समीकरणों (x+y=5) और (x-y=1) का हल क्या है?
What is the solution of the equations (x+y=5) and (x-y=1)?
#linear equations
#substitution
#elimination
#easy
#class 10
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A (x=3,\ y=2)
B (x=2,\ y=3)
C (x=4,\ y=1)
D (x=1,\ y=4)
Explanation opens after your attempt
Correct Answer
A. (x=3,\ y=2)
Step 1
Concept
Adding both equations gives (2x=6), so (x=3) and (y=2). In exams, add first when one variable cancels easily.
Step 2
Why this answer is correct
The correct answer is A. (x=3,\ y=2). Adding both equations gives (2x=6), so (x=3) and (y=2). In exams, add first when one variable cancels easily.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (2x=6), इसलिए (x=3) और (y=2)। परीक्षा में पहले जोड़कर आसान चर निकालें।
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समीकरणों (2x+y=7) और (x=2) में (y) का मान क्या है?
In the equations (2x+y=7) and (x=2), what is the value of (y)?
#linear equations
#substitution
#value finding
#easy
#class 10
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A (y=1)
B (y=2)
C (y=3)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Putting (x=2) gives (4+y=7), so (y=3). In substitution, place the given value directly.
Step 2
Why this answer is correct
The correct answer is C. (y=3). Putting (x=2) gives (4+y=7), so (y=3). In substitution, place the given value directly.
Step 3
Exam Tip
(x=2) रखने पर (4+y=7), इसलिए (y=3)। प्रतिस्थापन विधि में दिए मान को सीधे रखें।
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यदि (y=x+1) और (x+y=7), तो (x) और (y) के मान क्या होंगे?
If (y=x+1) and (x+y=7), what are the values of (x) and (y)?
#linear equations
#substitution
#isolated variable
#easy
#class 10
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A (x=4,\ y=3)
B (x=3,\ y=4)
C (x=2,\ y=5)
D (x=5,\ y=2)
Explanation opens after your attempt
Correct Answer
B. (x=3,\ y=4)
Step 1
Concept
Substituting (y=x+1) in (x+y=7) gives (2x+1=7), so (x=3) and (y=4). Use the already isolated variable in exams.
Step 2
Why this answer is correct
The correct answer is B. (x=3,\ y=4). Substituting (y=x+1) in (x+y=7) gives (2x+1=7), so (x=3) and (y=4). Use the already isolated variable in exams.
Step 3
Exam Tip
(y=x+1) को (x+y=7) में रखने पर (2x+1=7), इसलिए (x=3) और (y=4)। परीक्षा में बने हुए रूप का उपयोग करें।
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समीकरणों (3x+y=11) और (x+y=5) को विलोपन विधि से हल करने पर (x) का मान क्या है?
Using elimination method for (3x+y=11) and (x+y=5), what is the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
50 50-50 2 wrong hide
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? Hint Small clue
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2x=6), so (x=3). Subtract equal like terms when their signs are the same.
Step 2
Why this answer is correct
The correct answer is C. (x=3). Subtracting the second equation from the first gives (2x=6), so (x=3). Subtract equal like terms when their signs are the same.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2x=6), इसलिए (x=3)। समान चिन्ह वाले समान चर को घटाना उपयोगी होता है।
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यदि (x-y=4) और (x+y=10), तो (y) का मान क्या होगा?
If (x-y=4) and (x+y=10), what will be the value of (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
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? Hint Small clue
A (y=2)
B (y=3)
C (y=4)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (2x=14), so (x=7) and (y=3). After finding one variable, substitute it in any equation.
Step 2
Why this answer is correct
The correct answer is B. (y=3). Adding both equations gives (2x=14), so (x=7) and (y=3). After finding one variable, substitute it in any equation.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (2x=14), इसलिए (x=7) और (y=3)। एक चर मिलने के बाद उसे किसी भी समीकरण में रखें।
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समीकरणों (2x-y=1) और (x+y=8) का हल कौन-सा है?
Which is the solution of (2x-y=1) and (x+y=8)?
#linear equations
#elimination
#solution pair
#easy
#class 10
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A (x=5,\ y=3)
B (x=4,\ y=4)
C (x=2,\ y=6)
D (x=3,\ y=5)
Explanation opens after your attempt
Correct Answer
D. (x=3,\ y=5)
Step 1
Concept
Adding both equations gives (3x=9), so (x=3) and (y=5). Variables with opposite signs cancel quickly in elimination.
Step 2
Why this answer is correct
The correct answer is D. (x=3,\ y=5). Adding both equations gives (3x=9), so (x=3) and (y=5). Variables with opposite signs cancel quickly in elimination.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (3x=9), इसलिए (x=3) और (y=5)। विपरीत चिन्ह वाले चर विलोपन में जल्दी कटते हैं।
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यदि (x=2y) और (x+y=9), तो (x) का मान क्या है?
