यदि एक आयत की लंबाई \(\sqrt{30}+\sqrt{11}\) और चौड़ाई \(\sqrt{30}-\sqrt{11}\) है तो क्षेत्रफल क्या होगा?
If a rectangle has length \(\sqrt{30}+\sqrt{11}\) and breadth \(\sqrt{30}-\sqrt{11}\), what will be its area?
Explanation opens after your attempt
Correct Answer
B. (19)
Concept
Area is (\(\sqrt{30}+\sqrt{11}\)\(\sqrt{30}-\sqrt{11}\)=30-11=19). Conjugate dimensions give rational area.
Why this answer is correct
The correct answer is B. (19). Area is (\(\sqrt{30}+\sqrt{11}\)\(\sqrt{30}-\sqrt{11}\)=30-11=19). Conjugate dimensions give rational area.
Exam Tip
क्षेत्रफल (\(\sqrt{30}+\sqrt{11}\)\(\sqrt{30}-\sqrt{11}\)=30-11=19) है। संयुग्मी आयामों से परिमेय क्षेत्रफल मिलता है।
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