यदि \(a_3+a_{15}=108\) है, तो \(a_9\) का मान क्या है?

If \(a_3+a_{15}=108\), what is the value of \(a_9\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (54)

Step 1

Concept

\(a_9\) is equidistant from \(a_3\) and \(a_{15}\), so \(a_9=\frac{108}{2}=54\). The average of symmetric terms is the middle term.

Step 2

Why this answer is correct

The correct answer is C. (54). \(a_9\) is equidistant from \(a_3\) and \(a_{15}\), so \(a_9=\frac{108}{2}=54\). The average of symmetric terms is the middle term.

Step 3

Exam Tip

\(a_9\), \(a_3\) और \(a_{15}\) से समान दूरी पर है, इसलिए \(a_9=\frac{108}{2}=54\)। सममित पदों का औसत बीच का पद होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_3+a_{15}=108\) है, तो \(a_9\) का मान क्या है? / If \(a_3+a_{15}=108\), what is the value of \(a_9\)?

Correct Answer: C. (54). Explanation: \(a_9\), \(a_3\) और \(a_{15}\) से समान दूरी पर है, इसलिए \(a_9=\frac{108}{2}=54\)। सममित पदों का औसत बीच का पद होता है। / \(a_9\) is equidistant from \(a_3\) and \(a_{15}\), so \(a_9=\frac{108}{2}=54\). The average of symmetric terms is the middle term.

Which concept should I revise for this Mathematics MCQ?

\(a_9\) is equidistant from \(a_3\) and \(a_{15}\), so \(a_9=\frac{108}{2}=54\). The average of symmetric terms is the middle term.

What exam hint can help solve this Mathematics question?

\(a_9\), \(a_3\) और \(a_{15}\) से समान दूरी पर है, इसलिए \(a_9=\frac{108}{2}=54\)। सममित पदों का औसत बीच का पद होता है।