If (x=2y) and (x+y=9), what is the value of (x)?
#linear equations
#substitution
#value of x
#easy
#class 10
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A (x=3)
B (x=6)
C (x=9)
D (x=12)
Explanation opens after your attempt
Step 1
Concept
Using (x=2y) gives (2y+y=9), so (y=3) and (x=6). In substitution, form an equation in one variable.
Step 2
Why this answer is correct
The correct answer is B. (x=6). Using (x=2y) gives (2y+y=9), so (y=3) and (x=6). In substitution, form an equation in one variable.
Step 3
Exam Tip
(x=2y) रखने पर (2y+y=9), इसलिए (y=3) और (x=6)। प्रतिस्थापन में एक ही चर वाला समीकरण बनाइए।
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यदि (y=3x) और (x+y=8), तो हल क्या है?
If (y=3x) and (x+y=8), what is the solution?
#linear equations
#substitution
#solution
#easy
#class 10
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A (x=2,\ y=6)
B (x=6,\ y=2)
C (x=3,\ y=5)
D (x=1,\ y=7)
Explanation opens after your attempt
Correct Answer
A. (x=2,\ y=6)
Step 1
Concept
Substituting (y=3x) gives (4x=8), so (x=2) and (y=6). Substitution is easiest when one variable is already expressed as a multiple.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=6). Substituting (y=3x) gives (4x=8), so (x=2) and (y=6). Substitution is easiest when one variable is already expressed as a multiple.
Step 3
Exam Tip
(y=3x) को रखने पर (4x=8), इसलिए (x=2) और (y=6)। अनुपात वाले रूप में प्रतिस्थापन सबसे सरल होता है।
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समीकरणों (4x+y=14) और (x+y=5) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (4x+y=14) and (x+y=5).
#linear equations
#elimination
#value of x
#easy
#class 10
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A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3x=9), so (x=3). Identify the common variable before subtracting.
Step 2
Why this answer is correct
The correct answer is B. (x=3). Subtracting the second equation from the first gives (3x=9), so (x=3). Identify the common variable before subtracting.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3x=9), इसलिए (x=3)। घटाने से पहले समान चर को पहचानें।
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यदि (x+2y=11) और (x-y=2), तो (x) और (y) का मान क्या है?
If (x+2y=11) and (x-y=2), what are the values of (x) and (y)?
#linear equations
#substitution
#solution pair
#easy
#class 10
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A (x=3,\ y=4)
B (x=4,\ y=3)
C (x=5,\ y=3)
D (x=6,\ y=2)
Explanation opens after your attempt
Correct Answer
C. (x=5,\ y=3)
Step 1
Concept
From the second equation (x=y+2); substituting gives (3y+2=11), so (y=3) and (x=5). Substitute the isolated variable carefully.
Step 2
Why this answer is correct
The correct answer is C. (x=5,\ y=3). From the second equation (x=y+2); substituting gives (3y+2=11), so (y=3) and (x=5). Substitute the isolated variable carefully.
Step 3
Exam Tip
दूसरे समीकरण से (x=y+2); रखने पर (3y+2=11), इसलिए (y=3) और (x=5)। अलग किए हुए चर को ध्यान से रखें।
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समीकरणों (x+y=5) और (2x+3y=12) का हल क्या है?
What is the solution of (x+y=5) and (2x+3y=12)?
#linear equations
#substitution
#two equations
#easy
#class 10
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A (x=2,\ y=3)
B (x=3,\ y=2)
C (x=4,\ y=1)
D (x=1,\ y=4)
Explanation opens after your attempt
Correct Answer
B. (x=3,\ y=2)
Step 1
Concept
Using (x=5-y) gives (10-2y+3y=12), so (y=2) and (x=3). It is better to isolate a variable from the simpler equation.
Step 2
Why this answer is correct
The correct answer is B. (x=3,\ y=2). Using (x=5-y) gives (10-2y+3y=12), so (y=2) and (x=3). It is better to isolate a variable from the simpler equation.
Step 3
Exam Tip
(x=5-y) रखने पर (10-2y+3y=12), इसलिए (y=2) और (x=3)। सरल समीकरण से चर अलग करना बेहतर है।
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यदि (x+y=6) और (3x-y=6), तो (x) का मान क्या होगा?
If (x+y=6) and (3x-y=6), what will be the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
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? Hint Small clue
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Adding the equations gives (4x=12), so (x=3). Remove (y) by adding when its signs are opposite.
