किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times11\) है?
Which number has prime factorisation \(2^3\times3^2\times11\)?
#evaluate-factorisation
#number-792
#medium
A 792
B 396
C 1188
D 1584
Explanation opens after your attempt
Step 1
Concept
\(2^3=8\) और \(3^2=9\) निकालें। / Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times11=792\)। / \(8\times9\times11=792\).
Step 3
Exam Tip
पहले घातों को हल करें, फिर 11 से गुणा करें। / First solve the powers, then multiply by 11.
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यदि \(3888=2^p\times3^5\), तो (p) का मान क्या है?
If \(3888=2^p\times3^5\), what is the value of (p)?
#exponent-comparison
#number-3888
#medium
A 4
B 3
C 5
D 6
Explanation opens after your attempt
Step 1
Concept
\(3888=16\times243\) लिखें। / Write \(3888=16\times243\).
Step 2
Why this answer is correct
\(16=2^4\) और \(243=3^5\), इसलिए 2 की घात 4 है। / \(16=2^4\) and \(243=3^5\), so the power of 2 is 4.
Step 3
Exam Tip
तुलना करने पर (p=4) मिलेगा। / Comparing gives (p=4).
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यदि \(2450=2\times5^m\times7^2\), तो (m) का मान क्या है?
If \(2450=2\times5^m\times7^2\), what is the value of (m)?
#exponent-comparison
#number-2450
#medium
A 2
B 1
C 3
D 4
Explanation opens after your attempt
Step 1
Concept
\(2450=2\times1225\) है। / \(2450=2\times1225\).
Step 2
Why this answer is correct
\(1225=5^2\times7^2\), इसलिए \(2450=2\times5^2\times7^2\)। / \(1225=5^2\times7^2\), so \(2450=2\times5^2\times7^2\).
Step 3
Exam Tip
दिए गए रूप से तुलना करने पर (m=2) होगा। / Comparing with the given form gives (m=2).
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यदि \(2205=3^b\times5\times7^2\), तो (b) का मान क्या है?
If \(2205=3^b\times5\times7^2\), what is the value of (b)?
#exponent-comparison
#number-2205
#medium
A 2
B 1
C 3
D 4
Explanation opens after your attempt
Step 1
Concept
\(2205=45\times49\) है। / \(2205=45\times49\).
Step 2
Why this answer is correct
\(45=3^2\times5\) और \(49=7^2\), इसलिए \(2205=3^2\times5\times7^2\)। / \(45=3^2\times5\) and \(49=7^2\), so \(2205=3^2\times5\times7^2\).
Step 3
Exam Tip
तुलना करने पर (b=2) है। / Comparing gives (b=2).
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यदि \(2016=2^a\times3^2\times7\), तो (a) का मान क्या है?
If \(2016=2^a\times3^2\times7\), what is the value of (a)?
#exponent-comparison
#number-2016
#medium
A 5
B 4
C 6
D 3
Explanation opens after your attempt
Step 1
Concept
\(2016=32\times63\) लिखें। / Write \(2016=32\times63\).
Step 2
Why this answer is correct
\(32=2^5\) और \(63=3^2\times7\), इसलिए \(2016=2^5\times3^2\times7\)। / \(32=2^5\) and \(63=3^2\times7\), so \(2016=2^5\times3^2\times7\).
Step 3
Exam Tip
तुलना करने पर (a=5) है। / Comparing gives (a=5).
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संख्या 3969 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 3969?
#prime-factorisation
#number-3969
#medium
A \(3^4\times7^2\)
B \(3^3\times7^2\)
C \(81\times49\)
D \(63\times63\)
Explanation opens after your attempt
Correct Answer
A. \(3^4\times7^2\)
Step 1
Concept
\(3969=81\times49\) लिखें। / Write \(3969=81\times49\).
Step 2
Why this answer is correct
\(81=3^4\) और \(49=7^2\), इसलिए \(3969=3^4\times7^2\)। / \(81=3^4\) and \(49=7^2\), so \(3969=3^4\times7^2\).
Step 3
Exam Tip
दोनों भागों को अभाज्य घातों में लिखें। / Write both parts as prime powers.
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संख्या 3888 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 3888?
#prime-factorisation
#number-3888
#medium
A \(2^4\times3^5\)
B \(2^3\times3^5\)
C \(16\times243\)
D \(2^4\times243\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3^5\)
Step 1
Concept
\(3888=16\times243\) लिखें। / Write \(3888=16\times243\).
Step 2
Why this answer is correct
\(16=2^4\) और \(243=3^5\), इसलिए \(3888=2^4\times3^5\)। / \(16=2^4\) and \(243=3^5\), so \(3888=2^4\times3^5\).
