यदि समांतर श्रेणी में \(a_4+a_{10}=96\) है, तो \(a_7\) क्या होगा?
If in an arithmetic progression \(a_4+a_{10}=96\), what is \(a_7\)?
Explanation opens after your attempt
C. (48)
Concept
\(a_7\) is equidistant from \(a_4\) and \(a_{10}\), so \(a_7=\frac{96}{2}=48\). The average of symmetric terms is the middle term.
Why this answer is correct
The correct answer is C. (48). \(a_7\) is equidistant from \(a_4\) and \(a_{10}\), so \(a_7=\frac{96}{2}=48\). The average of symmetric terms is the middle term.
Exam Tip
\(a_7\), \(a_4\) और \(a_{10}\) से समान दूरी पर है, इसलिए \(a_7=\frac{96}{2}=48\)। सममित पदों का औसत मध्य पद होता है।
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