Step 2
Why this answer is correct
The correct answer is C. (x=3). Adding the equations gives (4x=12), so (x=3). Remove (y) by adding when its signs are opposite.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (4x=12), इसलिए (x=3)। विपरीत चिन्ह वाले (y) को जोड़कर हटाइए।
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समीकरणों (2x+y=9) और (x-y=3) में (y) का मान क्या है?
In the equations (2x+y=9) and (x-y=3), what is the value of (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
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A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (3x=12), so (x=4) and (y=1). Eliminate first, then find the other variable.
Step 2
Why this answer is correct
The correct answer is A. (y=1). Adding both equations gives (3x=12), so (x=4) and (y=1). Eliminate first, then find the other variable.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (3x=12), इसलिए (x=4) और (y=1)। पहले आसान विलोपन करें फिर दूसरा चर निकालें।
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यदि (x=5-y) और (2x+y=8), तो (y) का मान क्या होगा?
If (x=5-y) and (2x+y=8), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
50 50-50 2 wrong hide
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? Hint Small clue
A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=5-y) gives (10-2y+y=8), so (y=2). Be careful while simplifying negative signs.
Step 2
Why this answer is correct
The correct answer is B. (y=2). Substituting (x=5-y) gives (10-2y+y=8), so (y=2). Be careful while simplifying negative signs.
Step 3
Exam Tip
(x=5-y) रखने पर (10-2y+y=8), इसलिए (y=2)। ऋण चिन्हों को सरल करते समय सावधानी रखें।
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समीकरणों (5x-y=9) और (2x-y=3) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (5x-y=9) and (2x-y=3).
#linear equations
#elimination
#subtract equations
#easy
#class 10
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A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3x=6), so (x=2). Equal (y) terms can be removed by subtraction.
Step 2
Why this answer is correct
The correct answer is B. (x=2). Subtracting the second equation from the first gives (3x=6), so (x=2). Equal (y) terms can be removed by subtraction.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3x=6), इसलिए (x=2)। समान (y) पदों को घटाकर हटाया जा सकता है।
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यदि (x+y=12) और (x=7), तो (y) का मान क्या है?
If (x+y=12) and (x=7), what is the value of (y)?
#linear equations
#substitution
#direct value
#easy
#class 10
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? Hint Small clue
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=7) gives (7+y=12), so (y=5). Use the given variable value directly.
Step 2
Why this answer is correct
The correct answer is C. (y=5). Putting (x=7) gives (7+y=12), so (y=5). Use the given variable value directly.
Step 3
Exam Tip
(x=7) रखने पर (7+y=12), इसलिए (y=5)। दिए हुए चर का मान सीधे प्रयोग करें।
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समीकरणों (x+3y=13) और (x+y=7) को हल करने पर (y) कितना होगा?
On solving (x+3y=13) and (x+y=7), what is (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
50 50-50 2 wrong hide
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? Hint Small clue
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2y=6), so (y=3). When (x) is equal, subtraction is easiest.
Step 2
Why this answer is correct
The correct answer is B. (y=3). Subtracting the second equation from the first gives (2y=6), so (y=3). When (x) is equal, subtraction is easiest.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2y=6), इसलिए (y=3)। समान (x) होने पर घटाना सबसे आसान है।
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यदि (2x+2y=16) और (x-y=2), तो सही हल कौन-सा है?
If (2x+2y=16) and (x-y=2), which is the correct solution?
#linear equations
#elimination
#simplification
#easy
#class 10
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? Hint Small clue
A (x=4,\ y=4)
B (x=6,\ y=2)
C (x=5,\ y=3)
D (x=3,\ y=5)
Explanation opens after your attempt
Correct Answer
C. (x=5,\ y=3)
Step 1
Concept
The first equation becomes (x+y=8); adding it with (x-y=2) gives (2x=10). Simplifying an equation first makes solving easier.
Step 2
Why this answer is correct
The correct answer is C. (x=5,\ y=3). The first equation becomes (x+y=8); adding it with (x-y=2) gives (2x=10). Simplifying an equation first makes solving easier.
Step 3
Exam Tip
पहला समीकरण (x+y=8) बनता है; इसे (x-y=2) से जोड़ने पर (2x=10)। पहले समीकरण को सरल करने से हल आसान होता है।
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समीकरणों (y=x+4) और (2x+y=10) में (x) का मान क्या होगा?
In (y=x+4) and (2x+y=10), what will be the value of (x)?
#linear equations
#substitution
#value of x
#easy
#class 10
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? Hint Small clue
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Substituting (y=x+4) gives (3x+4=10), so (x=2). Combine like terms after substitution.
Step 2
Why this answer is correct
The correct answer is B. (x=2). Substituting (y=x+4) gives (3x+4=10), so (x=2). Combine like terms after substitution.
