यदि \(x=\sqrt{3}+\sqrt{2}\), तो (\(x-\sqrt{3}\)\(x-\sqrt{2}\)) का मान क्या है?

If \(x=\sqrt{3}+\sqrt{2}\), what is the value of (\(x-\sqrt{3}\)\(x-\sqrt{2}\))?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{6}\)

Step 1

Concept

\(x-\sqrt{3}=\sqrt{2}\) and \(x-\sqrt{2}=\sqrt{3}\).

Step 2

Why this answer is correct

Their product is \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\).

Step 3

Exam Tip

Simplify the small brackets first. चरण 1: \(x-\sqrt{3}=\sqrt{2}\) और \(x-\sqrt{2}=\sqrt{3}\)। चरण 2: उनका गुणन \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) है। चरण 3: पहले छोटे-छोटे कोष्ठकों को सरल करें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{3}+\sqrt{2}\), तो (\(x-\sqrt{3}\)\(x-\sqrt{2}\)) का मान क्या है? / If \(x=\sqrt{3}+\sqrt{2}\), what is the value of (\(x-\sqrt{3}\)\(x-\sqrt{2}\))?

Correct Answer: A. \(\sqrt{6}\). Explanation: चरण 1: \(x-\sqrt{3}=\sqrt{2}\) और \(x-\sqrt{2}=\sqrt{3}\)। चरण 2: उनका गुणन \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) है। चरण 3: पहले छोटे-छोटे कोष्ठकों को सरल करें। / Step 1: \(x-\sqrt{3}=\sqrt{2}\) and \(x-\sqrt{2}=\sqrt{3}\). Step 2: Their product is \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\). Step 3: Simplify the small brackets first.

Which concept should I revise for this Mathematics MCQ?

\(x-\sqrt{3}=\sqrt{2}\) and \(x-\sqrt{2}=\sqrt{3}\).

What exam hint can help solve this Mathematics question?

Simplify the small brackets first. चरण 1: \(x-\sqrt{3}=\sqrt{2}\) और \(x-\sqrt{2}=\sqrt{3}\)। चरण 2: उनका गुणन \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) है। चरण 3: पहले छोटे-छोटे कोष्ठकों को सरल करें।