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If the sum of the first n natural numbers is Sₙ = 25,425, what is the value of n?

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Answer and explanation

Correct answer: 225

The sum of the first n natural numbers is S_n=n(n+1)/2. Substituting the given sum gives n(n+1)/2=25425, so n(n+1)=50850. We need a consecutive pair of integers whose product is 50,850. Because n must be a natural number, checking the nearby option values is sufficient.

For n=225, n+1=226, and 225 times 226/2=225 times 113=25425. Thus the given sum is obtained exactly, so option C is correct. The neighboring values 224 and 226 would give different sums. The result is also sensible because the sum is approximately n^2/2, placing n near 225.

Related tags

SequencesProgressionsSum-Of-Natural-NumbersArithmetic-FormulaSum Of First N Natural NumbersSequences And ProgressionsMathematicsClass 9 Mcq

Frequently asked questions

What is the correct answer to this question?

225

Why is this the correct answer?

The sum of the first n natural numbers is S_n=n(n+1)/2. Substituting the given sum gives n(n+1)/2=25425, so n(n+1)=50850. We need a consecutive pair of integers whose product is 50,850. Because n must be a natural number, checking the nearby option values is sufficient.

For n=225, n+1=226, and 225 times 226/2=225 times 113=25425. Thus the given sum is obtained exactly, so option C is correct. The neighboring values 224 and 226 would give different sums. The result is also sensible because the sum is approximately n^2/2, placing n near 225.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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