\(a_7\) is equidistant from \(a_4\) and \(a_{10}\), so \(a_7=\frac{96}{2}=48\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (48). \(a_7\) is equidistant from \(a_4\) and \(a_{10}\), so \(a_7=\frac{96}{2}=48\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_7\), \(a_4\) और \(a_{10}\) से समान दूरी पर है, इसलिए \(a_7=\frac{96}{2}=48\)। सममित पदों का औसत मध्य पद होता है।
\(a_{10}\) is equidistant from \(a_5\) and \(a_{15}\), so \(a_{10}=\frac{150}{2}=75\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (75). \(a_{10}\) is equidistant from \(a_5\) and \(a_{15}\), so \(a_{10}=\frac{150}{2}=75\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_{10}\), \(a_5\) और \(a_{15}\) से समान दूरी पर है, इसलिए \(a_{10}=\frac{150}{2}=75\)। सममित पदों का औसत मध्य पद होता है।
\(a_{10}\) is equidistant from \(a_4\) and \(a_{16}\), so \(a_{10}=\frac{140}{2}=70\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (70). \(a_{10}\) is equidistant from \(a_4\) and \(a_{16}\), so \(a_{10}=\frac{140}{2}=70\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_{10}\), \(a_4\) और \(a_{16}\) से समान दूरी पर है, इसलिए \(a_{10}=\frac{140}{2}=70\)। सममित पदों का औसत बीच का पद होता है।
\(a_{10}\) is equidistant from \(a_6\) and \(a_{14}\), so \(a_{10}=\frac{120}{2}=60\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (60). \(a_{10}\) is equidistant from \(a_6\) and \(a_{14}\), so \(a_{10}=\frac{120}{2}=60\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_6\) और \(a_{14}\) से \(a_{10}\) समान दूरी पर है, इसलिए \(a_{10}=\frac{120}{2}=60\)। सममित पदों का औसत मध्य पद होता है।
\(a_5\) is equidistant from \(a_3\) and \(a_7\), so \(a_5=\frac{60}{2}=30\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (30). \(a_5\) is equidistant from \(a_3\) and \(a_7\), so \(a_5=\frac{60}{2}=30\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_5\), \(a_3\) और \(a_7\) से समान दूरी पर है, इसलिए \(a_5=\frac{60}{2}=30\)। सममित पदों का औसत मध्य पद होता है।
\(a_8\) is equidistant from \(a_4\) and \(a_{12}\), so \(a_8=\frac{112}{2}=56\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (56). \(a_8\) is equidistant from \(a_4\) and \(a_{12}\), so \(a_8=\frac{112}{2}=56\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_8\), \(a_4\) और \(a_{12}\) से समान दूरी पर है, इसलिए \(a_8=\frac{112}{2}=56\)। सममित पदों का औसत मध्य पद होता है।
\(a_9\) is equidistant from \(a_3\) and \(a_{15}\), so \(a_9=\frac{108}{2}=54\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (54). \(a_9\) is equidistant from \(a_3\) and \(a_{15}\), so \(a_9=\frac{108}{2}=54\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_9\), \(a_3\) और \(a_{15}\) से समान दूरी पर है, इसलिए \(a_9=\frac{108}{2}=54\)। सममित पदों का औसत बीच का पद होता है।
\(a_9\) is equidistant from \(a_5\) and \(a_{13}\), so \(a_9=\frac{86}{2}=43\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (43). \(a_9\) is equidistant from \(a_5\) and \(a_{13}\), so \(a_9=\frac{86}{2}=43\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_5\) और \(a_{13}\) से \(a_9\) समान दूरी पर है, इसलिए \(a_9=\frac{86}{2}=43\)। सममित पदों का औसत मध्य पद होता है।
\(a_4\) is equidistant from \(a_2\) and \(a_6\), so \(a_4=\frac{40}{2}=20\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (20). \(a_4\) is equidistant from \(a_2\) and \(a_6\), so \(a_4=\frac{40}{2}=20\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_4\), \(a_2\) और \(a_6\) से समान दूरी पर है, इसलिए \(a_4=\frac{40}{2}=20\)। सममित पदों का औसत मध्य पद होता है।
\(a_6\) is equidistant from \(a_3\) and \(a_9\), so \(a_6=\frac{72}{2}=36\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is C. (36). \(a_6\) is equidistant from \(a_3\) and \(a_9\), so \(a_6=\frac{72}{2}=36\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_3\) और \(a_9\) से \(a_6\) समान दूरी पर है, इसलिए \(a_6=\frac{72}{2}=36\)। सममित पदों का औसत मध्य पद होता है।
\(a_6\) is equidistant from \(a_2\) and \(a_{10}\), so \(a_6=\frac{64}{2}=32\). The average of symmetric terms is the middle term.
Step 2
Why this answer is correct
The correct answer is D. (32). \(a_6\) is equidistant from \(a_2\) and \(a_{10}\), so \(a_6=\frac{64}{2}=32\). The average of symmetric terms is the middle term.
Step 3
Exam Tip
\(a_2\) और \(a_{10}\) से \(a_6\) समान दूरी पर है, इसलिए \(a_6=\frac{64}{2}=32\)। सममित पदों का औसत बीच का पद होता है।
In an arithmetic progression, the average of \(a_4\) and \(a_8\) is \(a_6\), so \(a_6=\frac{50}{2}=25\). Equidistant terms average to the middle term.
Step 2
Why this answer is correct
The correct answer is B. (25). In an arithmetic progression, the average of \(a_4\) and \(a_8\) is \(a_6\), so \(a_6=\frac{50}{2}=25\). Equidistant terms average to the middle term.
Step 3
Exam Tip
समांतर श्रेणी में \(a_4\) और \(a_8\) का औसत \(a_6\) होता है, इसलिए \(a_6=\frac{50}{2}=25\)। समान दूरी वाले पदों का औसत बीच का पद होता है।
