Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
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Showing 541-550 of 600 questions.
Find the sum of natural numbers from (151) to (225).
B. (14100)
योग \(S_{225}-S_{150}=25425-11325=14100\) है। \(S_b-S_{a-1}\) विधि प्रयोग करें। / The sum is \(S_{225}-S_{150}=25425-11325=14100\). Use the \(S_b-S_{a-1}\) method.
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If \(S_n+S_{n-1}=1260\) and \(S_n-S_{n-1}=36\), which is the value of \(S_n\)?
B. (648)
दोनों समीकरण जोड़ने पर \(2S_n=1296\), इसलिए \(S_n=648\)। समीकरणों को जोड़कर \(S_n\) जल्दी मिलता है। / Adding the two equations gives \(2S_n=1296\), so \(S_n=648\). Adding equations gives \(S_n\) quickly.
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If \(S_{n+1}-S_{n-2}=330\), what will be the value of (n)?
C. (110)
(S_{n+1}-S_{n-2}=(n-1)+n+(n+1)=3n)। (3n=330) से (n=110)। / (S_{n+1}-S_{n-2}=(n-1)+n+(n+1)=3n). From (3n=330), (n=110).
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B. (180)
\(S_{180}-S_{179}=180\) होता है। क्रमिक योगों का अंतर अगला पद होता है। / \(S_{180}-S_{179}=180\). The difference of consecutive sums is the next term.
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What is the difference between the sum from (1) to (250) and the sum from (1) to (200)?
B. (11275)
\(S_{250}-S_{200}=31375-20100=11275\)। यह (201) से (250) तक का योग है। / \(S_{250}-S_{200}=31375-20100=11275\). This is the sum from (201) to (250).
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If \(S_n=7626\), what is the value of \(S_{n+2}\)?
A. (7875)
\(7626=S_{123}\), इसलिए \(S_{125}=\frac{125\cdot126}{2}=7875\)। पहले (n) पहचानें फिर (2) आगे बढ़ें। / \(7626=S_{123}\), so \(S_{125}=\frac{125\cdot126}{2}=7875\). First identify (n) and then move (2) ahead.
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If \(S_n-S_{n-1}=150\), what will be \(S_{n-1}\)?
A. (11175)
\(S_n-S_{n-1}=n\), इसलिए (n=150) और \(S_{149}=\frac{149\cdot150}{2}=11175\)। पिछले योग के लिए (n-1) लें। / \(S_n-S_{n-1}=n\), so (n=150) and \(S_{149}=\frac{149\cdot150}{2}=11175\). For the previous sum, take (n-1).
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What is (40%) of the sum of the first (125) natural numbers?
A. (3150)
\(S_{125}=7875\) और \(40%=\frac{2}{5}\), इसलिए मान (3150) है। प्रतिशत को भिन्न में बदलें। / \(S_{125}=7875\) and \(40%=\frac{2}{5}\), so the value is (3150). Convert percentage into a fraction.
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If \(S_n=25425\), what will be the value of (n)?
C. (225)
\(\frac{225\cdot226}{2}=25425\), इसलिए (n=225)। सूत्र में विकल्प रखकर उत्तर जांचें। / \(\frac{225\cdot226}{2}=25425\), so (n=225). Check the answer by substituting options in the formula.
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If \(S_n-S_{n-6}=861\), what will be the value of (n)?
D. (146)
(S_n-S_{n-6}=(n-5)+(n-4)+(n-3)+(n-2)+(n-1)+n=6n-15)। (6n-15=861) से (n=146)। / (S_n-S_{n-6}=(n-5)+(n-4)+(n-3)+(n-2)+(n-1)+n=6n-15). From (6n-15=861), (n=146).
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