Step 3
Exam Tip
243 को 3 की घात में बदलें। / Change 243 into a power of 3.
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संख्या 3645 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 3645?
#prime-factorisation
#number-3645
#medium
A \(3^6\times5\)
B \(3^5\times5\)
C \(729\times5\)
D \(81\times45\)
Explanation opens after your attempt
Correct Answer
A. \(3^6\times5\)
Step 1
Concept
\(3645=729\times5\) लिखें। / Write \(3645=729\times5\).
Step 2
Why this answer is correct
\(729=3^6\), इसलिए \(3645=3^6\times5\)। / Since \(729=3^6\), \(3645=3^6\times5\).
Step 3
Exam Tip
729 को अंतिम रूप में नहीं छोड़ना चाहिए। / 729 should not be left in the final form.
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संख्या 3528 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 3528?
#prime-factorisation
#number-3528
#medium
A \(2^3\times3^2\times7^2\)
B \(2^2\times3^2\times7^2\)
C \(72\times49\)
D \(8\times441\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^2\times7^2\)
Step 1
Concept
\(3528=72\times49\) लिखें। / Write \(3528=72\times49\).
Step 2
Why this answer is correct
\(72=2^3\times3^2\) और \(49=7^2\), इसलिए \(3528=2^3\times3^2\times7^2\)। / \(72=2^3\times3^2\) and \(49=7^2\), so \(3528=2^3\times3^2\times7^2\).
Step 3
Exam Tip
72 और 49 को अभाज्य घातों में बदलें। / Convert 72 and 49 into prime powers.
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संख्या 3402 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 3402?
#prime-factorisation
#number-3402
#medium
A \(2\times3^5\times7\)
B \(2\times3^4\times7\)
C \(2\times1701\)
D \(486\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^5\times7\)
Step 1
Concept
\(3402=2\times1701\) लिखें। / Write \(3402=2\times1701\).
Step 2
Why this answer is correct
\(1701=3^5\times7\), इसलिए \(3402=2\times3^5\times7\)। / \(1701=3^5\times7\), so \(3402=2\times3^5\times7\).
Step 3
Exam Tip
1701 को 3 और 7 के अभाज्य रूप में बदलें। / Convert 1701 into prime form using 3 and 7.
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संख्या 3120 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 3120?
#prime-factorisation
#number-3120
#medium
A \(2^4\times3\times5\times13\)
B \(2^3\times3\times5\times13\)
C \(312\times10\)
D \(16\times195\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3\times5\times13\)
Step 1
Concept
\(3120=16\times195\) लिखें। / Write \(3120=16\times195\).
Step 2
Why this answer is correct
\(16=2^4\) और \(195=3\times5\times13\), इसलिए \(3120=2^4\times3\times5\times13\)। / \(16=2^4\) and \(195=3\times5\times13\), so \(3120=2^4\times3\times5\times13\).
Step 3
Exam Tip
195 को पूरा अभाज्य रूप दें। / Give 195 its complete prime form.
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संख्या 2835 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 2835?
#prime-factorisation
#number-2835
#medium
A \(3^4\times5\times7\)
B \(3^3\times5\times7\)
C \(81\times35\)
D \(9\times315\)
Explanation opens after your attempt
Correct Answer
A. \(3^4\times5\times7\)
Step 1
Concept
\(2835=81\times35\) लिखें। / Write \(2835=81\times35\).
Step 2
Why this answer is correct
\(81=3^4\) और \(35=5\times7\), इसलिए \(2835=3^4\times5\times7\)। / \(81=3^4\) and \(35=5\times7\), so \(2835=3^4\times5\times7\).
Step 3
Exam Tip
81 को \(3^4\) में बदलें। / Change 81 into \(3^4\).
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संख्या 2640 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 2640?
#prime-factorisation
#number-2640
#medium
A \(2^4\times3\times5\times11\)
B \(2^3\times3\times5\times11\)
C \(24\times110\)
D \(16\times165\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3\times5\times11\)
Step 1
Concept
\(2640=16\times165\) लिखें। / Write \(2640=16\times165\).
Step 2
Why this answer is correct
\(16=2^4\) और \(165=3\times5\times11\), इसलिए \(2640=2^4\times3\times5\times11\)। / \(16=2^4\) and \(165=3\times5\times11\), so \(2640=2^4\times3\times5\times11\).
Step 3
Exam Tip
165 को आगे तोड़ें। / Break 165 further.
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संख्या 2450 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 2450?