Step 3
Exam Tip
(y=x+4) रखने पर (3x+4=10), इसलिए (x=2)। प्रतिस्थापन के बाद समान पदों को जोड़ें।
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यदि (3x+2y=16) और (3x-y=7), तो (y) का मान क्या है?
If (3x+2y=16) and (3x-y=7), what is the value of (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
50 50-50 2 wrong hide
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? Hint Small clue
A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3y=9), so (y=3). Subtract to remove the common (3x).
Step 2
Why this answer is correct
The correct answer is C. (y=3). Subtracting the second equation from the first gives (3y=9), so (y=3). Subtract to remove the common (3x).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3y=9), इसलिए (y=3)। समान (3x) को हटाने के लिए घटाइए।
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समीकरणों (x+4y=18) और (x=2) से (y) का मान ज्ञात कीजिए।
Find the value of (y) from (x+4y=18) and (x=2).
#linear equations
#substitution
#value of y
#easy
#class 10
50 50-50 2 wrong hide
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? Hint Small clue
A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=2) gives (2+4y=18), so (y=4). Do arithmetic carefully in simple substitution.
Step 2
Why this answer is correct
The correct answer is B. (y=4). Putting (x=2) gives (2+4y=18), so (y=4). Do arithmetic carefully in simple substitution.
Step 3
Exam Tip
(x=2) रखने पर (2+4y=18), इसलिए (y=4)। सरल प्रतिस्थापन में अंकगणित ध्यान से करें।
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यदि (2x+y=11) और (2x-y=5), तो (x) का मान क्या होगा?
If (2x+y=11) and (2x-y=5), what will be the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
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A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (4x=16), so (x=4). Add opposite (y) terms to eliminate them.
Step 2
Why this answer is correct
The correct answer is C. (x=4). Adding both equations gives (4x=16), so (x=4). Add opposite (y) terms to eliminate them.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (4x=16), इसलिए (x=4)। विपरीत (y) पदों को जोड़कर हटाइए।
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समीकरणों (x=3y-1) और (x+y=11) का हल क्या है?
What is the solution of (x=3y-1) and (x+y=11)?
#linear equations
#substitution
#solution pair
#easy
#class 10
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A (x=8,\ y=3)
B (x=7,\ y=4)
C (x=6,\ y=5)
D (x=5,\ y=6)
Explanation opens after your attempt
Correct Answer
A. (x=8,\ y=3)
Step 1
Concept
Substituting (x=3y-1) gives (4y-1=11), so (y=3) and (x=8). Use the given expression for (x) directly.
Step 2
Why this answer is correct
The correct answer is A. (x=8,\ y=3). Substituting (x=3y-1) gives (4y-1=11), so (y=3) and (x=8). Use the given expression for (x) directly.
Step 3
Exam Tip
(x=3y-1) रखने पर (4y-1=11), इसलिए (y=3) और (x=8)। बने हुए (x) के रूप को सीधे इस्तेमाल करें।
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यदि (4x+2y=20) और (x+y=7), तो (x) का मान क्या है?
If (4x+2y=20) and (x+y=7), what is the value of (x)?
#linear equations
#elimination
#simplify first
#easy
#class 10
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A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
The first equation becomes (2x+y=10); subtracting (x+y=7) gives (x=3). Divide by common factors first.
Step 2
Why this answer is correct
The correct answer is C. (x=3). The first equation becomes (2x+y=10); subtracting (x+y=7) gives (x=3). Divide by common factors first.
Step 3
Exam Tip
पहला समीकरण (2x+y=10) बनता है; इससे (x+y=7) घटाने पर (x=3)। पहले सामान्य गुणनखंड से भाग दें।
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समीकरणों (x-2y=1) और (x+y=10) में (y) का मान क्या है?
In the equations (x-2y=1) and (x+y=10), what is the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
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A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
From the second equation (x=10-y); substituting gives (10-y-2y=1), so (y=3). Watch brackets and signs in substitution.
Step 2
Why this answer is correct
The correct answer is B. (y=3). From the second equation (x=10-y); substituting gives (10-y-2y=1), so (y=3). Watch brackets and signs in substitution.
Step 3
Exam Tip
दूसरे से (x=10-y); रखने पर (10-y-2y=1), इसलिए (y=3)। प्रतिस्थापन में कोष्ठक और चिन्ह ध्यान रखें।
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यदि (3x+y=19) और (x+y=9), तो (x+y) का मान क्या है?
If (3x+y=19) and (x+y=9), what is the value of (x+y)?
#linear equations
#direct observation
#easy
#class 10
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A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
The second equation directly states (x+y=9). In exams, read the given equations carefully.
Step 2
Why this answer is correct
The correct answer is B. (9). The second equation directly states (x+y=9). In exams, read the given equations carefully.
