(\sqrt{3}\(\sqrt{3}+\sqrt{12}\)) का मान क्या है?

What is the value of (\sqrt{3}\(\sqrt{3}+\sqrt{12}\))?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

D. (9)

Step 1

Concept

\(\sqrt{12}=2\sqrt{3}\), so the bracket is \(3\sqrt{3}\) and the product is (9). Simplify the bracket first.

Step 2

Why this answer is correct

The correct answer is D. (9). \(\sqrt{12}=2\sqrt{3}\), so the bracket is \(3\sqrt{3}\) and the product is (9). Simplify the bracket first.

Step 3

Exam Tip

\(\sqrt{12}=2\sqrt{3}\), इसलिए अंदर \(3\sqrt{3}\) है और गुणनफल (9) है। पहले कोष्ठक को सरल करें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

(\sqrt{3}\(\sqrt{3}+\sqrt{12}\)) का मान क्या है? / What is the value of (\sqrt{3}\(\sqrt{3}+\sqrt{12}\))?

Correct Answer: D. (9). Explanation: \(\sqrt{12}=2\sqrt{3}\), इसलिए अंदर \(3\sqrt{3}\) है और गुणनफल (9) है। पहले कोष्ठक को सरल करें। / \(\sqrt{12}=2\sqrt{3}\), so the bracket is \(3\sqrt{3}\) and the product is (9). Simplify the bracket first.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{12}=2\sqrt{3}\), so the bracket is \(3\sqrt{3}\) and the product is (9). Simplify the bracket first.

What exam hint can help solve this Mathematics question?

\(\sqrt{12}=2\sqrt{3}\), इसलिए अंदर \(3\sqrt{3}\) है और गुणनफल (9) है। पहले कोष्ठक को सरल करें।