Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 91-100 of 600 questions.
A. (3)
दोनों पुस्तकें हिंदी होनी हैं इसलिए \(\binom{3}{2}=3\) तरीके हैं। शर्त पढ़कर सही समूह चुनें। / Both books must be Hindi, so there are \(\binom{3}{2}=3\) ways. Read the condition and choose the correct group.
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C. (30)
तरीके \(\binom{4}{2}\binom{5}{1}=6\cdot5=30\) हैं। अलग श्रेणियों का चयन गुणा से जुड़ता है। / The ways are \(\binom{4}{2}\binom{5}{1}=6\cdot5=30\). Selections from different categories are multiplied.
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C. (100)
तरीके \(\binom{5}{1}\binom{6}{3}=5\cdot20=100\) हैं। पहले शर्तों को अलग करें फिर गुणा करें। / The ways are \(\binom{5}{1}\binom{6}{3}=5\cdot20=100\). Separate the conditions first and then multiply.
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How many ways are there to choose exactly (2) sweets from (6) sweets?
B. (15)
ठीक (2) चुनने का अर्थ \(\binom{6}{2}\) है। इसका मान (15) है। / Choosing exactly (2) means \(\binom{6}{2}\). Its value is (15).
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B. (36)
स्थान तय नहीं है इसलिए केवल रंगों का चयन है। तरीके \(\binom{9}{2}=36\) हैं। / Positions are not fixed, so only colors are selected. The ways are \(\binom{9}{2}=36\).
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What is the total number of ways to choose (0) gifts or (1) gift from (10) different gifts?
B. (11)
कुल तरीके \(\binom{10}{0}+\binom{10}{1}=1+10=11\) हैं। (0) चयन को भी शामिल करें। / Total ways are \(\binom{10}{0}+\binom{10}{1}=1+10=11\). Include the (0) selection too.
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How many ways are there to choose exactly (4) chapters from (7) chapters for revision?
B. (35)
अध्यायों का क्रम नहीं पूछा गया है। इसलिए \(\binom{7}{4}=35\) होगा। / The order of chapters is not asked. Therefore \(\binom{7}{4}=35\).
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In how many ways can (2) questions be left out from (11) questions?
B. (55)
छोड़ने के लिए (2) प्रश्न चुनने हैं। इसलिए \(\binom{11}{2}=55\) तरीके हैं। / We need to choose (2) questions to leave out. Hence there are \(\binom{11}{2}=55\) ways.
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Selecting (9) students from (12) students is equal to not selecting how many students from (12)?
B. (3)
\(\binom{12}{9}=\binom{12}{3}\) होता है। (9) चुनना (3) न चुनने के बराबर है। / \(\binom{12}{9}=\binom{12}{3}\). Selecting (9) is the same as not selecting (3).
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C. (46)
कुल \(\binom{8}{3}=56\) हैं और केवल लड़के \(\binom{5}{3}=10\) हैं। इसलिए (56-10=46) तरीके हैं। / Total ways are \(\binom{8}{3}=56\), and all-boy selections are \(\binom{5}{3}=10\). Therefore (56-10=46) ways.
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