The perimeter of a rectangle is (96) cm and its length is (12) cm more than its breadth. What is the area of the rectangle?

540

Let the length and breadth of the rectangle be \(l\) cm and \(b\) cm. Since the perimeter is \(96\) cm, \(2(l+b)=96\), so \(l+b=48\). Also, \(l-b=12\). Adding these equations gives \(2l=60\), hence \(l=30\) and \(b=18\). Therefore, the area is \(l\times b=30\times18=540\) square cm. Option 560 does not correspond to this required pair of length and breadth. Exam tip: In perimeter questions, first divide \(2(l+b)\) by 2 to obtain \(l+b\).

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Algebraic methods: Substitution method and Elimination method..