Step 3
Exam Tip
दूसरा समीकरण सीधे (x+y=9) बताता है। परीक्षा में दिए हुए समीकरण को भी ध्यान से पढ़ें।
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समीकरणों (3x+y=19) और (x+y=9) को हल करने पर (x) और (y) क्या मिलते हैं?
On solving (3x+y=19) and (x+y=9), what values of (x) and (y) are obtained?
#linear equations
#elimination
#solution pair
#easy
#class 10
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A (x=5,\ y=4)
B (x=4,\ y=5)
C (x=6,\ y=3)
D (x=3,\ y=6)
Explanation opens after your attempt
Correct Answer
A. (x=5,\ y=4)
Step 1
Concept
Subtracting the second equation from the first gives (2x=10), so (x=5) and (y=4). Subtraction is correct to remove equal (y) terms.
Step 2
Why this answer is correct
The correct answer is A. (x=5,\ y=4). Subtracting the second equation from the first gives (2x=10), so (x=5) and (y=4). Subtraction is correct to remove equal (y) terms.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2x=10), इसलिए (x=5) और (y=4)। समान (y) हटाने के लिए घटाना सही है।
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यदि (y=2x-1) और (x+y=8), तो (y) का मान क्या होगा?
If (y=2x-1) and (x+y=8), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
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A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Substitution gives (x+2x-1=8), so (x=3) and (y=5). Find (x) first, then use the expression for (y).
Step 2
Why this answer is correct
The correct answer is C. (y=5). Substitution gives (x+2x-1=8), so (x=3) and (y=5). Find (x) first, then use the expression for (y).
Step 3
Exam Tip
रखने पर (x+2x-1=8), इसलिए (x=3) और (y=5)। पहले (x) निकालें फिर (y) के सूत्र में रखें।
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समीकरणों (5x+5y=25) और (x-y=1) का हल क्या है?
What is the solution of (5x+5y=25) and (x-y=1)?
#linear equations
#elimination
#simplification
#easy
#class 10
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A (x=1,\ y=4)
B (x=2,\ y=3)
C (x=3,\ y=2)
D (x=4,\ y=1)
Explanation opens after your attempt
Correct Answer
C. (x=3,\ y=2)
Step 1
Concept
The first equation is (x+y=5); adding it with (x-y=1) gives (2x=6). Reduce large coefficients first.
Step 2
Why this answer is correct
The correct answer is C. (x=3,\ y=2). The first equation is (x+y=5); adding it with (x-y=1) gives (2x=6). Reduce large coefficients first.
Step 3
Exam Tip
पहला समीकरण (x+y=5) है; इसे (x-y=1) से जोड़ने पर (2x=6)। बड़े गुणांक पहले छोटा करें।
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यदि (2x+4y=18) और (x+2y=9), तो इन दोनों समीकरणों के बारे में सही कथन क्या है?
If (2x+4y=18) and (x+2y=9), which statement is correct about these two equations?
#linear equations
#dependent equations
#easy
#class 10
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A दोनों अलग-अलग हल देती हैं / They give different solutions
B पहला समीकरण दूसरे का (2) गुना है / The first equation is (2) times the second
C इनमें कोई चर नहीं है / They have no variable
D दोनों में केवल (x) है / They contain only (x)
Explanation opens after your attempt
Correct Answer
B. पहला समीकरण दूसरे का (2) गुना है / The first equation is (2) times the second
Step 1
Concept
The first equation is (2(x+2y)=18), so it is (2) times the second. Recognizing proportional equations is also important.
Step 2
Why this answer is correct
The correct answer is B. पहला समीकरण दूसरे का (2) गुना है / The first equation is (2) times the second. The first equation is (2(x+2y)=18), so it is (2) times the second. Recognizing proportional equations is also important.
Step 3
Exam Tip
पहला समीकरण (2(x+2y)=18) है, इसलिए यह दूसरे का (2) गुना है। समानुपाती समीकरणों को पहचानना भी जरूरी है।
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समीकरणों (x+2y=14) और (x=4) में (y) कितना है?
In the equations (x+2y=14) and (x=4), what is (y)?
#linear equations
#substitution
#easy value
#easy
#class 10
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A (y=4)
B (y=5)
C (y=6)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
Putting (x=4) gives (4+2y=14), so (y=5). When one variable is given, substitute immediately.
Step 2
Why this answer is correct
The correct answer is B. (y=5). Putting (x=4) gives (4+2y=14), so (y=5). When one variable is given, substitute immediately.
Step 3
Exam Tip
(x=4) रखने पर (4+2y=14), इसलिए (y=5)। जब एक चर दिया हो तो प्रतिस्थापन तुरंत करें।
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यदि (2x-y=8) और (x=5), तो (y) का मान क्या है?
If (2x-y=8) and (x=5), what is the value of (y)?
