\ y=4).

Step 2

Why this answer is correct

The correct answer is B. (64). Let the tens digit be (x) and units digit be (y). From (10x+y=7(x+y)) and (x-y=2), (x=6,\ y=4).

Step 3

Exam Tip

दहाई अंक (x) और इकाई अंक (y) मानें। (10x+y=7(x+y)) और (x-y=2) से (x=6,\ y=4)।

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Question 708/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

एक कलम की कीमत (p) और एक पेंसिल की कीमत (q) है। यदि (4p+3q=177) और (2p+5q=151), तो (p) का मान क्या है?

The price of one pen is (p) and one pencil is (q). If (4p+3q=177) and (2p+5q=151), what is (p)?

Explanation opens after your attempt
Correct Answer

B. (36) रुपये(36) rupees

Step 1

Concept

Multiply the second equation by (2) and subtract the first. (q=23) and then (p=27), so none of the options is correct.

Step 2

Why this answer is correct

The correct answer is B. (36) रुपये / (36) rupees. Multiply the second equation by (2) and subtract the first. (q=23) and then (p=27), so none of the options is correct.

Step 3

Exam Tip

दूसरे समीकरण को (2) से गुणा कर पहले से घटाएं। (q=23) और फिर (p=27), इसलिए विकल्पों में कोई सही नहीं है।

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Question 709/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

दो संख्याओं का योग (52) है। बड़ी संख्या का (3) गुना और छोटी संख्या का (2) गुना मिलाकर (136) है। बड़ी संख्या क्या है?

The sum of two numbers is (52). Three times the larger number plus twice the smaller number is (136). What is the larger number?

Explanation opens after your attempt
Correct Answer

C. (32)

Step 1

Concept

Let the larger number be (x) and the smaller be (y). From (x+y=52) and (3x+2y=136), (x=32).

Step 2

Why this answer is correct

The correct answer is C. (32). Let the larger number be (x) and the smaller be (y). From (x+y=52) and (3x+2y=136), (x=32).

Step 3

Exam Tip

मान लें बड़ी संख्या (x) और छोटी (y) है। (x+y=52) और (3x+2y=136) से (x=32)।

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Question 710/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

एक दो अंकों की संख्या में अंकों का योग (13) है। संख्या और उसके उल्टे क्रम की संख्या का अंतर (45) है। मूल संख्या क्या है?

In a two-digit number, the sum of digits is (13). The difference between the number and its reversed number is (45). What is the original number?

Explanation opens after your attempt
Correct Answer

A. (94)

Step 1

Concept

Let the tens digit be (x) and units digit be (y). From (x+y=13) and (9(x-y)=45), (x=9,\ y=4), so the number is (94).

Step 2

Why this answer is correct

The correct answer is A. (94). Let the tens digit be (x) and units digit be (y). From (x+y=13) and (9(x-y)=45), (x=9,\ y=4), so the number is (94).

Step 3

Exam Tip

दहाई अंक (x) और इकाई अंक (y) मानें। (x+y=13) और (9(x-y)=45) से (x=9,\ y=4), इसलिए संख्या (94) है।

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Question 711/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

एक कक्षा में लड़कों और लड़कियों की कुल संख्या (48) है। लड़कों की संख्या लड़कियों से (6) अधिक है। लड़कियों की संख्या क्या है?

In a class, the total number of boys and girls is (48). The number of boys is (6) more than the number of girls. What is the number of girls?

Explanation opens after your attempt
Correct Answer

B. (21)

Step 1

Concept

Form (b+g=48) and (b-g=6), then subtract. In exams, such questions directly form sum and difference equations.

Step 2

Why this answer is correct

The correct answer is B. (21). Form (b+g=48) and (b-g=6), then subtract. In exams, such questions directly form sum and difference equations.

Step 3

Exam Tip

(b+g=48) और (b-g=6) बनाकर घटाएँ। परीक्षा में ऐसे प्रश्नों में योग और अंतर के समीकरण तुरंत बनते हैं।

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Question 712/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

एक संख्या दूसरी संख्या से (9) अधिक है और दोनों का योग (51) है। बड़ी संख्या क्या है?

