यदि समांतर श्रेणी में \(a_4+a_{10}=96\) है, तो \(a_7\) क्या होगा?

If in an arithmetic progression \(a_4+a_{10}=96\), what is \(a_7\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (48)

Step 1

Concept

\(a_7\) is equidistant from \(a_4\) and \(a_{10}\), so \(a_7=\frac{96}{2}=48\). The average of symmetric terms is the middle term.

Step 2

Why this answer is correct

The correct answer is C. (48). \(a_7\) is equidistant from \(a_4\) and \(a_{10}\), so \(a_7=\frac{96}{2}=48\). The average of symmetric terms is the middle term.

Step 3

Exam Tip

\(a_7\), \(a_4\) और \(a_{10}\) से समान दूरी पर है, इसलिए \(a_7=\frac{96}{2}=48\)। सममित पदों का औसत मध्य पद होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि समांतर श्रेणी में \(a_4+a_{10}=96\) है, तो \(a_7\) क्या होगा? / If in an arithmetic progression \(a_4+a_{10}=96\), what is \(a_7\)?

Correct Answer: C. (48). Explanation: \(a_7\), \(a_4\) और \(a_{10}\) से समान दूरी पर है, इसलिए \(a_7=\frac{96}{2}=48\)। सममित पदों का औसत मध्य पद होता है। / \(a_7\) is equidistant from \(a_4\) and \(a_{10}\), so \(a_7=\frac{96}{2}=48\). The average of symmetric terms is the middle term.

Which concept should I revise for this Mathematics MCQ?

\(a_7\) is equidistant from \(a_4\) and \(a_{10}\), so \(a_7=\frac{96}{2}=48\). The average of symmetric terms is the middle term.

What exam hint can help solve this Mathematics question?

\(a_7\), \(a_4\) और \(a_{10}\) से समान दूरी पर है, इसलिए \(a_7=\frac{96}{2}=48\)। सममित पदों का औसत मध्य पद होता है।