#linear equations
#substitution
#negative variable
#easy
#class 10
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A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=5) gives (10-y=8), so (y=2). Change the sign correctly when moving a negative variable.
Step 2
Why this answer is correct
The correct answer is B. (y=2). Putting (x=5) gives (10-y=8), so (y=2). Change the sign correctly when moving a negative variable.
Step 3
Exam Tip
(x=5) रखने पर (10-y=8), इसलिए (y=2)। ऋण चर को दूसरी तरफ ले जाते समय चिन्ह बदलें।
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समीकरणों (2x+3y=17) और (2x+y=9) से (y) का मान ज्ञात कीजिए।
Find the value of (y) from (2x+3y=17) and (2x+y=9).
#linear equations
#elimination
#value of y
#easy
#class 10
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A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2y=8), so (y=4). Eliminate the equal (2x) terms.
Step 2
Why this answer is correct
The correct answer is C. (y=4). Subtracting the second equation from the first gives (2y=8), so (y=4). Eliminate the equal (2x) terms.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2y=8), इसलिए (y=4)। समान (2x) पदों को विलोपित करें।
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यदि (x-y=5) और (y=2), तो (x) का मान क्या होगा?
If (x-y=5) and (y=2), what will be the value of (x)?
#linear equations
#substitution
#value of x
#easy
#class 10
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A (x=5)
B (x=6)
C (x=7)
D (x=8)
Explanation opens after your attempt
Step 1
Concept
Putting (y=2) gives (x-2=5), so (x=7). Substitute the given value in the original equation.
Step 2
Why this answer is correct
The correct answer is C. (x=7). Putting (y=2) gives (x-2=5), so (x=7). Substitute the given value in the original equation.
Step 3
Exam Tip
(y=2) रखने पर (x-2=5), इसलिए (x=7)। दिए हुए मान को मूल समीकरण में रखें।
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समीकरणों (x+y=15) और (y=6) से (x) कितना होगा?
From (x+y=15) and (y=6), what is (x)?
#linear equations
#substitution
#direct value
#easy
#class 10
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A (x=7)
B (x=8)
C (x=9)
D (x=10)
Explanation opens after your attempt
Step 1
Concept
Putting (y=6) gives (x+6=15), so (x=9). Check the final answer even in simple equations.
Step 2
Why this answer is correct
The correct answer is C. (x=9). Putting (y=6) gives (x+6=15), so (x=9). Check the final answer even in simple equations.
Step 3
Exam Tip
(y=6) रखने पर (x+6=15), इसलिए (x=9)। सरल समीकरणों में भी अंतिम उत्तर जांचें।
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यदि (3x-y=12) और (x+y=8), तो (x) का मान क्या है?
If (3x-y=12) and (x+y=8), what is the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
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A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (4x=20), so (x=5). When (y) terms are opposite, addition is the fastest method.
Step 2
Why this answer is correct
The correct answer is C. (x=5). Adding both equations gives (4x=20), so (x=5). When (y) terms are opposite, addition is the fastest method.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (4x=20), इसलिए (x=5)। विपरीत (y) होने पर जोड़ना सबसे तेज तरीका है।
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समीकरणों (x=10-2y) और (x+y=7) में (y) का मान क्या होगा?
In (x=10-2y) and (x+y=7), what will be the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
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A (y=1)
B (y=2)
C (y=3)
D (y=4)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=10-2y) gives (10-y=7), so (y=3). Combine like variable terms correctly.
Step 2
Why this answer is correct
The correct answer is C. (y=3). Substituting (x=10-2y) gives (10-y=7), so (y=3). Combine like variable terms correctly.
Step 3
Exam Tip
(x=10-2y) रखने पर (10-y=7), इसलिए (y=3)। समान चर वाले पदों को सही जोड़ें।
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यदि (4x-y=13) और (x-y=1), तो (x) कितना है?
If (4x-y=13) and (x-y=1), what is (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
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A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3x=12), so (x=4). Equal (-y) terms cancel by subtraction.
Step 2
Why this answer is correct
The correct answer is C. (x=4). Subtracting the second equation from the first gives (3x=12), so (x=4). Equal (-y) terms cancel by subtraction.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3x=12), इसलिए (x=4)। समान (-y) पद घटाने पर कट जाते हैं।
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समीकरणों (2x+y=6) और (y=2x) का हल कौन-सा है?
Which is the solution of (2x+y=6) and (y=2x)?
#linear equations
#substitution
#careful checking
#easy
#class 10
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A (x=1,\ y=2)
B (x=2,\ y=1)
C (x=3,\ y=0)
D (x=0,\ y=3)
Explanation opens after your attempt
Correct Answer
A. (x=1,\ y=2)
Step 1
Concept
Substituting (y=2x) gives (2x+2x=6), so \(x=\frac{3}{2}\); hence none of the listed pairs would be correct.