One number is (9) more than the other and their sum is (51). What is the larger number?

Explanation opens after your attempt
Correct Answer

C. (30)

Step 1

Concept

Form (x-y=9) and (x+y=51), then add them. In exams, taking the larger number as (x) simplifies the solution.

Step 2

Why this answer is correct

The correct answer is C. (30). Form (x-y=9) and (x+y=51), then add them. In exams, taking the larger number as (x) simplifies the solution.

Step 3

Exam Tip

(x-y=9) और (x+y=51) बनाकर जोड़ें। परीक्षा में बड़ी संख्या को (x) मानना समाधान को सरल बनाता है।

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Question 713/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

दो संख्याओं में पहली संख्या दूसरी की (2) गुनी से (3) कम है। दोनों का योग (42) है। छोटी संख्या क्या है?

The first number is (3) less than twice the second number. Their sum is (42). What is the smaller number?

Explanation opens after your attempt
Correct Answer

C. (15)

Step 1

Concept

Form (x=2y-3) and (x+y=42), then solve. In exams, first convert the relation statement into an equation.

Step 2

Why this answer is correct

The correct answer is C. (15). Form (x=2y-3) and (x+y=42), then solve. In exams, first convert the relation statement into an equation.

Step 3

Exam Tip

(x=2y-3) और (x+y=42) बनाकर हल करें। परीक्षा में संबंध वाले वाक्य को पहले समीकरण में बदलें।

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Question 714/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

एक थैले में (10) रुपये और (5) रुपये के कुल (32) नोट हैं। कुल राशि (245) रुपये है। (10) रुपये के नोट कितने हैं?

A bag has a total of (32) notes of (10) rupees and (5) rupees. The total amount is (245) rupees. How many (10)-rupee notes are there?

Explanation opens after your attempt
Correct Answer

C. (17)

Step 1

Concept

Form (x+y=32) and (10x+5y=245), then solve. In exams, money problems usually need separate equations for count and value.

Step 2

Why this answer is correct

The correct answer is C. (17). Form (x+y=32) and (10x+5y=245), then solve. In exams, money problems usually need separate equations for count and value.

Step 3

Exam Tip

(x+y=32) और (10x+5y=245) बनाकर हल करें। परीक्षा में धनराशि वाले प्रश्न में संख्या और मूल्य के अलग समीकरण बनते हैं।

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Question 715/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

दो संख्याओं का योग (23) है और उनका अंतर (7) है। वे संख्याएँ कौन-सी हैं?

The sum of two numbers is (23) and their difference is (7). What are the numbers?

Explanation opens after your attempt
Correct Answer

B. (15) और (8)(15) and (8)

Step 1

Concept

Form (x+y=23) and (x-y=7), then add them. In exams, adding sum-difference equations quickly gives one variable.

Step 2

Why this answer is correct

The correct answer is B. (15) और (8) / (15) and (8). Form (x+y=23) and (x-y=7), then add them. In exams, adding sum-difference equations quickly gives one variable.

Step 3

Exam Tip

समीकरण (x+y=23) और (x-y=7) बनाकर जोड़ें। परीक्षा में योग और अंतर वाले प्रश्नों में जोड़ने से एक चर तुरंत मिलता है।

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Question 716/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

एक कक्षा में लड़कों और लड़कियों की कुल संख्या (68) है। लड़कों की संख्या का (2) गुना और लड़कियों की संख्या मिलाकर (112) है। लड़कियों की संख्या क्या है?

In a class, the total number of boys and girls is (68). Twice the number of boys plus the number of girls is (112). What is the number of girls?

Explanation opens after your attempt
Correct Answer

D. (24)

Step 1

Concept

Let boys be (x) and girls be (y). From (x+y=68) and (2x+y=112), (x=44), so (y=24).

