यदि समांतर श्रेणी में \(a_5+a_{15}=150\) है, तो \(a_{10}\) क्या होगा?

If in an arithmetic progression \(a_5+a_{15}=150\), what is \(a_{10}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (75)

Step 1

Concept

\(a_{10}\) is equidistant from \(a_5\) and \(a_{15}\), so \(a_{10}=\frac{150}{2}=75\). The average of symmetric terms is the middle term.

Step 2

Why this answer is correct

The correct answer is C. (75). \(a_{10}\) is equidistant from \(a_5\) and \(a_{15}\), so \(a_{10}=\frac{150}{2}=75\). The average of symmetric terms is the middle term.

Step 3

Exam Tip

\(a_{10}\), \(a_5\) और \(a_{15}\) से समान दूरी पर है, इसलिए \(a_{10}=\frac{150}{2}=75\)। सममित पदों का औसत मध्य पद होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि समांतर श्रेणी में \(a_5+a_{15}=150\) है, तो \(a_{10}\) क्या होगा? / If in an arithmetic progression \(a_5+a_{15}=150\), what is \(a_{10}\)?

Correct Answer: C. (75). Explanation: \(a_{10}\), \(a_5\) और \(a_{15}\) से समान दूरी पर है, इसलिए \(a_{10}=\frac{150}{2}=75\)। सममित पदों का औसत मध्य पद होता है। / \(a_{10}\) is equidistant from \(a_5\) and \(a_{15}\), so \(a_{10}=\frac{150}{2}=75\). The average of symmetric terms is the middle term.

Which concept should I revise for this Mathematics MCQ?

\(a_{10}\) is equidistant from \(a_5\) and \(a_{15}\), so \(a_{10}=\frac{150}{2}=75\). The average of symmetric terms is the middle term.

What exam hint can help solve this Mathematics question?

\(a_{10}\), \(a_5\) और \(a_{15}\) से समान दूरी पर है, इसलिए \(a_{10}=\frac{150}{2}=75\)। सममित पदों का औसत मध्य पद होता है।