Step 2
Why this answer is correct
The correct answer is A. (x=1,\ y=2). Substituting (y=2x) gives (2x+2x=6), so \(x=\frac{3}{2}\); hence none of the listed pairs would be correct.
Step 3
Exam Tip
(y=2x) रखने पर (4x=6)? नहीं, सही सरल रूप (2x+2x=6) से \(x=\frac{3}{2}\) आता है, इसलिए दिए विकल्पों में कोई नहीं होता।
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समीकरणों (3x+2y=22) और (x=4) में (y) का मान क्या है?
In the equations (3x+2y=22) and (x=4), what is the value of (y)?
#linear equations
#substitution
#value of y
#easy
#class 10
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A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=4) gives (12+2y=22), so (y=5). Substitute the given value directly and simplify.
Step 2
Why this answer is correct
The correct answer is C. (y=5). Putting (x=4) gives (12+2y=22), so (y=5). Substitute the given value directly and simplify.
Step 3
Exam Tip
(x=4) रखने पर (12+2y=22), इसलिए (y=5)। दिए हुए मान को सीधे रखकर समीकरण सरल करें।
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यदि (y=x-2) और (2x+y=13), तो सही हल कौन-सा है?
If (y=x-2) and (2x+y=13), which is the correct solution?
#linear equations
#substitution
#solution pair
#easy
#class 10
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A (x=5,\ y=3)
B (x=4,\ y=5)
C (x=3,\ y=5)
D (x=6,\ y=2)
Explanation opens after your attempt
Correct Answer
A. (x=5,\ y=3)
Step 1
Concept
Substituting (y=x-2) gives (3x-2=13), so (x=5) and (y=3). Using the isolated variable makes solving easier.
Step 2
Why this answer is correct
The correct answer is A. (x=5,\ y=3). Substituting (y=x-2) gives (3x-2=13), so (x=5) and (y=3). Using the isolated variable makes solving easier.
Step 3
Exam Tip
(y=x-2) रखने पर (3x-2=13), इसलिए (x=5) और (y=3)। अलग किए हुए चर का उपयोग करना आसान रहता है।
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समीकरणों (4x+y=21) और (2x+y=11) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (4x+y=21) and (2x+y=11).
#linear equations
#elimination
#value of x
#easy
#class 10
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A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2x=10), so (x=5). Remove equal (y) terms by subtraction.
Step 2
Why this answer is correct
The correct answer is D. (x=5). Subtracting the second equation from the first gives (2x=10), so (x=5). Remove equal (y) terms by subtraction.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2x=10), इसलिए (x=5)। समान (y) पदों को घटाकर हटाएं।
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यदि (x+3y=16) और (x-y=4), तो (x) और (y) के मान क्या हैं?
If (x+3y=16) and (x-y=4), what are the values of (x) and (y)?
#linear equations
#substitution
#solution pair
#easy
#class 10
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A (x=6,\ y=4)
B (x=7,\ y=3)
C (x=8,\ y=2)
D (x=5,\ y=5)
Explanation opens after your attempt
Correct Answer
B. (x=7,\ y=3)
Step 1
Concept
From the second equation (x=y+4); substituting gives (4y+4=16), so (y=3) and (x=7). Choose the simpler equation for substitution.
Step 2
Why this answer is correct
The correct answer is B. (x=7,\ y=3). From the second equation (x=y+4); substituting gives (4y+4=16), so (y=3) and (x=7). Choose the simpler equation for substitution.
Step 3
Exam Tip
दूसरे समीकरण से (x=y+4); रखने पर (4y+4=16), इसलिए (y=3) और (x=7)। प्रतिस्थापन में सरल समीकरण चुनें।
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समीकरणों (5x+y=26) और (x+y=10) को हल करने पर (y) कितना होगा?
On solving (5x+y=26) and (x+y=10), what is (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
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A (y=4)
B (y=5)
C (y=6)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (4x=16), so (x=4) and (y=6). After finding one variable, put it in the smaller equation.
Step 2
Why this answer is correct
The correct answer is C. (y=6). Subtracting the second equation from the first gives (4x=16), so (x=4) and (y=6). After finding one variable, put it in the smaller equation.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (4x=16), इसलिए (x=4) और (y=6)। एक चर मिलने के बाद उसे छोटे समीकरण में रखें।
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यदि (2x-3y=1) और (x=5), तो (y) का मान क्या है?
If (2x-3y=1) and (x=5), what is the value of (y)?
#linear equations
#substitution
#negative term
#easy
#class 10
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A (y=3)
B (y=4)
C (y=5)
D (y=6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=5) gives (10-3y=1), so (y=3). Watch the signs while solving a negative term.