#prime-factorisation
#number-2450
#medium
A \(2\times5^2\times7^2\)
B \(2^2\times5\times7^2\)
C \(2\times1225\)
D \(50\times49\)
Explanation opens after your attempt
Correct Answer
A. \(2\times5^2\times7^2\)
Step 1
Concept
\(2450=2\times1225\) लिखें। / Write \(2450=2\times1225\).
Step 2
Why this answer is correct
\(1225=5^2\times7^2\), इसलिए \(2450=2\times5^2\times7^2\)। / \(1225=5^2\times7^2\), so \(2450=2\times5^2\times7^2\).
Step 3
Exam Tip
1225 को अभाज्य घातों में बदलें। / Convert 1225 into prime powers.
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संख्या 2340 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 2340?
#prime-factorisation
#number-2340
#medium
A \(2^2\times3^2\times5\times13\)
B \(2\times3^2\times5\times13\)
C \(234\times10\)
D \(4\times585\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^2\times5\times13\)
Step 1
Concept
\(2340=234\times10\) लिखें। / Write \(2340=234\times10\).
Step 2
Why this answer is correct
\(234=2\times3^2\times13\) और \(10=2\times5\), इसलिए \(2340=2^2\times3^2\times5\times13\)। / \(234=2\times3^2\times13\) and \(10=2\times5\), so \(2340=2^2\times3^2\times5\times13\).
Step 3
Exam Tip
2 की घात 2 बनती है। / The power of 2 becomes 2.
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संख्या 2268 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 2268?
#prime-factorisation
#number-2268
#medium
A \(2^2\times3^4\times7\)
B \(2^3\times3^3\times7\)
C \(4\times567\)
D \(2^2\times81\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^4\times7\)
Step 1
Concept
\(2268=4\times567\) लिखें। / Write \(2268=4\times567\).
Step 2
Why this answer is correct
\(4=2^2\) और \(567=3^4\times7\), इसलिए \(2268=2^2\times3^4\times7\)। / \(4=2^2\) and \(567=3^4\times7\), so \(2268=2^2\times3^4\times7\).
Step 3
Exam Tip
567 को पूरा अभाज्य रूप में बदलें। / Convert 567 into complete prime form.
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संख्या 2205 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 2205?
#prime-factorisation
#number-2205
#medium
A \(3^2\times5\times7^2\)
B \(3\times5\times7^2\)
C \(45\times49\)
D \(9\times245\)
Explanation opens after your attempt
Correct Answer
A. \(3^2\times5\times7^2\)
Step 1
Concept
\(2205=45\times49\) लिखें। / Write \(2205=45\times49\).
Step 2
Why this answer is correct
\(45=3^2\times5\) और \(49=7^2\), इसलिए \(2205=3^2\times5\times7^2\)। / \(45=3^2\times5\) and \(49=7^2\), so \(2205=3^2\times5\times7^2\).
Step 3
Exam Tip
45 और 49 को पूरा अभाज्य रूप दें। / Give complete prime form to 45 and 49.
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संख्या 2016 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 2016?
#prime-factorisation
#number-2016
#medium
A \(2^5\times3^2\times7\)
B \(2^4\times3^2\times7\)
C \(32\times63\)
D \(2^5\times9\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2^5\times3^2\times7\)
Step 1
Concept
\(2016=32\times63\) लिखें। / Write \(2016=32\times63\).
Step 2
Why this answer is correct
\(32=2^5\) और \(63=3^2\times7\), इसलिए \(2016=2^5\times3^2\times7\)। / \(32=2^5\) and \(63=3^2\times7\), so \(2016=2^5\times3^2\times7\).
Step 3
Exam Tip
63 को अभाज्य घातों में बदलें। / Convert 63 into prime powers.
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संख्या 1875 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1875?
#prime-factorisation
#number-1875
#medium
A \(3\times5^4\)
B \(3^2\times5^3\)
C \(75\times25\)
D \(3\times625\)
Explanation opens after your attempt
Correct Answer
A. \(3\times5^4\)
Step 1
Concept
\(1875=3\times625\) लिखें। / Write \(1875=3\times625\).
Step 2
Why this answer is correct
\(625=5^4\), इसलिए \(1875=3\times5^4\)। / Since \(625=5^4\), \(1875=3\times5^4\).
Step 3
Exam Tip
625 को अंतिम रूप में न छोड़कर \(5^4\) लिखें। / Do not leave 625 in the final form; write \(5^4\).
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संख्या 1848 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 1848?
