Concept-wise Practice

surd product MCQ Questions for Class 10

surd product se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with surd product.

यदि \(a=\sqrt{13}+\sqrt{6}\) और \(b=\sqrt{13}-\sqrt{6}\), तो (ab) का मान क्या है?

If \(a=\sqrt{13}+\sqrt{6}\) and \(b=\sqrt{13}-\sqrt{6}\), what is the value of (ab)?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

(ab=13-6=7). In exams conjugate multiplication removes radicals.

Step 2

Why this answer is correct

The correct answer is A. (7). (ab=13-6=7). In exams conjugate multiplication removes radicals.

Step 3

Exam Tip

(ab=13-6=7) है। परीक्षा में संयुग्मी गुणन से मूल हट जाते हैं।

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यदि \(x=\sqrt{3}+\sqrt{2}\), तो (\(x-\sqrt{3}\)\(x-\sqrt{2}\)) का मान क्या है?

If \(x=\sqrt{3}+\sqrt{2}\), what is the value of (\(x-\sqrt{3}\)\(x-\sqrt{2}\))?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{6}\)

Step 1

Concept

\(x-\sqrt{3}=\sqrt{2}\) and \(x-\sqrt{2}=\sqrt{3}\).

Step 2

Why this answer is correct

Their product is \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\).

Step 3

Exam Tip

Simplify the small brackets first. चरण 1: \(x-\sqrt{3}=\sqrt{2}\) और \(x-\sqrt{2}=\sqrt{3}\)। चरण 2: उनका गुणन \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) है। चरण 3: पहले छोटे-छोटे कोष्ठकों को सरल करें।

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