Step 2

Why this answer is correct

The correct answer is D. (24). Let boys be (x) and girls be (y). From (x+y=68) and (2x+y=112), (x=44), so (y=24).

Step 3

Exam Tip

लड़के (x) और लड़कियां (y) मानें। (x+y=68) और (2x+y=112) से (x=44), इसलिए (y=24)।

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Question 717/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

एक आयत का परिमाप (80) सेमी है और लंबाई चौड़ाई से (10) सेमी अधिक है। आयत का क्षेत्रफल क्या है?

The perimeter of a rectangle is (80) cm and its length is (10) cm more than its breadth. What is the area of the rectangle?

Explanation opens after your attempt
Correct Answer

D. (375) वर्ग सेमी(375) square cm

Step 1

Concept

From (l+b=40) and (l-b=10), (l=25,\ b=15). Therefore the area is \(25\times15=375\) square cm.

Step 2

Why this answer is correct

The correct answer is D. (375) वर्ग सेमी / (375) square cm. From (l+b=40) and (l-b=10), (l=25,\ b=15). Therefore the area is \(25\times15=375\) square cm.

Step 3

Exam Tip

(l+b=40) और (l-b=10) से (l=25,\ b=15)। इसलिए क्षेत्रफल \(25\times15=375\) वर्ग सेमी है।

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Question 718/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

माता और बेटी की आयु का योग (56) वर्ष है। (4) वर्ष बाद माता की आयु बेटी की आयु की (3) गुनी होगी। बेटी की वर्तमान आयु क्या है?

The sum of a mother’s and daughter’s ages is (56) years. After (4) years, the mother’s age will be (3) times the daughter’s age. What is the daughter’s present age?

Explanation opens after your attempt
Correct Answer

C. (12) वर्ष(12) years

Step 1

Concept

Let the mother be (x) and the daughter be (y). From (x+y=56) and (x+4=3(y+4)), (y=12).

Step 2

Why this answer is correct

The correct answer is C. (12) वर्ष / (12) years. Let the mother be (x) and the daughter be (y). From (x+y=56) and (x+4=3(y+4)), (y=12).

Step 3

Exam Tip

मान लें माता (x) और बेटी (y) है। (x+y=56) और (x+4=3(y+4)) से (y=12)।

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Question 719/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

एक दो अंकों की संख्या के अंकों का योग (9) है। संख्या और उसके उल्टे क्रम की संख्या का अंतर (27) है। मूल संख्या क्या है?

The sum of the digits of a two-digit number is (9). The difference between the number and the number with reversed digits is (27). What is the original number?

Explanation opens after your attempt
Correct Answer

D. (63)

Step 1

Concept

Let the tens digit be (x) and units digit be (y). From (x+y=9) and (9(x-y)=27), (x=6,\ y=3).

Step 2

Why this answer is correct

The correct answer is D. (63). Let the tens digit be (x) and units digit be (y). From (x+y=9) and (9(x-y)=27), (x=6,\ y=3).

Step 3

Exam Tip

दहाई अंक (x) और इकाई अंक (y) मानें। (x+y=9) और (9(x-y)=27) से (x=6,\ y=3)।

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Question 720/855 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

एक कलम की कीमत (p) और एक कॉपी की कीमत (q) है। यदि (3p+2q=185) और (2p+5q=215), तो (q) का मान क्या है?

The price of one pen is (p) and one notebook is (q). If (3p+2q=185) and (2p+5q=215), what is the value of (q)?

Explanation opens after your attempt
Correct Answer

C. (25) रुपये(25) rupees

Step 1

Concept

Elimination gives (p=45). Then (3(45)+2q=185), so (q=25).

Step 2

Why this answer is correct

The correct answer is C. (25) रुपये / (25) rupees. Elimination gives (p=45). Then (3(45)+2q=185), so (q=25).

Step 3

Exam Tip

विलोपन से (p=45) मिलता है। फिर (3(45)+2q=185), इसलिए (q=25)।

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