यदि किसी समांतर श्रेणी में \(a_6+a_{14}=120\) है, तो \(a_{10}\) का मान क्या होगा?
If in an arithmetic progression \(a_6+a_{14}=120\), what is the value of \(a_{10}\)?
Explanation opens after your attempt
Correct Answer
C. (60)
Concept
\(a_{10}\) is equidistant from \(a_6\) and \(a_{14}\), so \(a_{10}=\frac{120}{2}=60\). The average of symmetric terms is the middle term.
Why this answer is correct
The correct answer is C. (60). \(a_{10}\) is equidistant from \(a_6\) and \(a_{14}\), so \(a_{10}=\frac{120}{2}=60\). The average of symmetric terms is the middle term.
Exam Tip
\(a_6\) और \(a_{14}\) से \(a_{10}\) समान दूरी पर है, इसलिए \(a_{10}=\frac{120}{2}=60\)। सममित पदों का औसत मध्य पद होता है।
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