#prime-factorisation
#number-1848
#medium
A \(2^3\times3\times7\times11\)
B \(2^2\times3\times7\times11\)
C \(8\times231\)
D \(2^3\times21\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3\times7\times11\)
Step 1
Concept
\(1848=8\times231\) लिखें। / Write \(1848=8\times231\).
Step 2
Why this answer is correct
\(8=2^3\) और \(231=3\times7\times11\), इसलिए \(1848=2^3\times3\times7\times11\)। / \(8=2^3\) and \(231=3\times7\times11\), so \(1848=2^3\times3\times7\times11\).
Step 3
Exam Tip
231 को पूरा अभाज्य रूप दें। / Give 231 its complete prime form.
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संख्या 1620 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1620?
#prime-factorisation
#number-1620
#medium
A \(2^2\times3^4\times5\)
B \(2\times3^4\times5\)
C \(162\times10\)
D \(4\times405\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^4\times5\)
Step 1
Concept
\(1620=162\times10\) लिखें। / Write \(1620=162\times10\).
Step 2
Why this answer is correct
\(162=2\times3^4\) और \(10=2\times5\), इसलिए \(1620=2^2\times3^4\times5\)। / \(162=2\times3^4\) and \(10=2\times5\), so \(1620=2^2\times3^4\times5\).
Step 3
Exam Tip
2 की कुल घात सही गिनें। / Count the total power of 2 correctly.
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संख्या 1485 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 1485?
#prime-factorisation
#number-1485
#medium
A \(3^3\times5\times11\)
B \(3^2\times5\times11\)
C \(135\times11\)
D \(27\times55\)
Explanation opens after your attempt
Correct Answer
A. \(3^3\times5\times11\)
Step 1
Concept
\(1485=135\times11\) लिखें। / Write \(1485=135\times11\).
Step 2
Why this answer is correct
\(135=3^3\times5\), इसलिए \(1485=3^3\times5\times11\)। / \(135=3^3\times5\), so \(1485=3^3\times5\times11\).
Step 3
Exam Tip
135 को पूरा अभाज्य रूप दें। / Give 135 its complete prime form.
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संख्या 1344 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1344?
#prime-factorisation
#number-1344
#medium
A \(2^6\times3\times7\)
B \(2^5\times3\times7\)
C \(64\times21\)
D \(2^6\times21\)
Explanation opens after your attempt
Correct Answer
A. \(2^6\times3\times7\)
Step 1
Concept
\(1344=64\times21\) लिखें। / Write \(1344=64\times21\).
Step 2
Why this answer is correct
\(64=2^6\) और \(21=3\times7\), इसलिए \(1344=2^6\times3\times7\)। / \(64=2^6\) and \(21=3\times7\), so \(1344=2^6\times3\times7\).
Step 3
Exam Tip
21 संयुक्त है, इसलिए उसे 3 और 7 में तोड़ें। / Since 21 is composite, split it into 3 and 7.
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संख्या 1215 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 1215?
#prime-factorisation
#number-1215
#medium
A \(3^5\times5\)
B \(3^4\times5^2\)
C \(243\times5\)
D \(81\times15\)
Explanation opens after your attempt
Correct Answer
A. \(3^5\times5\)
Step 1
Concept
\(1215=243\times5\) लिखें। / Write \(1215=243\times5\).
Step 2
Why this answer is correct
\(243=3^5\), इसलिए \(1215=3^5\times5\)। / Since \(243=3^5\), \(1215=3^5\times5\).
Step 3
Exam Tip
243 संयुक्त है, इसलिए अंतिम अभाज्य रूप में 3 की घात लिखें। / 243 is composite, so write it as a power of 3 in final prime form.
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संख्या 1170 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 1170?
#prime-factorisation
#number-1170
#medium
A \(2\times3^2\times5\times13\)
B \(2^2\times3\times5\times13\)
C \(117\times10\)
D \(9\times130\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^2\times5\times13\)
Step 1
Concept
\(1170=117\times10\) लिखें। / Write \(1170=117\times10\).
Step 2
Why this answer is correct
\(117=3^2\times13\) और \(10=2\times5\), इसलिए \(1170=2\times3^2\times5\times13\)। / \(117=3^2\times13\) and \(10=2\times5\), so \(1170=2\times3^2\times5\times13\).
Step 3
Exam Tip
117 और 10 को अंतिम रूप में न रखें। / Do not keep 117 and 10 in the final form.
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अभाज्य गुणनखंडन में घातों की तुलना करते समय सबसे पहले क्या देखना चाहिए?
What should be checked first while comparing powers in prime factorisation?
