Concept-wise Practice

forming equation MCQ Questions for Class 10

forming equation se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

39 questions tagged with forming equation.

Question 31/39 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

किस विकल्प में (x=1) और (x=4) मूल हैं?

Which option has roots (x=1) and (x=4)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-5x+4=0\)

Step 1

Concept

If the roots are (1) and (4), the factors are ((x-1)) and ((x-4)). Their product gives \(x^2-5x+4=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-5x+4=0\). If the roots are (1) and (4), the factors are ((x-1)) and ((x-4)). Their product gives \(x^2-5x+4=0\).

Step 3

Exam Tip

मूल (1) और (4) हों तो गुणनखंड ((x-1)) और ((x-4)) होंगे। इनका गुणन \(x^2-5x+4=0\) देता है।

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Question 32/39 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि किसी द्विघात समीकरण में (a=2), (b=-7), (c=3) हैं, तो समीकरण कौन-सा है?

If a quadratic equation has (a=2), (b=-7), (c=3), which equation is it?

Explanation opens after your attempt
Correct Answer

B. \(2x^2-7x+3=0\)

Step 1

Concept

Substituting in \(ax^2+bx+c=0\) gives \(2x^2-7x+3=0\). Keep the negative sign of (b).

Step 2

Why this answer is correct

The correct answer is B. \(2x^2-7x+3=0\). Substituting in \(ax^2+bx+c=0\) gives \(2x^2-7x+3=0\). Keep the negative sign of (b).

Step 3

Exam Tip

मानक रूप \(ax^2+bx+c=0\) में मान रखने पर \(2x^2-7x+3=0\) मिलता है। (b) का ऋण चिन्ह साथ रखें।

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Question 33/39 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि (a=3,\ b=0,\ c=-12) हैं तो संबंधित द्विघात समीकरण कौन-सा है?

If (a=3,\ b=0,\ c=-12), which is the corresponding quadratic equation?

Explanation opens after your attempt
Correct Answer

A. \(3x^2-12=0\)

Step 1

Concept

Substituting in \(ax^2+bx+c=0\) gives \(3x^2+0x-12=0\). Simplifying gives \(3x^2-12=0\).

Step 2

Why this answer is correct

The correct answer is A. \(3x^2-12=0\). Substituting in \(ax^2+bx+c=0\) gives \(3x^2+0x-12=0\). Simplifying gives \(3x^2-12=0\).

Step 3

Exam Tip

मानक रूप \(ax^2+bx+c=0\) में मान रखने पर \(3x^2+0x-12=0\) मिलता है। इसे सरल करने पर \(3x^2-12=0\) है।

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Question 34/39 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

जिन मूलों में (0) और (-3) हों उनके लिए सही द्विघात समीकरण कौन-सा है?

Which quadratic equation has roots (0) and (-3)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+3x=0\)

Step 1

Concept

For roots (0) and (-3), the factors are (x) and (x+3). So the equation is (x(x+3)=0), that is \(x^2+3x=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2+3x=0\). For roots (0) and (-3), the factors are (x) and (x+3). So the equation is (x(x+3)=0), that is \(x^2+3x=0\).

Step 3

Exam Tip

मूल (0) और (-3) होने पर गुणनखंड (x) और (x+3) होंगे। इसलिए समीकरण (x(x+3)=0) यानी \(x^2+3x=0\) है।

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Question 35/39 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

किसी संख्या का वर्ग उस संख्या के (5) गुने से (6) अधिक है। यदि संख्या (x) है तो समीकरण क्या होगा?

The square of a number is (6) more than (5) times the number. If the number is (x), what is the equation?

Explanation opens after your attempt
Correct Answer

A. \(x^2=5x+6\)

Step 1

Concept

The square is \(x^2\), and (6) more than (5) times the number is (5x+6). So the equation is \(x^2=5x+6\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2=5x+6\). The square is \(x^2\), and (6) more than (5) times the number is (5x+6). So the equation is \(x^2=5x+6\).

Step 3

Exam Tip

संख्या का वर्ग \(x^2\) और (5) गुने से (6) अधिक (5x+6) है। इसलिए समीकरण \(x^2=5x+6\) बनेगा।

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Question 36/39 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि (a=2), (b=0), (c=-18) हैं तो समीकरण क्या होगा?

If (a=2), (b=0), (c=-18), what is the equation?

Explanation opens after your attempt
Correct Answer

A. \(2x^2-18=0\)

Step 1

Concept

Substituting in standard form gives \(2x^2+0x-18=0\). This is written as \(2x^2-18=0\).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-18=0\). Substituting in standard form gives \(2x^2+0x-18=0\). This is written as \(2x^2-18=0\).

Step 3

Exam Tip

मानक रूप में रखने पर \(2x^2+0x-18=0\) मिलता है। इसे \(2x^2-18=0\) लिखते हैं।

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Question 37/39 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

कौन सा रूप (a=3), (b=-4), (c=-2) को दर्शाता है?

Which form represents (a=3), (b=-4), (c=-2)?

Explanation opens after your attempt
Correct Answer

A. \(3x^2-4x-2=0\)

Step 1

Concept

Putting the values in \(ax^2+bx+c=0\) gives \(3x^2-4x-2=0\). Watch the sign of (b).

Step 2

Why this answer is correct

The correct answer is A. \(3x^2-4x-2=0\). Putting the values in \(ax^2+bx+c=0\) gives \(3x^2-4x-2=0\). Watch the sign of (b).

Step 3

Exam Tip

मानक रूप \(ax^2+bx+c=0\) में मान रखने पर \(3x^2-4x-2=0\) मिलता है। (b) का चिन्ह ध्यान रखें।

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Question 38/39 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि (a=1), (b=0), (c=-25) हैं तो समीकरण क्या होगा?

If (a=1), (b=0), (c=-25), what is the equation?

Explanation opens after your attempt
Correct Answer

A. \(x^2-25=0\)

Step 1

Concept

Substituting in \(ax^2+bx+c=0\) gives \(x^2+0x-25=0\). This is written as \(x^2-25=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-25=0\). Substituting in \(ax^2+bx+c=0\) gives \(x^2+0x-25=0\). This is written as \(x^2-25=0\).

Step 3

Exam Tip

\(ax^2+bx+c=0\) में रखने पर \(x^2+0x-25=0\) मिलता है। इसे \(x^2-25=0\) लिखते हैं।

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Question 39/39 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

कौन सा रूप \(ax^2+bx+c=0\) में (a=2), (b=-5), (c=3) को दर्शाता है?

Which form represents (a=2), (b=-5), (c=3) in \(ax^2+bx+c=0\)?

Explanation opens after your attempt
Correct Answer

A. \(2x^2-5x+3=0\)

Step 1

Concept

Putting the given values in standard form gives \(2x^2-5x+3=0\). Keep the sign of (b) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-5x+3=0\). Putting the given values in standard form gives \(2x^2-5x+3=0\). Keep the sign of (b) carefully.

Step 3

Exam Tip

दिए गए मान सीधे मानक रूप में रखने पर \(2x^2-5x+3=0\) मिलता है। (b) का चिन्ह ध्यान रखें।

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