\(\sqrt{16+\sqrt{45}}\) का वर्ग किसके बराबर है?
What is the square of \(\sqrt{16+\sqrt{45}}\) equal to?
Explanation opens after your attempt
D. \(16+\sqrt{45}\)
Concept
The square of a square root gives the number inside. So (\left\(\sqrt{16+\sqrt{45}}\right\)2=16+\sqrt{45}).
Why this answer is correct
The correct answer is D. \(16+\sqrt{45}\). The square of a square root gives the number inside. So (\left\(\sqrt{16+\sqrt{45}}\right\)2=16+\sqrt{45}).
Exam Tip
वर्गमूल का वर्ग अंदर की संख्या देता है। इसलिए (\left\(\sqrt{16+\sqrt{45}}\right\)2=16+\sqrt{45}) है।
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