Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 171-180 of 600 questions.
What is the value of \(\sqrt{12}\times\sqrt{27}\)?
B. (18)
\(\sqrt{12}\times\sqrt{27}=\sqrt{324}=18\) है। दो अपरिमेयों का गुणनफल परिमेय हो सकता है। / \(\sqrt{12}\times\sqrt{27}=\sqrt{324}=18\). The product of two irrationals can be rational.
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Which statement is correct about \(\sqrt{2}+\sqrt{3}\)?
C. यह अपरिमेय हैIt is irrational
\(\sqrt{2}\) और \(\sqrt{3}\) अलग अपरिमेय मूल हैं और उनका योग अपरिमेय है। इसे \(\sqrt{5}\) नहीं लिखते। / \(\sqrt{2}\) and \(\sqrt{3}\) are different irrational radicals and their sum is irrational. It is not written as \(\sqrt{5}\).
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Which is the simplified form of \(\sqrt{200}\)?
A. \(10\sqrt{2}\)
\(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\) है। बड़े पूर्ण वर्ग गुणनखंड से हल छोटा होता है। / \(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\). Using a large perfect-square factor makes the solution shorter.
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What is the simplified value of \(\frac{\sqrt{80}}{\sqrt{5}}\)?
B. (4)
\(\frac{\sqrt{80}}{\sqrt{5}}=\sqrt{16}=4\) है। भाग में मूलों को मिलाकर सरल करें। / \(\frac{\sqrt{80}}{\sqrt{5}}=\sqrt{16}=4\). Combine roots in division and simplify.
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Which option is a non-terminating and repeating decimal?
A. \(0.123123123\ldots\)
(123) बार-बार दोहरता है इसलिए यह आवर्ती और परिमेय है। आवर्ती दशमलव अपरिमेय नहीं होता। / (123) repeats again and again, so it is repeating and rational. A repeating decimal is not irrational.
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What is the result of \(5\sqrt{3}-2\sqrt{3}\)?
C. \(3\sqrt{3}\)
समान मूलों के गुणांक घटाने पर \(3\sqrt{3}\) मिलता है। यह अपरिमेय है। / Subtracting coefficients of like radicals gives \(3\sqrt{3}\). It is irrational.
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What is the value of (\sqrt{3}\(\sqrt{3}+\sqrt{12}\))?
D. (9)
\(\sqrt{12}=2\sqrt{3}\), इसलिए अंदर \(3\sqrt{3}\) है और गुणनफल (9) है। पहले कोष्ठक को सरल करें। / \(\sqrt{12}=2\sqrt{3}\), so the bracket is \(3\sqrt{3}\) and the product is (9). Simplify the bracket first.
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Which statement is correct when comparing \(\sqrt{17}\) and \(\sqrt{18}\)?
A. \(\sqrt{17}<\sqrt{18}\)
क्योंकि (17<18), इसलिए \(\sqrt{17}<\sqrt{18}\)। धनात्मक मूलों की तुलना अंदर की संख्या से करें। / Since (17<18), \(\sqrt{17}<\sqrt{18}\). Compare positive roots using the numbers inside.
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What is the simplified form of (\sqrt{2}\times\(3\sqrt{2}+1\))?
B. \(6+\sqrt{2}\)
वितरण करने पर \(3\times2+\sqrt{2}=6+\sqrt{2}\) मिलता है। मूल का गुणन ध्यान से करें। / Distributing gives \(3\times2+\sqrt{2}=6+\sqrt{2}\). Multiply radical terms carefully.
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Which is the rationalised form of \(\frac{3}{\sqrt{2}+1}\)?
C. \(3\sqrt{2}-3\)
हर के संयुग्मी \(\sqrt{2}-1\) से गुणा करने पर (3\(\sqrt{2}-1\)) मिलता है। इसलिए रूप \(3\sqrt{2}-3\) है। / Multiplying by the conjugate \(\sqrt{2}-1\) gives (3\(\sqrt{2}-1\)). So the form is \(3\sqrt{2}-3\).
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