Step 2
Why this answer is correct
The correct answer is A. (y=3). Putting (x=5) gives (10-3y=1), so (y=3). Watch the signs while solving a negative term.
Step 3
Exam Tip
(x=5) रखने पर (10-3y=1), इसलिए (y=3)। ऋण पद को हल करते समय चिन्हों का ध्यान रखें।
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समीकरणों (x=2y+1) और (x+y=13) का हल क्या है?
What is the solution of (x=2y+1) and (x+y=13)?
#linear equations
#substitution
#solution pair
#easy
#class 10
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A (x=7,\ y=6)
B (x=8,\ y=5)
C (x=9,\ y=4)
D (x=10,\ y=3)
Explanation opens after your attempt
Correct Answer
C. (x=9,\ y=4)
Step 1
Concept
Substituting (x=2y+1) gives (3y+1=13), so (y=4) and (x=9). Combine like terms after substitution.
Step 2
Why this answer is correct
The correct answer is C. (x=9,\ y=4). Substituting (x=2y+1) gives (3y+1=13), so (y=4) and (x=9). Combine like terms after substitution.
Step 3
Exam Tip
(x=2y+1) रखने पर (3y+1=13), इसलिए (y=4) और (x=9)। प्रतिस्थापन के बाद समान पद जोड़ें।
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यदि (3x+4y=25) और (3x+y=13), तो (y) कितना है?
If (3x+4y=25) and (3x+y=13), what is (y)?
#linear equations
#elimination
#value of y
#easy
#class 10
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A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (3y=12), so (y=4). Subtraction is correct to remove the equal (3x).
Step 2
Why this answer is correct
The correct answer is C. (y=4). Subtracting the second equation from the first gives (3y=12), so (y=4). Subtraction is correct to remove the equal (3x).
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (3y=12), इसलिए (y=4)। समान (3x) हटाने के लिए घटाना सही है।
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समीकरणों (x+2y=17) और (y=6) से (x) का मान ज्ञात कीजिए।
Find the value of (x) from (x+2y=17) and (y=6).
#linear equations
#substitution
#value of x
#easy
#class 10
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A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Putting (y=6) gives (x+12=17), so (x=5). The given value quickly gives the other variable.
Step 2
Why this answer is correct
The correct answer is C. (x=5). Putting (y=6) gives (x+12=17), so (x=5). The given value quickly gives the other variable.
Step 3
Exam Tip
(y=6) रखने पर (x+12=17), इसलिए (x=5)। सीधे दिए गए मान से दूसरा चर जल्दी मिलता है।
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यदि (6x+2y=28) और (3x+y=14), तो सही कथन कौन-सा है?
If (6x+2y=28) and (3x+y=14), which statement is correct?
#linear equations
#equivalent equations
#easy
#class 10
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A पहला समीकरण दूसरे का (2) गुना है / The first equation is (2) times the second
B दोनों समीकरण हमेशा अलग हल देंगे / Both equations will always give different solutions
C इनमें केवल (y) है / They contain only (y)
D इनमें कोई स्थिरांक नहीं है / They have no constant
Explanation opens after your attempt
Correct Answer
A. पहला समीकरण दूसरे का (2) गुना है / The first equation is (2) times the second
Step 1
Concept
Multiplying (3x+y=14) by (2) gives (6x+2y=28). Recognize equivalent equations formed by multiplication.
Step 2
Why this answer is correct
The correct answer is A. पहला समीकरण दूसरे का (2) गुना है / The first equation is (2) times the second. Multiplying (3x+y=14) by (2) gives (6x+2y=28). Recognize equivalent equations formed by multiplication.
Step 3
Exam Tip
(3x+y=14) को (2) से गुणा करने पर (6x+2y=28) मिलता है। गुणन से बने समान समीकरणों को पहचानें।
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समीकरणों (2x+y=12) और (x+2y=12) का हल क्या है?
What is the solution of (2x+y=12) and (x+2y=12)?
#linear equations
#elimination
#solution pair
#easy
#class 10
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A (x=3,\ y=6)
B (x=4,\ y=4)
C (x=6,\ y=3)
D (x=5,\ y=5)
Explanation opens after your attempt
Correct Answer
B. (x=4,\ y=4)
Step 1
Concept
Subtracting the equations gives (x-y=0), so (x=y); substituting gives (3x=12). When equality is found, put it into the original equation.
Step 2
Why this answer is correct
The correct answer is B. (x=4,\ y=4). Subtracting the equations gives (x-y=0), so (x=y); substituting gives (3x=12). When equality is found, put it into the original equation.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (x-y=0), इसलिए (x=y); रखने पर (3x=12)। समानता मिलने पर उसे तुरंत मूल समीकरण में रखें।
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