#prime-factorisation
#powers
#medium
A एक ही अभाज्य आधार की घातें / Powers of the same prime base
B सभी संयुक्त गुणनखंडों का योग / Sum of all composite factors
C संख्या का अंतिम अंक ही / Only the last digit of the number
D गुणनखंडों का क्रम ही / Only the order of factors
Explanation opens after your attempt
Correct Answer
A. एक ही अभाज्य आधार की घातें / Powers of the same prime base
Step 1
Concept
अभाज्य गुणनखंडन में आधार पहले पहचानते हैं। / In prime factorisation, identify the bases first.
Step 2
Why this answer is correct
एक ही आधार की घातों की तुलना की जाती है, जैसे 2 की घात 2 से और 3 की घात 3 से। / Powers of the same base are compared, such as power of 2 with power of 2 and power of 3 with power of 3.
Step 3
Exam Tip
परीक्षा में आधार अलग हों तो घातों को सीधे न मिलाएं। / In exams, do not compare powers directly when bases are different.
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अभाज्य गुणनखंडन में \(18\times100\) को अंतिम उत्तर क्यों नहीं माना जाता?
Why is \(18\times100\) not considered a final answer in prime factorisation?
#prime-factorisation
#concept-check
#medium
A क्योंकि 18 और 100 संयुक्त संख्याएं हैं / Because 18 and 100 are composite numbers
B क्योंकि गुणा करना हमेशा गलत है / Because multiplication is always wrong
C क्योंकि 18 अभाज्य और 100 अभाज्य हैं / Because 18 and 100 are prime
D क्योंकि घातों का उपयोग नहीं किया जा सकता / Because powers cannot be used
Explanation opens after your attempt
Correct Answer
A. क्योंकि 18 और 100 संयुक्त संख्याएं हैं / Because 18 and 100 are composite numbers
Step 1
Concept
अभाज्य गुणनखंडन में हर अंतिम गुणनखंड अभाज्य होना चाहिए। / In prime factorisation, every final factor must be prime.
Step 2
Why this answer is correct
\(18=2\times3^2\) और \(100=2^2\times5^2\), इसलिए दोनों संयुक्त हैं। / \(18=2\times3^2\) and \(100=2^2\times5^2\), so both are composite.
Step 3
Exam Tip
\(18\times100\) को आगे \(2^3\times3^2\times5^2\) में बदलना होगा। / \(18\times100\) must be changed further into \(2^3\times3^2\times5^2\).
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संख्या 8192 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 8192?
#prime-factorisation
#power-of-two
#medium
A \(2^{13}\)
B \(2^{12}\)
C \(64^2\times2\)
D \(16^3\times2\)
Explanation opens after your attempt
Correct Answer
A. \(2^{13}\)
Step 1
Concept
8192 को बार-बार 2 से भाग दें। / Divide 8192 repeatedly by 2.
Step 2
Why this answer is correct
तेरह बार 2 मिलने से \(8192=2^{13}\)। / Thirteen factors of 2 give \(8192=2^{13}\).
Step 3
Exam Tip
64 और 16 संयुक्त हैं, इसलिए अंतिम अभाज्य रूप में 2 की घात लिखें। / 64 and 16 are composite, so write the power of 2 in final prime form.
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किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times5\times7\times11\) है?
Which number has prime factorisation \(2^2\times3\times5\times7\times11\)?
#evaluate-factorisation
#number-4620
#medium
A 4620
B 2310
C 9240
D 3850
Explanation opens after your attempt
Step 1
Concept
\(2^2=4\) निकालें। / Calculate \(2^2=4\).
Step 2
Why this answer is correct
\(4\times3\times5\times7\times11=4620\)। / \(4\times3\times5\times7\times11=4620\).
Step 3
Exam Tip
कई गुणनखंड हों तो जोड़े बनाकर गुणा करें। / When there are many factors, multiply in pairs.
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संख्या 5400 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 5400?
#prime-factorisation
#number-5400
#medium
A \(2^3\times3^3\times5^2\)
B \(2^2\times3^3\times5^2\)
C \(54\times100\)
D \(2^3\times27\times25\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^3\times5^2\)
Step 1
Concept
\(5400=54\times100\) लिखें। / Write \(5400=54\times100\).
Step 2
Why this answer is correct
\(54=2\times3^3\) और \(100=2^2\times5^2\), इसलिए \(5400=2^3\times3^3\times5^2\)। / \(54=2\times3^3\) and \(100=2^2\times5^2\), so \(5400=2^3\times3^3\times5^2\).
Step 3
Exam Tip
54 और 100 दोनों को पूरा तोड़ें। / Break both 54 and 100 completely.
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