यदि \(a_2+a_{10}=64\) है, तो \(a_6\) का मान क्या है?
If \(a_2+a_{10}=64\), what is the value of \(a_6\)?
Explanation opens after your attempt
Correct Answer
D. (32)
Concept
\(a_6\) is equidistant from \(a_2\) and \(a_{10}\), so \(a_6=\frac{64}{2}=32\). The average of symmetric terms is the middle term.
Why this answer is correct
The correct answer is D. (32). \(a_6\) is equidistant from \(a_2\) and \(a_{10}\), so \(a_6=\frac{64}{2}=32\). The average of symmetric terms is the middle term.
Exam Tip
\(a_2\) और \(a_{10}\) से \(a_6\) समान दूरी पर है, इसलिए \(a_6=\frac{64}{2}=32\)। सममित पदों का औसत बीच का पद होता है।
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