Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 461-470 of 600 questions.
If \(x=\sqrt{2}-1\) then what is (x\(\sqrt{2}+1\))?
A. 1
((a-b)(a+b)=a-2-b-2)। उत्तर (2-1=1) है। / Use ((a-b)(a+b)=a-2-b-2). The result is (2-1=1).
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B. \(\frac{2}{7},-4\)
भिन्न और पूर्णांक दोनों परिमेय हैं। संख्या के प्रकार पहचानें। / Fractions and integers are rational. Identify number types.
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What is the simplified form of \(\sqrt{45}+\sqrt{80}\)?
A. \(13\sqrt{5}\)
\(\sqrt{45}=3\sqrt{5}\) और \(\sqrt{80}=4\sqrt{5}\)। योग \(7\sqrt{5}\) है। / \(\sqrt{45}=3\sqrt{5}\) and \(\sqrt{80}=4\sqrt{5}\). Sum is \(7\sqrt{5}\).
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If \(x=\sqrt{11}\) then what is \(x^2+5\)?
B. 16
\(x^2=11\) इसलिए उत्तर 16 है। पहले वर्ग निकालें। / \(x^2=11\), so the answer is 16. Evaluate the square first.
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C. 1
1 का मान अन्य सभी से कम है। अनुमानित मान उपयोग करें। / 1 is smaller than all others. Use approximate values.
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If \(a=\sqrt{8}\) then what is \(a^2\)?
C. 8
वर्गमूल का वर्ग मूल संख्या देता है। उत्तर 8 है। / The square of a square root gives the original number. Answer is 8.
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What is the simplified form of \(\sqrt{200}\)?
A. \(10\sqrt{2}\)
\(200=100\times2\) इसलिए \(\sqrt{200}=10\sqrt{2}\)। पूर्ण वर्ग अलग करें। / \(200=100\times2\), so \(\sqrt{200}=10\sqrt{2}\). Extract perfect squares.
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If \(x=\sqrt{5}+\sqrt{5}\) then what is (x)?
C. \(2\sqrt{5}\)
समान मूलों के गुणांक जोड़े जाते हैं। उत्तर \(2\sqrt{5}\) है। / Add coefficients of like surds. Result is \(2\sqrt{5}\).
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B. \(\frac{9}{32}\)
हर में केवल 2 के गुणनखंड हैं। इसलिए दशमलव समाप्त होगा। / The denominator has only factor 2. Hence the decimal terminates.
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If \(x=\sqrt{13}\) then what type of number is (x)?
C. अपरिमेयIrrational
13 पूर्ण वर्ग नहीं है। इसलिए \(\sqrt{13}\) अपरिमेय है। / 13 is not a perfect square. Hence \(\sqrt{13}\) is irrational.
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