Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 621-630 of 651 questions.
What is the square of \(\sqrt{16+\sqrt{45}}\) equal to?
D. \(16+\sqrt{45}\)
वर्गमूल का वर्ग अंदर की संख्या देता है। इसलिए (\left\(\sqrt{16+\sqrt{45}}\right\)2=16+\sqrt{45}) है। / The square of a square root gives the number inside. So (\left\(\sqrt{16+\sqrt{45}}\right\)2=16+\sqrt{45}).
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B. (19)
क्षेत्रफल (\(\sqrt{30}+\sqrt{11}\)\(\sqrt{30}-\sqrt{11}\)=30-11=19) है। संयुग्मी आयामों से परिमेय क्षेत्रफल मिलता है। / Area is (\(\sqrt{30}+\sqrt{11}\)\(\sqrt{30}-\sqrt{11}\)=30-11=19). Conjugate dimensions give rational area.
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What is the value of (\(\sqrt{112}+\sqrt{63}\)\(\sqrt{112}-\sqrt{63}\))?
C. (49)
यह \(a^2-b^2\) रूप है। इसलिए मान (112-63=49) है। / This is the \(a^2-b^2\) form. So the value is (112-63=49).
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If \(y=\sqrt{75}+\sqrt{147}\), what is the value of \(\frac{y}{\sqrt{3}}\)?
B. (12)
\(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{147}=7\sqrt{3}\), इसलिए \(y=12\sqrt{3}\) है। भाग देने पर (12) मिलता है। / \(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{147}=7\sqrt{3}\), so \(y=12\sqrt{3}\). Dividing gives (12).
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Which is the simplified form of \(\frac{\sqrt{10}-\sqrt{6}}{\sqrt{10}+\sqrt{6}}\)?
C. \(4-\sqrt{15}\)
संयुग्मी से गुणा करने पर (\frac{\(\sqrt{10}-\sqrt{6}\)2}{4}=4-\sqrt{15}) मिलता है। हर को परिमेय बनाएं। / Multiplying by the conjugate gives (\frac{\(\sqrt{10}-\sqrt{6}\)2}{4}=4-\sqrt{15}). Make the denominator rational.
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If \(m=\sqrt{245}-\sqrt{125}\) and \(n=2\sqrt{5}\), what is (m-n)?
A. (0)
\(\sqrt{245}=7\sqrt{5}\) और \(\sqrt{125}=5\sqrt{5}\), इसलिए \(m=2\sqrt{5}\) है। अतः (m-n=0) है। / \(\sqrt{245}=7\sqrt{5}\) and \(\sqrt{125}=5\sqrt{5}\), so \(m=2\sqrt{5}\). Hence (m-n=0).
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What is the value of (\sqrt{11}\left\(\sqrt{539}-\sqrt{275}\right\))?
B. (22)
\(\sqrt{539}=7\sqrt{11}\) और \(\sqrt{275}=5\sqrt{11}\), इसलिए कोष्ठक \(2\sqrt{11}\) है। \(\sqrt{11}\) से गुणा करने पर (22) मिलता है। / \(\sqrt{539}=7\sqrt{11}\) and \(\sqrt{275}=5\sqrt{11}\), so the bracket is \(2\sqrt{11}\). Multiplying by \(\sqrt{11}\) gives (22).
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If \(z=\sqrt{29}-\sqrt{18}\), which is the value of \(z^2\)?
C. \(47-2\sqrt{522}\)
(\(\sqrt{29}-\sqrt{18}\)2=29+18-2\sqrt{522}) है। मध्य पद का चिन्ह ऋणात्मक रखें। / (\(\sqrt{29}-\sqrt{18}\)2=29+18-2\sqrt{522}). Keep the middle term negative.
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What is the rationalised form of \(\frac{5}{\sqrt{26}+\sqrt{17}}\)?
C. (\frac{5\(\sqrt{26}-\sqrt{17}\)}{9})
संयुग्मी से गुणा करने पर हर (26-17=9) बनता है। इसलिए रूप (\frac{5\(\sqrt{26}-\sqrt{17}\)}{9}) है। / Multiplying by the conjugate makes the denominator (26-17=9). So the form is (\frac{5\(\sqrt{26}-\sqrt{17}\)}{9}).
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If \(x=\sqrt{5}+\sqrt{45}\) and \(y=\sqrt{80}\), what is the value of (x-y)?
A. (0)
\(x=\sqrt{5}+3\sqrt{5}=4\sqrt{5}\) और \(y=4\sqrt{5}\) है। इसलिए (x-y=0) है। / \(x=\sqrt{5}+3\sqrt{5}=4\sqrt{5}\) and \(y=4\sqrt{5}\). Therefore (x-y=0).
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